Chapter 4: Problem 9
Find values of the trigonometric functions of the angle (in standard position) whose terminal side passes through the given points. For Exercises \(3-14,\) give answers in exact form. For Exercises 15 and \(16,\) the coordinates are approximate. $$(1, \sqrt{15})$$
Short Answer
Expert verified
The trigonometric functions are: \(\sin(\theta) = \frac{\sqrt{15}}{4}\), \(\cos(\theta) = \frac{1}{4}\), \(\tan(\theta) = \sqrt{15}\), \(\csc(\theta) = \frac{4\sqrt{15}}{15}\), \(\sec(\theta) = 4\), \(\cot(\theta) = \frac{\sqrt{15}}{15}\).
Step by step solution
01
Identify the point
The point given is \(1, \sqrt{15}\). This point lies on the terminal side of an angle in standard position, where \ x = 1 \ and \ y = \sqrt{15} \.
02
Calculate the hypotenuse
The hypotenuse \(r\) is calculated using the Pythagorean theorem: \\[ r = \sqrt{x^2 + y^2} = \sqrt{1^2 + (\sqrt{15})^2} = \sqrt{1 + 15} = \sqrt{16} = 4. \]
03
Compute the sine function
The sine of the angle \(\theta\) is given by \(\sin(\theta) = \frac{y}{r}\). Substitute the known values: \\[ \sin(\theta) = \frac{\sqrt{15}}{4}. \]
04
Compute the cosine function
The cosine of the angle is \(\cos(\theta) = \frac{x}{r}\). Substitute the known values: \\[ \cos(\theta) = \frac{1}{4}. \]
05
Compute the tangent function
The tangent of the angle is \(\tan(\theta) = \frac{y}{x}\). Substitute the known values: \\[ \tan(\theta) = \frac{\sqrt{15}}{1} = \sqrt{15}. \]
06
Compute the cosecant function
The cosecant of the angle is the reciprocal of the sine function: \(\csc(\theta) = \frac{r}{y}\). Substitute the known values: \\[ \csc(\theta) = \frac{4}{\sqrt{15}} = \frac{4\sqrt{15}}{15}. \]
07
Compute the secant function
The secant of the angle is the reciprocal of the cosine function: \(\sec(\theta) = \frac{r}{x}\). Substitute the known values: \\[ \sec(\theta) = \frac{4}{1} = 4. \]
08
Compute the cotangent function
The cotangent of the angle is the reciprocal of the tangent function: \(\cot(\theta) = \frac{x}{y}\). Substitute the known values: \\[ \cot(\theta) = \frac{1}{\sqrt{15}} = \frac{\sqrt{15}}{15}. \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Pythagorean Theorem
The Pythagorean theorem is a fundamental concept in trigonometry and geometry. It is crucial when determining the distance of a point from the origin on a coordinate plane. The theorem states that in a right-angled triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the other two sides. This can be expressed with the equation:
- \(a^2 + b^2 = c^2\)
- \(a\) and \(b\) are the lengths of the triangle's legs,
- and \(c\) is the length of the hypotenuse.
- \[r = \sqrt{1^2 + (\sqrt{15})^2} = \sqrt{16} = 4\].
Sine Function
The sine function is a fundamental trigonometric function, representing the ratio of the length of the side opposite to the angle to the hypotenuse in a right triangle. For an angle \(\theta\) in standard position, with a terminal side passing through the point \((1, \sqrt{15})\), the sine can be calculated using the following expression:
- \(\sin(\theta) = \frac{y}{r}\)
- \[\sin(\theta) = \frac{\sqrt{15}}{4}\].
Cosine Function
The cosine function is another key trigonometric function that measures the ratio of the adjacent side to the hypotenuse in a right triangle. When positioning an angle in the standard position, you can compute the cosine using:
- \( \cos(\theta) = \frac{x}{r} \)
- \[ \cos(\theta) = \frac{1}{4} \].
Tangent Function
The tangent function links the sine and cosine functions by expressing their ratio. It is defined as the ratio of the opposite side to the adjacent side in a right triangle. For our angle \(\theta\) in standard position, tangent is computed by:
- \( \tan(\theta) = \frac{y}{x} \)
- \[ \tan(\theta) = \frac{\sqrt{15}}{1} = \sqrt{15} \].