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Solve the given third- and fourth-order differential equations. $$D^{3} y-6 D^{2} y+11 D y-6 y=0$$

Short Answer

Expert verified
The general solution is \( y(t) = C_1 e^{t} + C_2 e^{2t} + C_3 e^{3t} \).

Step by step solution

01

Rewrite the Differential Equation

The given differential equation is \( D^{3} y - 6 D^{2} y + 11 D y - 6 y = 0 \). We can write this using the differential operator \( D \) as \( (D^3 - 6D^2 + 11D - 6)y = 0 \). This means we are seeking the roots of the characteristic equation.
02

Find the Characteristic Equation

The characteristic equation associated with the differential operator is \( D^3 - 6D^2 + 11D - 6 = 0 \). This polynomial needs to be solved to find the roots, which will give us the general solution of the differential equation.
03

Factor the Characteristic Polynomial

The polynomial \( D^3 - 6D^2 + 11D - 6 \) can be factored as \( (D - 1)(D - 2)(D - 3) = 0 \). These factors are derived by trial, synthetic division, or by inspection, verifying that each linear factor produces a zero of the polynomial.
04

Solve for Roots

Setting each factor equal to zero, we find the roots: \( D - 1 = 0 \Rightarrow D = 1 \), \( D - 2 = 0 \Rightarrow D = 2 \), and \( D - 3 = 0 \Rightarrow D = 3 \). These are distinct real roots of the characteristic equation.
05

Write the General Solution

Since the roots are distinct and real, the general solution of the differential equation is given by \( y(t) = C_1 e^{t} + C_2 e^{2t} + C_3 e^{3t} \), where \( C_1, C_2, \) and \( C_3 \) are constants determined by initial or boundary conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Characteristic Equation
When solving differential equations, the characteristic equation is a crucial element in finding solutions. In the case of homogeneous linear differential equations with constant coefficients, the characteristic equation is formed by replacing the differential operator with a variable, often denoted as\( D \) or\( r \). For example, consider the differential equation \( D^{3} y - 6 D^{2} y + 11 D y - 6 y = 0 \). To form the characteristic equation, replace\( D \) with a dummy variable, say\( r \), resulting in \( r^{3} - 6 r^{2} + 11 r - 6 = 0 \). Solving this equation allows us to find the values of\( r \), which provide crucial insight into the behavior of the solution to the differential equation.
It's essentially a step of translating the differential equation into an algebraic form that can be more readily solved. This forms the basis for determining the nature of the solution, which can be real, complex, or repeated.
Factorization
Factorization is the process of breaking down a complex expression into simpler components or factors which, when multiplied together, give the original expression. For polynomial equations like the characteristic equation \( r^{3} - 6r^{2} + 11r - 6 = 0 \), factorization involves finding linear factors such as \((D - 1)(D - 2)(D - 3) = 0\).
This is particularly helpful because breaking the equation into linear factors simplifies the process of identifying the roots. You can achieve this through methods such as:
  • Trial and Error: Testing likely candidates to see if they make the polynomial equal to zero.
  • Synthetic Division: A shortcut method for dividing a polynomial by a linear binomial.
  • Inspection: Observing patterns or using known algebraic identities for simplification.
Factorization simplifies the equation and helps identify roots efficiently, making it easier to write down the general solution of the differential equation.
General Solution
Once the roots of the characteristic equation are determined, constructing the general solution follows. For distinct real roots obtained from \( (D - 1)(D - 2)(D - 3) = 0 \), the roots were found to be 1, 2, and 3.
The general solution is a linear combination of exponential functions corresponding to these roots. For example, the solution can be expressed as \( y(t) = C_1 e^{t} + C_2 e^{2t} + C_3 e^{3t} \). Here:
  • \(C_1, C_2, C_3\): Free constants determined by initial or boundary conditions.
  • \(e^{t}\): Exponential terms associated with each distinct root.
By combining these exponential terms, the general solution captures all possible solutions to the differential equation. Adjusting the constants according to specific conditions allows one to refine the solution to meet particular cases or scenarios.
Distinct Real Roots
In the context of differential equations, 'distinct real roots' refer to unique real numbers obtained as solutions of the characteristic equation. For example, when solving \(D^{3} y - 6 D^{2} y + 11 D y - 6 y = 0\), through factorization, we found that the roots \(1, 2, \) and \(3\) are distinct and real.
These roots play an essential role in determining the type of solution the differential equation will have:
  • Each distinct root leads to a unique term in the general solution, typically represented in exponential form.
  • The uniqueness of roots ensures there are no repeated contributions in the solution, thus simplifying the structure.
Understanding whether roots are distinct, repeated, or complex is key to constructing the correct solution form for the differential equation. Distinct real roots often lead to simpler exponential solutions that can be easily interpreted and applied.

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Most popular questions from this chapter

Solve the given problems by solving the appropriate differential equation. Assume that the rate at which highway construction increases is directly proportional to the total mileage \(M\) of all highways already completed at time \(t\) (in years). Solve for \(M\) as a function of \(t\) if \(M=5250 \mathrm{mi}\) for a certain county when \(t=0\) and \(M=5460 \mathrm{mi}\) for \(t=2.00\) years.

Solve the given problems by solving the appropriate differential equation. According to Newton's law of cooling, the rate at which a body cools is proportional to the difference in temperature between it and the surrounding medium. Assuming Newton's law holds, how long will it take a cup of hot water, initially at \(200^{\circ} \mathrm{F},\) to cool to \(100^{\circ} \mathrm{F}\) if the room temperature is \(80.0^{\circ} \mathrm{F},\) if it cools to \(140^{\circ} \mathrm{F}\) in 5.0 min?

Solve the given third- and fourth-order differential equations. $$D^{4} y-D^{3} y-9 D^{2} y+9 D y=0$$

Solve the given differential equations by Laplace transforms. The function is subject to the given conditions. A spring is stretched \(1 \mathrm{m}\) by a \(20-\mathrm{N}\) weight. The spring is stretched 0.5 m below the equilibrium position with the weight attached and then released. If it is in a medium that resists the motion with a force equal to \(12 v\), where \(v\) is the velocity, find the displacement y of the weight as a function of the time.

Solve the given problems by solving the appropriate differential equation. For a DNA sample in a liquid containing a solute of constant concentration \(c_{0}\), the rate at which the concentration \(c(t)\) of solute in the sample changes is proportional to \(c_{0}-c(t) .\) Find \(c(t)\) if \(c(0)=0\)

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