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$$\text { Solve the problems in related rates.}$$ One statement of Boyle's law is that the pressure of a gas varies inversely as the volume for constant temperature. If a certain gas occupies \(650 \mathrm{cm}^{3}\) when the pressure is \(230 \mathrm{kPa}\) and the volume is increasing at the rate of \(20.0 \mathrm{cm}^{3} / \mathrm{min}\), how fast is the pressure changing when the volume is \(810 \mathrm{cm}^{3} ?\)

Short Answer

Expert verified
The pressure is decreasing at approximately 4.57 kPa/min when the volume is 810 cm³.

Step by step solution

01

Boyle's Law

Boyle's Law states that for a constant temperature, the pressure \( P \) of a gas varies inversely with its volume \( V \). Mathematically, this is expressed as \( P = \frac{k}{V} \), where \( k \) is a constant.
02

Determine the Constant \( k \)

Use the initial condition to find \( k \). Given \( P = 230 \) kPa and \( V = 650 \) cm³, substitute these into the equation \( P = \frac{k}{V} \):\[ 230 = \frac{k}{650} \]Solving for \( k \) gives \( k = 230 \times 650 = 149500 \).
03

Differentiate with Respect to Time

Differentiate the equation \( P = \frac{k}{V} \) with respect to time \( t \).\[ \frac{dP}{dt} = \frac{d}{dt}\left(\frac{149500}{V}\right) \]Using the chain rule, this becomes:\[ \frac{dP}{dt} = -\frac{149500}{V^2} \cdot \frac{dV}{dt} \]
04

Substitute Known Values

We know the volume \( V = 810 \) cm³ and the rate \( \frac{dV}{dt} = 20 \) cm³/min. Substitute these into the differentiated equation:\[ \frac{dP}{dt} = -\frac{149500}{810^2} \times 20 \]Calculating, we find:\[ \frac{dP}{dt} \approx -4.57 \text{ kPa/min} \] (rounded to two decimal places).
05

Interpret the Result

The negative sign indicates that the pressure \( P \) is decreasing at the rate of approximately 4.57 kPa/min.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Boyle's Law
Boyle's Law is a fundamental principle in physics that explains the relationship between the pressure and volume of a gas kept at a constant temperature. According to Boyle's Law, the pressure of a gas varies inversely with its volume. This means as one increases, the other decreases. It is mathematically represented as:\( P = \frac{k}{V} \)where \( P \) stands for pressure, \( V \) for volume, and \( k \) is a constant. This constant represents the state of the system at a given temperature.When studying gas behaviors, Boyle's Law is crucial because it helps us understand how gases will behave under different pressure and volume conditions. For instance, if you compress a gas, its pressure will rise if the temperature remains the same. Similarly, if the volume of the gas expands, the pressure drops. This inverse relationship can be visually understood with the help of a graph, where pressure is on one axis and volume on the other, forming a curve rather than a straight line.Understanding Boyle’s Law is vital for solving problems involving gases, as it lays the groundwork for calculating changes in pressure when the volume changes, provided the temperature remains constant.
Inverse Variation
Inverse variation is an essential mathematical concept often seen in the relationship between different quantities. When one quantity increases, the other quantity decreases, and the product of both quantities remains constant. This is the backbone of Boyle's Law, where pressure varies inversely with volume.In the context of Boyle's Law, the formula \( P = \frac{k}{V} \) showcases this inverse relationship. Here, an increase in volume \( V \) results in a decrease in pressure \( P \), as long as the temperature is constant. Essentially, if you were to multiply pressure and volume together, the product would always equal the constant \( k \).This relationship can be illustrated through another example like speed and travel time for a constant distance. Faster speeds mean shorter travel time, and vice versa, maintaining the distance constant.Inverse variation might seem complex, but when visualized, it becomes clearer. If you plot these variables on a graph, you won't see a straight line, but a hyperbolic curve, emphasizing the inverse nature of their relationship.
Pressure Change
Pressure change is a critical concept in various scientific fields, especially when dealing with gases under different conditions. In problems involving related rates, understanding how fast the pressure is changing with respect to time is crucial.With Boyle's Law in mind, you can predict how the pressure will change as the volume changes over time. For a given gas system at a constant temperature, if the volume changes at a certain rate, you can find out how quickly the pressure is changing.In the given exercise, the pressure change was calculated using:\[ \frac{dP}{dt} = -\frac{k}{V^2} \cdot \frac{dV}{dt} \]This formula tells us how the pressure varies over time as the volume changes. Here, \( \frac{dV}{dt} \) is the rate of change of volume, and \( \frac{dP}{dt} \) is the rate of change of pressure. The negative sign denotes that an increase in volume leads to a decrease in pressure, consistent with inverse variation.Understanding pressure change is vital for predicting gas behavior in practical scenarios. Whether you're calculating airflow in a system or how a sealed gas tank responds to temperature changes, grasping these related rates provides invaluable insight.

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