Chapter 24: Problem 32
In Exercises \(21-32,\) sketch the graphs of the given functions by determining the appropriate information and points from the first and second derivatives. Use a calculator to check the graph. In Exercises \(27-32,\) use the function maximum-minimum feature to check the local maximum and minimum points. $$y=x^{4}+32 x+2$$
Short Answer
Step by step solution
Find the First Derivative
Critical Points from the First Derivative
Find the Second Derivative
Analyze the Second Derivative
Sketch the Graph and Verify with a Calculator
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First Derivative
For our function, which is given as \( y = x^4 + 32x + 2 \), we used the power rule to find the first derivative: \( \frac{dy}{dx} = 4x^3 + 32 \).
- Where the derivative is positive, the function is increasing.
- Where the derivative is negative, the function is decreasing.
- A zero derivative indicates a potential maximum, minimum, or saddle point.
Second Derivative
For the function \( y = x^4 + 32x + 2 \), the second derivative is \( \frac{d^2y}{dx^2} = 12x^2 \).
- When the second derivative is positive, the function is concave upwards like a smile, meaning it increases at an increasing rate.
- When the second derivative is negative, the function is concave downwards like a frown.
- If the second derivative equals zero, the function could have an inflection point, which is where the concavity changes.
Critical Points
For our example function, \( 4x^3 + 32 = 0 \) simplifies to \( x^3 = -8 \), resulting in \( x = -2 \) as a critical point. Here, the derivative is zero, suggesting a possible turnaround point or extremum.
Critical points can:
- Indicate high and low spots in the curve, known as local maxima and minima.
- Signal changes in direction, such as moving from increasing to decreasing, and vice versa.
Local Minimum
From our analysis of the function \( y = x^4 + 32x + 2 \), we determined that the critical point \( x = -2 \) is a local minimum.
- The first derivative equals zero at this point, pointing to a potential extremum.
- The second derivative is positive, indicating the function is concave up here, akin to a bowl shape. Thus, \( x = -2 \) is a local minimum.
Function Concavity
Using the second derivative \( \frac{d^2y}{dx^2} = 12x^2 \), we assessed that it is always positive for all real x-values, indicating the function is concave up everywhere.
- When concave up, a function resembles a U-shape, implying that as the x-values increase, the function's rate of increase is itself increasing.
- Understanding concavity assists in better visualizing the graph and anticipating the function's behavior in broader terms.