Chapter 30: Problem 46
Solve the given problems as indicated. Use geometric series to show that \(\sum_{n=0}^{\infty}(-1)^{n} x^{n}=\frac{1}{1+x}\) for \(|x|<1\).
Short Answer
Expert verified
The series converges to \(\frac{1}{1+x}\) for \(|x| < 1\).
Step by step solution
01
Recall the Geometric Series Formula
The formula for the sum of an infinite geometric series is \( S = \frac{a}{1-r} \) where \( a \) is the first term of the series and \( r \) is the common ratio. This formula applies when \(|r| < 1\).
02
Identify the Components
Identify \(a\) and \(r\) in the series \(\sum_{n=0}^{\infty}(-1)^{n}x^{n}\). Here, \(a = 1\) (the first term when \(n=0\), as \((-1)^0x^0 = 1\)), and \(r = -x\).
03
Apply the Formula
Substitute \(a = 1\) and \(r = -x\) into the geometric series formula. Thus, we have:\[ S = \frac{1}{1 - (-x)} \]This simplifies to:\[ S = \frac{1}{1 + x} \]
04
Verify the Condition
The series converges when \(|x| < 1\), which is the condition given for our series. Thus, the formula holds under the given condition.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sum of Infinite Series
In a geometric series, the terms progress by multiplying a fixed value known as the common ratio. When dealing with infinite series, we don't just sum a set number of terms. Instead, we consider an endless number of terms, adding them together theoretically to determine whether a meaningful sum, called "S," can be found.
The mathematical representation of an infinite geometric series is given by:
For example, in our given problem, we have the infinite series summed as \( \sum_{n=0}^{\infty}(-1)^{n}x^{n} \). The result is elegantly represented by \( \frac{1}{1+x} \), showcasing the power of understanding how infinite geometric series work.
The mathematical representation of an infinite geometric series is given by:
- First term: \( a \)
- Common ratio: \( r \) (a constant value multiplied to get each subsequent term)
- \( S = \frac{a}{1-r} \)
For example, in our given problem, we have the infinite series summed as \( \sum_{n=0}^{\infty}(-1)^{n}x^{n} \). The result is elegantly represented by \( \frac{1}{1+x} \), showcasing the power of understanding how infinite geometric series work.
Common Ratio
The common ratio is a key piece in understanding geometric series. It's the factor you multiply by to get from one term to the next in the series.
For the series \( \sum_{n=0}^{\infty}(-1)^{n}x^{n} \), identifying the common ratio \( r \) is vital. In this case, the common ratio \( r \) is \(-x\) as seen from growing the terms:
For the series \( \sum_{n=0}^{\infty}(-1)^{n}x^{n} \), identifying the common ratio \( r \) is vital. In this case, the common ratio \( r \) is \(-x\) as seen from growing the terms:
- First term (n=0): \((−1)^{0}x^{0} = 1\)
- Second term (n=1): \((-1)^{1}x^{1} = -x\)
Convergence Condition
For an infinite series to converge—that is, to have a finite sum—the terms need to become smaller and smaller as we progress. The convergence condition for a geometric series is that the absolute value of the common ratio \( r \) must be less than 1.
If \(|r| < 1\), the terms approach zero, allowing the infinite sum to settle at a finite number. Conversely, if \(|r| \geq 1\), the series will not converge, meaning the terms stay the same or increase, and the sum will not stabilize.
In our problem, since our common ratio is \(-x\), the condition \(|-x| < 1\) simplifies to \(|x| < 1\). This condition must be met for the series to converge and for our solution \( \frac{1}{1+x} \) to be valid. Understanding and checking these conditions is crucial for solving similar problems in geometric series.
If \(|r| < 1\), the terms approach zero, allowing the infinite sum to settle at a finite number. Conversely, if \(|r| \geq 1\), the series will not converge, meaning the terms stay the same or increase, and the sum will not stabilize.
In our problem, since our common ratio is \(-x\), the condition \(|-x| < 1\) simplifies to \(|x| < 1\). This condition must be met for the series to converge and for our solution \( \frac{1}{1+x} \) to be valid. Understanding and checking these conditions is crucial for solving similar problems in geometric series.
Mathematical Proofs
In mathematics, proofs are used to demonstrate that a particular statement or theorem holds true universally. When it comes to geometric series, proofs can establish the validity of formulas like the infinite sum equation \( S = \frac{a}{1-r} \) and test their limits.
Proving the convergence and resulting sum of an infinite geometric series typically involves:
Proving the convergence and resulting sum of an infinite geometric series typically involves:
- Establishing the value of \( a \) and \( r \) based on the series definition.
- Demonstrating that \(|r| < 1\) to show convergence.
- Applying the sum formula appropriately with substitution.