Chapter 6: Problem 30
Factor the given expressions completely. $$36 s^{2}-121 t^{4}$$
Short Answer
Expert verified
The expression factors as \((6s - 11t^2)(6s + 11t^2)\).
Step by step solution
01
Recognize the Difference of Squares
The expression given is \( 36s^2 - 121t^4 \). Notice that this is a subtractive form, indicating it could be factored as a difference of squares. The formula for a difference of squares is \( a^2 - b^2 = (a-b)(a+b) \). First, identify \( a^2 \) and \( b^2 \).
02
Identify \( a^2 \) and \( b^2 \)
Recognize \( 36s^2 \) as \( (6s)^2 \) and \( 121t^4 \) as \( (11t^2)^2 \). Here, \( a = 6s \) and \( b = 11t^2 \). Substitute into the difference of squares formula.
03
Apply the Difference of Squares Formula
Using the formula \( a^2 - b^2 = (a - b)(a + b) \), we substitute \( a = 6s \) and \( b = 11t^2 \) to get: \[ (6s - 11t^2)(6s + 11t^2) \].
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Difference of Squares
In algebra, a common technique for factoring expressions is recognizing the 'difference of squares'. This method is particularly useful when you have an expression in the form of \( a^2 - b^2 \). The difference of squares can always be rewritten as \((a-b)(a+b)\). This is because when you multiply \((a-b)\) and \((a+b)\), you get back to \(a^2 - b^2\) due to the middle terms cancelling each other out: \( +ab - ab = 0 \).
To use this formula effectively:
To use this formula effectively:
- First, ensure you are dealing with two perfect squares separated by a subtraction symbol.
- Identify the terms that are squared, which will be your values for \(a\) and \(b\).
- Apply the formula \((a-b)(a+b)\) to factor the expression completely.
Algebraic Expressions
Algebraic expressions are a fundamental part of algebra that consist of numbers, variables, and operations. In the given example, the expression \(36s^2 - 121t^4\) is made up of terms with variables \(s\) and \(t\), and coefficients 36 and -121, respectively.
When you're working with algebraic expressions:
When you're working with algebraic expressions:
- Terms are separated by plus or minus signs, and can contain constants or variables raised to a power.
- Algebraic expressions do not have an equal sign, differentiating them from algebraic equations.
- Simplifying or factoring these expressions helps in solving algebraic problems and understanding their structure more deeply.
Polynomials
Polynomials are a specific type of algebraic expression that consist of coefficients and variables, where the variables are raised to non-negative integer powers. Each individual term in a polynomial is known as a monomial; when there are two terms, it's called a binomial, and three terms form a trinomial.
In terms of the exercise, \(36s^2 - 121t^4\) is a binomial consisting of two terms. Each term in the polynomial is raised to a specific power, \(s^2\) and \(t^4\).
To effectively deal with polynomials:
In terms of the exercise, \(36s^2 - 121t^4\) is a binomial consisting of two terms. Each term in the polynomial is raised to a specific power, \(s^2\) and \(t^4\).
To effectively deal with polynomials:
- Understand the highest power of the variable, which represents the degree of the polynomial.
- Use factoring techniques like the difference of squares, factoring by grouping, or the quadratic formula, among others, depending on the polynomial's structure.