Chapter 7: Problem 19
Use a calculator to solve the given equations. If there are no real roots, state this as the answer. \(-3 x^{2}+11 x-5=0\)
Short Answer
Expert verified
The equation has two real roots: approximately 0.53 and 3.14.
Step by step solution
01
Identify the Equation Type
The given equation \[-3x^2 + 11x - 5 = 0\]is a quadratic equation of the form \(ax^2 + bx + c = 0\). Here, \(a = -3\), \(b = 11\), and \(c = -5\).
02
Determine Discriminant
The discriminant of a quadratic equation is given by \[D = b^2 - 4ac\]Substitute the given values:\[D = 11^2 - 4(-3)(-5) = 121 - 60 = 61\]
03
Check Discriminant Sign
Since the discriminant \(D = 61\) is greater than zero, the quadratic equation has two distinct real roots.
04
Use the Quadratic Formula
The quadratic formula to find the roots is \[x = \frac{-b \pm \sqrt{D}}{2a}\]
05
Substitute Values into Formula
Substitute \(a = -3\), \(b = 11\), and \(D = 61\) into the formula:\[x = \frac{-11 \pm \sqrt{61}}{2(-3)}\]
06
Calculate Each Root
Now, calculate each root:1. For the root \(x_1\):\[x_1 = \frac{-11 + \sqrt{61}}{-6}\]Using a calculator, calculate \(\sqrt{61} \approx 7.81\):\[x_1 = \frac{-11 + 7.81}{-6} = \frac{-3.19}{-6} \approx 0.53\]2. For the root \(x_2\):\[x_2 = \frac{-11 - \sqrt{61}}{-6}\]\[x_2 = \frac{-11 - 7.81}{-6} = \frac{-18.81}{-6} \approx 3.14\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Discriminant
The discriminant is a key component in solving quadratic equations. It is represented by the symbol \(D\) and is calculated using the formula:
- \(D = b^2 - 4ac\)
- \(a\) is the coefficient of \(x^2\)
- \(b\) is the coefficient of \(x\)
- \(c\) is the constant term
- If \(D > 0\), the equation has two distinct real roots.
- If \(D = 0\), the equation has exactly one real root, often called a repeated or double root.
- If \(D < 0\), the equation has no real roots, but two complex roots.
Real Roots
Real roots are the solutions to a quadratic equation that can be expressed as real numbers. When we talk about real roots, we are referring to the actual intersection points of the quadratic curve \(y = ax^2 + bx + c\) with the x-axis on a graph.
These points are where the value of \(y\), or the output of the quadratic equation, is zero. Real roots can be one of the following:
These points are where the value of \(y\), or the output of the quadratic equation, is zero. Real roots can be one of the following:
- Two Distinct Real Roots: This happens when the discriminant \(D > 0\). The graph touches the x-axis at two points.
- One Real Root: Occurs when \(D = 0\). The graph is tangent to the x-axis, touching it at just one point.
- No Real Roots: If \(D < 0\), the graph does not touch the x-axis at all, indicating the presence of complex roots instead of real ones.
Quadratic Formula
The quadratic formula is a universal method used to find the roots of any quadratic equation \(ax^2 + bx + c = 0\). This is how the formula appears:
The quadratic formula incorporates the discriminant \(b^2 - 4ac\) under the square root, which is pivotal in determining the nature of the roots:
By calculating these steps, the resulting roots are approximately \(0.53\) and \(3.14\), providing precise solutions to the equation.
- \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)
The quadratic formula incorporates the discriminant \(b^2 - 4ac\) under the square root, which is pivotal in determining the nature of the roots:
- If \(D > 0\), the two calculations with \(\pm\) give two different real roots.
- If \(D = 0\), both calculations will result in the same root, reflecting the double root.
- If \(D < 0\), the square root of a negative number results in complex numbers.
By calculating these steps, the resulting roots are approximately \(0.53\) and \(3.14\), providing precise solutions to the equation.