Chapter 5: Problem 40
Set up appropriate systems of equations. All numbers are accurate to at least two significant digits. A certain 18 -hole golf course has par- \(3,\) par- \(4,\) and par- 5 holes, and there are twice as many par-4 holes as par- 5 holes. How many holes of each type are there if a golfer has par on every hole for a score of \(70 ?\)
Short Answer
Step by step solution
Define the Variables
Set Up the Equations
Simplify and Substitute
Solve for One Variable
Solve for z
Solve for y
Solve for x
Verify the Solution
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Par Score Calculation
- Par-3 holes contribute 3 strokes each.
- Par-4 holes contribute 4 strokes each.
- Par-5 holes contribute 5 strokes each.
Variables in Equations
- Let \( x \) be the number of par-3 holes.
- Let \( y \) be the number of par-4 holes.
- Let \( z \) be the number of par-5 holes.
- The total number of holes: \( x + y + z = 18 \)
- The relationship between par-4 and par-5 holes: \( y = 2z \)
- The par score calculation combining all hole types discussed earlier.
Solving Equations Step by Step
First, we use the relationship \( y = 2z \) to substitute for \( y \) in our equations, transforming equation 1 to \( x + 3z = 18 \) and equation 2 to \( 3x + 13z = 70 \).**Step 2: Solve for One Variable**
We subtract the first transformed equation from the second to isolate variables, simplifying it to \( 2x + 10z = 52 \).**Step 3: Isolate \( z \)**
Dividing by 2, we get \( x + 5z = 26 \). Then subtract \( x + 3z = 18 \) from this, leaving us with \( 2z = 8 \), giving \( z = 4 \).**Step 4: Solve for Remaining Variables (\( x \) and \( y \))**
Substitute \( z \) into \( y = 2z \), getting \( y = 8 \). Then substitute \( z = 4 \) into the equation \( x + 3z = 18 \) to find \( x = 6 \).This careful step-by-step process allows us to find the solution: 6 par-3 holes, 8 par-4 holes, and 4 par-5 holes, ensuring that we meet all conditions set by the problem.