Chapter 28: Problem 11
Integrate each of the given functions. $$\int_{1}^{4} \frac{e^{\sqrt{x}}}{2 \sqrt{x}} d x$$
Short Answer
Expert verified
The integral is \( e^2 - e \).
Step by step solution
01
Identify the Inner Function for Substitution
The given integral is \( \int_{1}^{4} \frac{e^{\sqrt{x}}}{2 \sqrt{x}} \, dx \). Notice that the exponent in the numerator involves \( \sqrt{x} \), which suggests using substitution. Let \( u = \sqrt{x} \), hence \( x = u^2 \) and differentiate both sides to get \( dx = 2u \, du \).
02
Adjust the Integral Using Substitution
Using the substitution \( dx = 2u \, du \), the integral becomes \( \int_{u=1}^{2} \frac{e^u}{2u} \times 2u \, du \). The \( 2u \) in the numerator and \( 2u \) in the denominator will cancel out, simplifying the integral to \( \int_{1}^{2} e^u \, du \).
03
Integrate with Respect to \( u \)
The integral now is \( \int_{1}^{2} e^u \, du \). The antiderivative of \( e^u \) is itself, \( e^u \). Evaluate this from \( u = 1 \) to \( u = 2 \).
04
Evaluate the Definite Integral
Substitute the upper and lower limits of \( u \) into the antiderivative: \( e^2 - e^1 \), which simplifies to \( e^2 - e \).
05
Finalize the Calculation
The integral evaluates to \( e^2 - e \). Converting this back from \( u \) to \( x \) confirms the change was correctly managed, resulting in the solution.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Definite Integrals
Definite integrals are a fundamental aspect of integral calculus. They are used to find the net area between a function's graph and the x-axis within specific limits. The notation \( \int_{a}^{b} f(x) \, dx \) represents the definite integral of \( f(x) \) from \( a \) to \( b \), where \( a \) and \( b \) are the lower and upper limits, respectively.
When you evaluate a definite integral, the result is a number that represents the size of this area, taking into account parts above and below the x-axis. This can mean portions below the x-axis subtract from the total area, indicating the 'net' value. This concept applies directly to our exercise, where we integrate \( \int_{1}^{4} \frac{e^{\sqrt{x}}}{2 \sqrt{x}} \, dx \). By calculating this integral over the interval from 1 to 4, we find the accumulated value of the function, considering both top and bottom sections.
To solve a definite integral:
When you evaluate a definite integral, the result is a number that represents the size of this area, taking into account parts above and below the x-axis. This can mean portions below the x-axis subtract from the total area, indicating the 'net' value. This concept applies directly to our exercise, where we integrate \( \int_{1}^{4} \frac{e^{\sqrt{x}}}{2 \sqrt{x}} \, dx \). By calculating this integral over the interval from 1 to 4, we find the accumulated value of the function, considering both top and bottom sections.
To solve a definite integral:
- Find the antiderivative of the function, unrelated to the limits initially.
- Evaluate this antiderivative at the upper limit.
- Evaluate it again at the lower limit and subtract this from the result at the upper limit.
Substitution Method
The substitution method, also known as \( u \)-substitution, is a technique for simplifying integrals. It's especially useful when dealing with composite functions, where one function is nested inside another. Think of it as a way to "undo" the chain rule of differentiation.
To use substitution:
To use substitution:
- Identify the inner function, typically seen within another function or operation.
- Set this inner function equal to \( u \). For example, in \( \int \frac{e^{\sqrt{x}}}{2 \sqrt{x}} \, dx \), letting \( u = \sqrt{x} \) simplifies things.
- Differentiate the new \( u \) to express \( dx \) in terms of \( du \). In our case, \( dx = 2u \, du \).
- Rewrite the integral in terms of \( u \) and simplify before integrating.
Antiderivatives
Antiderivatives are the heart of integrating functions. They refer to the reverse process of differentiation. In simple terms, if differentiating a function \( F(x) \) gives us \( f(x) \), then \( F(x) \) is the antiderivative of \( f(x) \). For definite integrals, finding the antiderivative is a key step before evaluating at the limits.
In our covered example, after using substitution, the integral simplifies to \( \int_{1}^{2} e^u \, du \). The antiderivative of \( e^u \) is simply \( e^u \) itself. Recognizing antiderivatives quickly is crucial for solving integrals efficiently.
When evaluating, you substitute back the variable values and compute the difference, as seen when calculating \( e^2 - e^1 \), ultimately resulting in \( e^2 - e \). Integrating through antiderivatives, especially after substitution, simplifies complex integrals in calculus considerably.
In our covered example, after using substitution, the integral simplifies to \( \int_{1}^{2} e^u \, du \). The antiderivative of \( e^u \) is simply \( e^u \) itself. Recognizing antiderivatives quickly is crucial for solving integrals efficiently.
When evaluating, you substitute back the variable values and compute the difference, as seen when calculating \( e^2 - e^1 \), ultimately resulting in \( e^2 - e \). Integrating through antiderivatives, especially after substitution, simplifies complex integrals in calculus considerably.