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Find antiderivatives of the given functions. $$f(x)=x^{2}-4+x^{-2}$$

Short Answer

Expert verified
\( F(x) = \frac{x^3}{3} - 4x - x^{-1} + C \) is an antiderivative of \( f(x) = x^2 - 4 + x^{-2} \).

Step by step solution

01

Understand the Function

The function given is a combination of three power functions: \( f(x) = x^2 - 4 + x^{-2} \). We need to find antiderivatives for each term separately and then combine these results.
02

Use Antiderivative Rules

Recall the power rule for antiderivatives: \( \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \) for \( n eq -1 \). We'll apply this rule to each term.
03

Find Antiderivative of Each Term

For \( x^2 \), the antiderivative is \( \frac{x^{2+1}}{2+1} = \frac{x^3}{3} \).For \( -4 \), the antiderivative is \( -4x \) (since the antiderivative of a constant \( c \) is \( cx + C \)).For \( x^{-2} \), the antiderivative is \( \frac{x^{-2+1}}{-2+1} = \frac{x^{-1}}{-1} = -x^{-1} \).
04

Combine the Antiderivatives

Combine the antiderivatives of each term:\( \int f(x) \, dx = \frac{x^3}{3} - 4x - x^{-1} + C \), where \( C \) is the constant of integration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Power Rule for Antiderivatives
The power rule is a fundamental tool for finding antiderivatives in calculus. It allows us to find an antiderivative for any function expressed as a power of x, as long as the power is not -1. Here’s how it works:
  • If you have a function like \( x^n \), the antiderivative can be found using: \[ \int x^n \, dx = \frac{x^{n+1}}{n+1} + C \] where \( C \) is the constant of integration, and \( n \) is any number except -1.
  • This rule simplifies the process of finding antiderivatives by giving us a straightforward formula.
For example, in the function \( x^2 \), \( n = 2 \), so using our power rule, we find the antiderivative to be \( \frac{x^{3}}{3} \). Applying a similar technique to \( x^{-2} \), we have \( n = -2 \), so the antiderivative is \( -x^{-1} \).

Remember, this rule does not work when \( n = -1 \), which is a peculiarity that requires a different approach, using the natural logarithm function.
Constant of Integration
Whenever you calculate an antiderivative, it's crucial to include a constant of integration, denoted by \( C \). But why do we need this constant term? Let’s explore:
  • Antiderivatives represent a whole family of functions. The constant \( C \) accounts for all possible vertical shifts of the antiderivative. It indicates that there are infinite solutions differing by this constant value.
  • In the function \( f(x) \), for instance, if we calculate \( \int (f(x)) \), it will add \( C \) to signal that each antiderivative is part of this larger set of solutions.
Therefore, when you find \( \int f(x) \, dx \) as \( \frac{x^{3}}{3} - 4x - x^{-1} + C \), the \( C \) encapsulates the idea that there are many valid antiderivatives for this integral, all differing only by a constant.
Step-by-Step Solution
Approaching calculus problems step-by-step can turn complex tasks into manageable parts. Let’s walk through finding the antiderivative for \( f(x) = x^2 - 4 + x^{-2} \) using this approach:
  • Step 1: Break down the function \( f(x) = x^2 - 4 + x^{-2} \) into its components and focus on each one individually.
  • Step 2: Apply the power rule for each term:
    • For \( x^2 \): \( \int x^2 \, dx = \frac{x^3}{3} \).
    • For the constant \( -4 \): Its antiderivative is \( -4x \) because the antiderivative of a constant \( c \) is \( cx + C \).
    • For \( x^{-2} \): Using the power rule, we find \( \int x^{-2} \, dx = -x^{-1} \).
By systematically applying these steps, you can ensure accuracy and understand each part of the process. Finally, combine these results to get the complete antiderivative: \[ \int f(x) \, dx = \frac{x^3}{3} - 4x - x^{-1} + C \] This organized approach not only aids in understanding but also helps in cementing the problem-solving process.

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