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Express each radical in simplest form, rationalize denominators, and perform the indicated operations. $$\sqrt[6]{\sqrt{2}}-\sqrt[12]{2^{13}}$$

Short Answer

Expert verified
The simplified expression is \(-2^{1/12}\).

Step by step solution

01

Simplify the first radical

The expression \( \sqrt[6]{\sqrt{2}} \) can be rewritten using fractional exponents. Recall that \( \sqrt[n]{a} = a^{1/n} \). Therefore, \( \sqrt{2} = 2^{1/2} \). Applying this, we have \( \sqrt[6]{2^{1/2}} = (2^{1/2})^{1/6} = 2^{1/12} \).
02

Simplify the second radical

Now, consider \( \sqrt[12]{2^{13}} \). This can also be expressed using fractional exponents. Rewrite it as \( (2^{13})^{1/12} = 2^{13/12} \).
03

Express both terms with common denominators

The goal is to perform the operation between the two terms. We have \( 2^{1/12} \) and \( 2^{13/12} \). Since these are like terms in terms of base, they can be directly subtracted. Both have the base 2, so the expressions can be combined: \( 2^{1/12} - 2^{13/12} = 2^{1/12} - 2^{13/12} \).
04

Perform the subtraction

Since \( 2^{1/12} \) and \( 2^{13/12} \) are coefficients of the same base, factor out the \( 2^{1/12} \). The expression becomes \( 2^{1/12}(1 - 2^{12/12}) = 2^{1/12}(1 - 2) \). Simplifying further, \( 1 - 2 = -1 \), so we have \( 2^{1/12} \times (-1) = -2^{1/12} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rationalizing Denominators
Rationalizing the denominator is an important concept in algebra that involves transforming expressions to eliminate any radicals (like square roots) from the denominator. This process can make equations easier to handle and understand, especially when it comes to simplification or further algebraic manipulations. Particularly, this is often done by multiplying the numerator and the denominator of a fraction by an appropriate expression that will eliminate the radical.

Let's consider a fraction like \( \frac{a}{\sqrt{b}} \). To rationalize the denominator, you would multiply both the numerator and the denominator by \( \sqrt{b} \), resulting in \( \frac{a\times \sqrt{b}}{b} \). Here's a step-by-step way of thinking about it:
  • Identify the radical in the denominator.
  • Multiply both the numerator and the denominator by whatever it takes to make the denominator a perfect square (or cube, etc.).
  • Simplify the result.
Using this technique ensures that equations are more manageable and often simplifies solving complex calculations. Rationalizing denominators is a fundamental technique you'll frequently encounter, and mastering it aids in understanding more advanced algebra topics.
Fractional Exponents
Fractional exponents are an alternative way to express roots, and they can simplify many mathematical expressions. They follow a straightforward rule wherein the power represents the numerator of the fraction and the root is the denominator. For example, the expression \( a^{1/n} \) is equivalent to the \( n \)-th root of \( a \), \( \sqrt[n]{a} \).

In practice, if you encounter an expression like \( \sqrt[m]{x} \), you can rewrite it as \( x^{1/m} \). This conversion can make calculations more visually manageable and help when simplifying expressions. Here’s how you handle them practically:
  • Convert all roots into fractional exponents.
  • Apply the laws of exponents to simplify the expression. For instance, \( x^{a/b} \times x^{c/d} = x^{(ad+bc)/bd} \).
  • Simplify each fraction as much as possible.
When we express radicals using fractional exponents, we enable ourselves to leverage rules of exponents for further simplifying expressions or solving equations.
Like Terms in Algebra
In algebra, combining like terms is a fundamental skill that simplifies expressions and equations. Like terms are terms that contain the same variables raised to the same power. This concept is crucial for performing operations such as addition and subtraction.

When working with expressions like \( 2^x - 3^x \), you may notice that the terms cannot be combined directly because they have different bases. However, in expressions having a common base, such as \( 2^{1/12} \) and \( 2^{13/12} \), you can combine them similarly to how you handle coefficients in simple algebra (using their exponents).
  • Ensure the terms have the same base and exponents that can be directly compared or combined.
  • Employ operations (like subtraction) on the coefficients if you are able to factor out a common base.
  • Simplify the expression further by performing arithmetic operations on the coefficients.
Understanding how to identify and combine like terms streamlines solving equations and working through algebraic expressions, avoiding unnecessary complexity.

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Most popular questions from this chapter

$$\text {Solve the given problems.}$$ Rationalize the denominator of \(\frac{1}{\sqrt[3]{x^{2}}+\sqrt[3]{x}+1}\) by using the $$\text { equation } a^{3}-b^{3}=(a-b)\left(a^{2}+a b+b^{2}\right)$$

Solve the given problems. In optics, the combined focal length \(F\) of two lenses is given by \(F=\left[f_{1}^{-1}+f_{2}^{-1}+d\left(f_{1} f_{2}\right)^{-1}\right]^{-1},\) where \(f_{1}\) and \(f_{2}\) are the focal lengths of the lenses and \(d\) is the distance between them. Simplify the right side of this equation.

$$\text {Solve the given problems.}$$ The resonant frequency \(\omega\) of a capacitance \(C\) in parallel with a resistance \(R\) and inductance \(L\) (see Fig. 11.9 ) is $$\omega=\frac{1}{\sqrt{L C}} \sqrt{1-\frac{R^{2} C}{L}}$$ Combine terms under the radical, rationalize the denominator, and simplify.

Perform the indicated operations. The electric current \(i\) (in \(A\) ) in a circuit with a battery of voltage \(E\) a resistance \(R\), and an inductance \(L,\) is \(i=\frac{E}{R}\left(1-e^{-R \nu L}\right)\) where \(t\) is the time after the circuit is closed. See Fig. \(11.4 .\) Find \(i\) for \(E=6.20 \mathrm{V}, R=1.20 \Omega, L=3.24 \mathrm{H},\) and \(t=0.00100 \mathrm{s}\) (The number \(e\) is irrational and can be found from the calculator.)

Perform the indicated operations. A factor used in measuring the loudness sensed by the human ear is \(\left(I / I_{0}\right)^{0.3},\) where \(I\) is the intensity of the sound and \(I_{0}\) is a reference intensity. Evaluate this factor for \(I=3.2 \times 10^{-6} \mathrm{W} / \mathrm{m}^{2}\) (ordinary conversation) and \(I_{0}=10^{-12} \mathrm{W} / \mathrm{m}^{2}\)

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