Chapter 7: Problem 9
Sketch the graph of each parabola by using the vertex, the \(y\) -intercept, and the \(x\) -intercepts. Check the graph using \(a\) calculator. \(y=x^{2}-4\)
Short Answer
Expert verified
The vertex is at (0, -4), y-intercept at (0, -4), and x-intercepts at (2, 0) and (-2, 0).
Step by step solution
01
Identify the Vertex
The equation of a parabola in the form \(y = ax^2 + bx + c\) has a vertex at \((h, k)\), where \(h = -\frac{b}{2a}\). In our equation \(y = x^2 - 4\), \(a = 1\), \(b = 0\), and \(c = -4\). Thus, \(h = -\frac{0}{2 \cdot 1} = 0\). Since there is no linear term, the vertex is at \((0, -4)\).
02
Find the y-Intercept
The \(y\)-intercept is found by setting \(x = 0\) in the equation \(y = x^2 - 4\). Substituting \(x = 0\) gives \(y = 0^2 - 4 = -4\). Thus, the \(y\)-intercept is at \( (0, -4) \).
03
Determine the x-Intercepts
To find the \(x\)-intercepts, set \(y = 0\) in the equation \(y = x^2 - 4\). This gives the equation \(x^2 - 4 = 0\). Factor this equation as \((x - 2)(x + 2) = 0\). Therefore, the solutions \(x = 2\) and \(x = -2\) are the \(x\)-intercepts, meaning the points \((2, 0)\) and \((-2, 0)\).
04
Sketch the Parabola
Plot the vertex \((0, -4)\), the \(y\)-intercept \((0, -4)\), and the two \(x\)-intercepts \((2, 0)\) and \((-2, 0)\) on the graph. Draw a symmetrical parabola opening upwards, passing through the intercepts and vertex.
05
Verify with a Calculator
Using a graphing calculator, input the function \(y = x^2 - 4\) to graph it and confirm that it matches the sketched parabola. Verify the vertices and intercepts visually on the calculator display.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex
The vertex of a parabola provides valuable information about the graph's turning point. In the standard quadratic equation form, \(y = ax^2 + bx + c\), the vertex can be found at the coordinates \((h, k)\). To determine \(h\), use the formula \(h = -\frac{b}{2a}\). In the given equation \(y = x^2 - 4\), comparing it with the standard form tells us that \(a = 1\), \(b = 0\), and \(c = -4\). Because \(b\) is zero, \(h\) simplifies to \(h = 0\) after calculating \(-\frac{0}{2 \cdot 1}\). The \(k\) value is directly the \(c\) term, resulting in a vertex at the point \((0, -4)\). The vertex being \((0, -4)\) means it's also the lowest point on the parabola because the parabola opens upwards (as \(a > 0\)). This critical point dictates much of the graph's shape and is a starting point for graphing the parabola successfully.
x-intercepts
Finding the x-intercepts is an essential part of graphing a parabola. These points are where the graph of the parabola crosses the x-axis and therefore occur where \(y = 0\). To find the x-intercepts of the quadratic equation \(y = x^2 - 4\), set the equation equal to zero: \(x^2 - 4 = 0\). This can be rewritten by factoring it as \((x - 2)(x + 2) = 0\) .
Setting each factor equal to zero provides two solutions:
Setting each factor equal to zero provides two solutions:
- \(x - 2 = 0\) gives \(x = 2\)
- \(x + 2 = 0\) gives \(x = -2\)
y-intercept
The y-intercept is the point where the parabola touches the y-axis, occurring when \(x = 0\). For the equation \(y = x^2 - 4\), substituting \(x = 0\) gives the calculation: \(y = 0^2 - 4 = -4\)This results in the y-intercept located at the point \((0, -4)\). Interestingly, this point is exactly where the vertex is located, revealing symmetry about the y-axis of this particular parabola. Graphically, the y-intercept helps anchor the parabola on the graph and contributes to understanding how the parabola is positioned in relation to other plotted points.
graphing calculator
Using a graphing calculator can greatly help visualize the function \(y = x^2 - 4\). This tool allows for precise graph plotting and verification of calculated points, ensuring an accurate representation of the parabola.To use a graphing calculator effectively,
- Input the quadratic equation into the function plotter to generate the graph.
- Locate the vertex, x-intercepts, and y-intercept visually on the display, confirming their positions match predicted values.
- Utilize the zoom and trace features to closely inspect portions of the graph or to measure distances.