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Find the nth term of the given infinite series for which \(n=1,2,3, \ldots\) $$\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\cdots$$

Short Answer

Expert verified
The nth term of the series is \( \frac{1}{2^n} \).

Step by step solution

01

Identify the Pattern

First, observe the sequence: \( \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \frac{1}{16} + \cdots \). Notice that each term in the series is a fraction that is halved from the previous term.
02

General Term Analysis

The first term is \( \frac{1}{2} \), the second term is \( \frac{1}{4} \), the third term is \( \frac{1}{8} \), and so on. In general, the \( n \)-th term of the sequence can be expressed as \( \frac{1}{2^n} \). This matches the pattern where each term is the previous term divided by 2, or equivalently the denominator is a power of 2.
03

Confirm the Formula

To verify, substitute \( n = 1, 2, 3, \ldots \) into \( a_n = \frac{1}{2^n} \):\- For \( n = 1 \), \( a_1 = \frac{1}{2} \)\- For \( n = 2 \), \( a_2 = \frac{1}{4} \)\- For \( n = 3 \), \( a_3 = \frac{1}{8} \)\This confirms the correctness of the formula.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Infinite Series
An infinite series is a sum of an unlimited number of terms. Imagine adding numbers together forever without stopping. That's what an infinite series does! There's no end to the terms you're adding, hence the name "infinite". In math, we often represent this type of series by using a series notation like \( \sum_{n=1}^{\infty} a_n \), where each \( a_n \) is a term in the series.

Infinite series can have amazing properties. Some converge to a limit—meaning as you add more terms, the sum approaches a specific number. Others diverge, meaning they grow indefinitely or oscillate without settling on a value. A series given by \( \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \cdots \) is a geometric series, and it converges to 1.

Understanding infinite series is crucial in various fields such as calculus and physics. They help in modeling and solving real-world problems, like calculating the sum of an infinite number of decreasing payments in finance.
Nth Term
Finding the nth term of a sequence means determining the formula that tells you what any term in the sequence will be if you pick a particular number \( n \). For our series \( \frac{1}{2} + \frac{1}{4} + \frac{1}{8} + \cdots \), the nth term \( a_n \) is \( \frac{1}{2^n} \).

Let's understand why this works. The first term, \( n=1 \), is \( \frac{1}{2} \), the second term \( n=2 \) is \( \frac{1}{4} \), and the third term \( n=3 \) is \( \frac{1}{8} \). If you follow this pattern, you'll see that the denominator of each term is a power of 2: 2, 4, 8, and so on, or in mathematical terms, \( 2^n \).

This approach of finding the nth term is essential when you're dealing with sequences, as it simplifies the process of finding any term without having to list all the ones that come before it.
Sequence Pattern
A sequence pattern is the rule or formula that defines how a sequence progresses. In the sequence \( \frac{1}{2}, \frac{1}{4}, \frac{1}{8} \), and so on, the pattern is clear: each term is half of the previous one.

Identifying a sequence pattern helps in finding expressions like the nth term. In this case, by recognizing that each subsequent term is produced by multiplying the previous term by \( \frac{1}{2} \), we generate a simple formula for consecutive terms. Patterns in sequences often involve arithmetic operations such as addition, subtraction, multiplication, or they might involve powers, as with squared or cubed numbers.

Recognizing these patterns simplifies the task of predicting future terms and plays a role in many mathematical disciplines, helping solve broader problems involving sequences and series.
Mathematical Sequence
A mathematical sequence is an ordered list of numbers following a certain rule. In the sequence \( \frac{1}{2} \), \( \frac{1}{4} \), \( \frac{1}{8} \), and continuing, each number is called a "term". These terms form the elements of the sequence.

Sequences are everywhere in mathematics and beyond. They can be finite (having a limited number of terms) or infinite, just like the one in our exercise. There are many types of sequences ranging from arithmetic (where each term is obtained by adding a constant to the previous term) to geometric (where each term is obtained by multiplying the previous term by a constant, as seen here).

Understanding sequences involves learning the rules by which they operate and seeing how these rules apply to produce the next term. This knowledge is crucial for tackling problems in areas like calculus, number theory, and algorithm design.

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Most popular questions from this chapter

Solve the given problems as indicated. A sequence is defined recursively (see Exercise 47) by \(x_{1}=\frac{N}{2}\) \(x_{n+1}=\frac{1}{2}\left(x_{n}+\frac{N}{x_{n}}\right) .\) With \(N=10,\) find \(x_{6}\) and compare the value with \(\sqrt{10}\). It can be seen that \(\sqrt{N}\) can be approximated using this recursion sequence.

Solve the given problems by using series expansions. The period \(T\) of a pendulum of length \(L\) is given by $$ T=2 \pi \sqrt{\frac{L}{g}}\left(1+\frac{1}{4} \sin ^{2} \frac{\theta}{2}+\frac{9}{64} \sin ^{4} \frac{\theta}{2}+\cdots\right) $$ where \(g\) is the acceleration due to gravity and \(\theta\) is the maximum angular displacement. If \(L=1.000 \mathrm{m}\) and \(g=9.800 \mathrm{m} / \mathrm{s}^{2},\) calculate \(T\) for \(\theta=10.0^{\circ}\) (a) if only one term (the 1 ) of the series is used and (b) if two terms of the indicated series are used. In the second term, substitute one term of the series for \(\sin ^{2}(\theta / 2)\)

Solve the given problems. Expand \(f(x)=x^{2}\) in a half-range sine series for \(0 \leq x<2\)

Find the values of \(x\) for which the given series converge. $$\sum_{n=2}^{\infty} \frac{x^{n}}{5^{n}}$$

Use a calculator to display (a) the function in the endicated exercise of this set and (b) the first two terms of the Taylor series found for that exercise in the same display. Describe how elosely the graph in part (b) fits the graph in part (a). Use the given values of \(x\) for \(X\) min and \(X\) max. Exercise \(17 \text { (tan } x), x=0\) to \(x=1.5\)

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