Chapter 6: Problem 70
Factor the expressions completely. It is necessary to set up the proper expression. Each expression comes from the technical area indicated. A pipe of outside diameter \(d\) is inserted into a pipe of inside radius \(r .\) Express in factored form the cross-sectional area within the larger pipe that is outside the smaller pipe.
Short Answer
Step by step solution
- Understanding the Objective
- Inside Pipe Area Calculation
- Outside Larger Pipe Area Calculation
- Calculate the Area Outside the Smaller Pipe
- Factoring Out the Common Factor
- Difference of Squares and Final Factored Form
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Difference of Squares
For instance, in our exercise, we are given \( \frac{d^2}{4} - r^2 \). This indeed represents a difference of squares. We can observe how it fits the pattern:
- The term \( \left(\frac{d}{2}\right)^2 \) acts as our \( a^2 \).
- The term \( r^2 \) acts as our \( b^2 \).
Area Calculation
Here, we calculate two areas:
- The smaller, inner pipe’s area: \( \pi r^2 \).
- The larger, outer pipe’s area: \( \pi \left( \frac{d}{2} \right)^2 \).
Geometry
- An inner circle of radius \( r \).
- An outer circle encompassing diameter \( d \).
Algebra
- Identify common factors, such as \( \pi \), in the expressions \( \pi \frac{d^2}{4} \) and \( \pi r^2 \).
- Utilize factoring techniques, specifically factoring out common factors and employing difference of squares methods.