Chapter 27: Problem 30
Find the derivatives of the given functions. $$y=\sqrt{x+\ln 3+\ln x}$$
Short Answer
Expert verified
The derivative is \( \frac{dy}{dx} = \frac{1}{2\sqrt{x + \ln 3 + \ln x}} \cdot \left(\frac{x+1}{x}\right) \).
Step by step solution
01
Identify the Function Type
The given function is \[ y = \sqrt{x + \ln 3 + \ln x} \] This function is a composition of functions, involving a square root and logarithms.
02
Apply the Chain Rule
The square root can be rewritten as a power function: \[ y = (x + \ln 3 + \ln x)^{1/2} \] We will apply the chain rule here, which states that if you have a function \( y = (u(x))^{n} \), its derivative is \( \frac{dy}{dx} = n\cdot (u(x))^{n-1} \cdot \frac{du}{dx} \). Here, \( u(x) = x + \ln 3 + \ln x \) and \( n = 1/2 \).
03
Differentiate the Outer Function
Differentiate the outer function using the chain rule:\[ \frac{d}{dx} = \frac{1}{2}(x + \ln 3 + \ln x)^{-1/2} \cdot \frac{d}{dx}(x + \ln 3 + \ln x) \] Here, \( (x + \ln 3 + \ln x)^{1/2} \) becomes \( \frac{1}{2}(x + \ln 3 + \ln x)^{-1/2} \).
04
Differentiate the Inner Function
Now differentiate the inner function \( u(x) = x + \ln 3 + \ln x \):1. The derivative of \( x \) is 1.2. The derivative of \( \ln 3 \) is 0 (as it is a constant).3. The derivative of \( \ln x \) is \( \frac{1}{x} \).Therefore, \[ \frac{du}{dx} = 1 + \frac{1}{x} \]
05
Combine Results
Substitute \( \frac{du}{dx} \) back into the derivative equation from Step 3:\[ \frac{dy}{dx} = \frac{1}{2}(x + \ln 3 + \ln x)^{-1/2} \cdot \left(1 + \frac{1}{x}\right) \] Simplify this expression:\[ \frac{dy}{dx} = \frac{1}{2\sqrt{x + \ln 3 + \ln x}} \left(1 + \frac{1}{x}\right) \] So the derivative of the given function is:\[ \frac{dy}{dx} = \frac{1}{2\sqrt{x + \ln 3 + \ln x}} \cdot \left(\frac{x+1}{x}\right) \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chain Rule
The chain rule is a fundamental concept in calculus, particularly useful when dealing with the derivative of composite functions. Think of it as a way to "chain" together the derivatives of nested functions. The essence of the chain rule is to help us find the rate of change of a function that is composed of other functions. For a function of the form \( y = (u(x))^n \), the chain rule states that the derivative is:\[ \frac{dy}{dx} = n \cdot (u(x))^{n-1} \cdot \frac{du}{dx} \]
- First, differentiate the outer function: this often involves functions like power, exponential, or trigonometric functions.
- Then, multiply by the derivative of the inner function (\( u(x) \)).
Logarithmic Functions
Logarithmic functions are a unique category of functions involving logarithms, which are the inverse of exponential functions. In simpler terms, while exponential functions involve raising numbers to a power, logarithmic functions work backward and solve for the power. For a logarithmic function with base \( a \), like \( y = \log_a(x) \), the derivative is computed using properties:
- The natural logarithm \( \ln(x) \) is a special logarithmic function with base \( e \), an irrational constant roughly equal to 2.718.
- The derivative of the natural logarithm \( \ln(x) \) is \( \frac{1}{x} \).
Composition of Functions
A composition of functions means that one function is applied within another, creating a nested operation. This concept is at the heart of the described problem. When you look at the function \( y = \sqrt{x + \ln 3 + \ln x} \), this is a composition because it's more than a straightforward function - it combines multiple operations.
- The outermost function in this case is the square root, which we expressed as a power function: \( (x + \ln 3 + \ln x)^{1/2} \).
- The inner function is \( x + \ln 3 + \ln x \), combining both linear and logarithmic elements.