Chapter 1: Problem 22
Each of the given formulas arises in the technical or scientific area of study shown. Solve for the indicated letter. \(f=\frac{F}{d-F},\) for \(d \quad\) (photography)
Short Answer
Expert verified
The solution is \( d = \frac{F + fF}{f} \).
Step by step solution
01
Understand the Formula
The formula given is \( f = \frac{F}{d-F} \), and you need to solve for \( d \). It arises from photography in relation to focus and distance.
02
Cross Multiply
To eliminate the fraction, multiply both sides by \( d - F \). This gives: \( f(d - F) = F \).
03
Expand the Equation
Distribute \( f \) on the left side to get: \( fd - fF = F \).
04
Isolate Terms with d
Add \( fF \) to both sides to isolate the term with \( d \): \( fd = F + fF \).
05
Solve for d
Divide both sides by \( f \) to solve for \( d \): \( d = \frac{F + fF}{f} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Cross Multiplication
Cross multiplication is a useful method for solving equations that involve fractions. It allows us to eliminate the fractional form and transform the equation into a simpler, more straightforward one, where multiplication takes the central stage. In equations like \( f = \frac{F}{d-F} \), cross multiplication works by multiplying each side of the equation by the denominator of the fraction. This step is essential in clearing the fraction from the equation and setting up a scenario where terms can be reorganized efficiently.
- Start with the given equation: \( f = \frac{F}{d-F} \).
- To clear the fraction, think of the equation as a balance scale that you can adjust evenly. Multiply both sides by \( d - F \), resulting in: \( f(d - F) = F \).
Isolation of Variables
When working with algebraic equations, isolating variables is a strategy to solve for unknowns. This involves rearranging the equation so the unknown variable stands alone on one side of the equation. Here, we need to solve for \( d \) in the equation \( fd - fF = F \).
- Begin by gathering all terms involving \( d \) to one side of the equation. In this case, it's already isolated: \( fd \).
- Focus on expressions not involving your variable of interest. Add \( fF \) to both sides of the equation: \( fd = F + fF \).
- This rearrangement clears the path for you to solve for \( d \) by performing a single division operation in the next step.
Fractional Equations
Fractional equations like \( f = \frac{F}{d-F} \) integrate fractions directly into the equation itself, requiring specific handling steps to solve. They often arise in situations like science and engineering, where ratios and proportions are commonplace.
- The primary goal is to eliminate fractions early in the solution process, typically achieved through cross multiplication.
- Once the equation has been transformed into a format without fractions (e.g., \( fd - fF = F \)), focus shifts to traditional algebraic methods for solving equations.
- Simplifying and reducing terms paves the way for isolating and then solving for the variable of interest, ensuring no fractional residue remains to complicate interpretation.