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Find all of the second derivatives of the given functions. $$z=3 x^{2} y-y^{3}+2 x y$$

Short Answer

Expert verified
The second derivatives are \( \frac{\partial^2 z}{\partial x^2} = 6y \), \( \frac{\partial^2 z}{\partial y^2} = -6y \), and \( \frac{\partial^2 z}{\partial x \partial y} = 6x + 2 \).

Step by step solution

01

Identify the Function

The function given is \( z = 3x^2y - y^3 + 2xy \). Our goal is to find all of the second derivatives of this function, which include \( \frac{\partial^2 z}{\partial x^2} \), \( \frac{\partial^2 z}{\partial y^2} \), and \( \frac{\partial^2 z}{\partial x \partial y} \).
02

Find \( \frac{\partial z}{\partial x} \)

Differentiate \( z = 3x^2y - y^3 + 2xy \) with respect to \( x \), treating \( y \) as a constant: \[ \frac{\partial z}{\partial x} = 6xy + 2y \].
03

Find \( \frac{\partial^2 z}{\partial x^2} \)

Differentiate \( \frac{\partial z}{\partial x} = 6xy + 2y \) with respect to \( x \): \[ \frac{\partial^2 z}{\partial x^2} = 6y \].
04

Find \( \frac{\partial z}{\partial y} \)

Differentiate \( z = 3x^2y - y^3 + 2xy \) with respect to \( y \), treating \( x \) as a constant: \[ \frac{\partial z}{\partial y} = 3x^2 - 3y^2 + 2x \].
05

Find \( \frac{\partial^2 z}{\partial y^2} \)

Differentiate \( \frac{\partial z}{\partial y} = 3x^2 - 3y^2 + 2x \) with respect to \( y \): \[ \frac{\partial^2 z}{\partial y^2} = -6y \].
06

Find \( \frac{\partial^2 z}{\partial x \partial y} \)

Differentiate \( \frac{\partial z}{\partial x} = 6xy + 2y \) with respect to \( y \): \[ \frac{\partial^2 z}{\partial x \partial y} = 6x + 2 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Differentiation
Partial differentiation is like zooming in on one variable at a time within a multivariable function. Imagine you have a function that depends on different inputs, let's say variables like \( x \) and \( y \). When you want to understand how the function changes as one specific variable changes, while keeping the others constant, you use partial differentiation.

This method is particularly useful when working with functions like \( z = 3x^2y - y^3 + 2xy \). Here, when we find \( \frac{\partial z}{\partial x} \), we are seeing how \( z \) changes with respect to \( x \) while treating \( y \) as a constant. Similarly, finding \( \frac{\partial z}{\partial y} \) helps us see the change in \( z \) regarding \( y \) with \( x \) as a constant.

  • \( \frac{\partial z}{\partial x} = 6xy + 2y \): Focuses on changes as \( x \) varies.
  • \( \frac{\partial z}{\partial y} = 3x^2 - 3y^2 + 2x \): Examines changes as \( y \) varies.
Understanding these helps lay the groundwork for exploring more complex relationships in the realm of calculus.
Multivariable Calculus
Multivariable calculus opens the door to understanding functions that depend on more than one variable. It's the branch of mathematics that is concerned with the study of calculus applied to functions with multiple inputs. For instance, in the given function \( z = 3x^2y - y^3 + 2xy \), both \( x \) and \( y \) play crucial roles.

When dealing with multivariable functions, we often explore first and second derivatives to understand their behavior.
In this case, the second derivatives \( \frac{\partial^2 z}{\partial x^2} \), \( \frac{\partial^2 z}{\partial y^2} \), and \( \frac{\partial^2 z}{\partial x \partial y} \) provide insights into how the rate of change itself changes with respect to one or more of the variables.

  • \( \frac{\partial^2 z}{\partial x^2} = 6y \): Examines the curvature in the direction of \( x \).
  • \( \frac{\partial^2 z}{\partial y^2} = -6y \): Focuses on the curvature in the direction of \( y \).
  • \( \frac{\partial^2 z}{\partial x \partial y} = 6x + 2 \): Looks at the interaction effects between \( x \) and \( y \).
These second derivatives are essential not only for theoretical calculus but also for practical applications in fields like physics, engineering, and economics.
Mathematical Functions
Mathematical functions serve as the workhorses in calculus, forming the foundation on which various calculus concepts are built. Functions describe relationships between variables. In multivariable calculus, functions can have multiple independent variables, each contributing uniquely to the output.

The given function \( z = 3x^2y - y^3 + 2xy \) is a typical example of a function with two variables. Each term in the function presents a unique interaction between \( x \) and \( y \).

  • The term \( 3x^2y \) indicates the dependency of \( z \) on both \( x \) and \( y \) in a multiplicative relationship.
  • \( -y^3 \) shows the influence of \( y \) cubed, independently reducing the value of \( z \).
  • Lastly, \( 2xy \) adds another layer of interaction between \( x \) and \( y \).
By analyzing such functions through differentiation, we can predict how changes in the variables affect the outcome — a crucial skill in mathematical modeling and solving real-world problems.

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