Chapter 7: Problem 5
Sketch the graph of each parabola by using only the vertex and the \(y\) -intercept. Check the graph using a calculator. \(y=-3 x^{2}+10 x-4\)
Short Answer
Expert verified
Vertex is \(\left(\frac{5}{3}, \frac{25}{9}\right)\), \(y\)-intercept is \((0, -4)\); the parabola opens downward.
Step by step solution
01
Identify the coefficients
The given quadratic equation is of the form \(y = ax^2 + bx + c\). For \(y = -3x^2 + 10x - 4\), identify \(a = -3\), \(b = 10\), and \(c = -4\).
02
Find the vertex
The vertex of a parabola \(y = ax^2 + bx + c\) is given by the formula \(x = -\frac{b}{2a}\). Substituting in the values, we have \(x = -\frac{10}{2(-3)} = \frac{10}{6} = \frac{5}{3}\). Substitute \(x = \frac{5}{3}\) back into the equation to find \(y\): \(y = -3\left(\frac{5}{3}\right)^2 + 10\left(\frac{5}{3}\right) - 4\). Simplifying gives \(y = \frac{-75}{9} + \frac{50}{3} - 4\), which further simplifies to \(y = \frac{25}{9}\). Thus, the vertex is \(\left(\frac{5}{3}, \frac{25}{9}\right)\).
03
Find the y-intercept
The \(y\)-intercept occurs where \(x = 0\). Substituting \(x = 0\) into the equation \(y = -3x^2 + 10x - 4\), we find \(y = -4\). Therefore, the \(y\)-intercept is at \((0, -4)\).
04
Sketch the graph
Plot the vertex \(\left(\frac{5}{3}, \frac{25}{9}\right)\) and the \(y\)-intercept \((0, -4)\) on the coordinate plane. Since \(a = -3\) (which is negative), the parabola opens downward.
05
Verify with a calculator
Use a graphing calculator to input the equation \(y = -3x^2 + 10x - 4\). Check that the vertex \(\left(\frac{5}{3}, \frac{25}{9}\right)\) and \(y\)-intercept \((0, -4)\) match the graph.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vertex of a Parabola
The vertex of a parabola is a pivotal point that helps us understand and sketch the graph more precisely. For any quadratic function expressed in the form \(y = ax^2 + bx + c\), the vertex provides the exact coordinates where the parabola either reaches a maximum or a minimum point—depending on its orientation. To find the vertex, we need the formula \(x = -\frac{b}{2a}\). Here, \(b\) and \(a\) are simply coefficients in the quadratic equation. Given the equation \(y = -3x^2 + 10x - 4\), plug in the coefficients \(b = 10\) and \(a = -3\) into the formula:
- \(x = -\frac{10}{2(-3)} = \frac{5}{3}\)
- \[y = -3\left(\frac{5}{3}\right)^2 + 10\left(\frac{5}{3}\right) - 4\]
- Simplifying yields \(y = \frac{25}{9}\)
Y-intercept Calculation
Understanding the \(y\)-intercept is crucial in graphing functions, as it reveals where the graph crosses the \(y\)-axis. The calculation of the \(y\)-intercept is straightforward. It's the point where the value of \(x\) is zero in the equation. By setting \(x = 0\) in the quadratic equation \(y = -3x^2 + 10x - 4\), we can solve for \(y\):
- Substituting gives \(y = -4\)
Downward-opening Parabola
A parabola’s orientation can be either upward or downward, determined by the coefficient \(a\) in the quadratic equation. When \(a\) is negative, as in \(-3\) in the equation \(y = -3x^2 + 10x - 4\), the parabola will open downwards. This means the vertex signifies a maximum rather than a minimum.This downwards-opening feature impacts the graph’s shape significantly:
- The arms of the parabola diverge downwards.
- The vertex serves as the highest point on the graph.
- The parabola forms a symmetrical shape around the vertical line drawn through the vertex.