Chapter 24: Problem 20
Find the indicated velocities and accelerations. An electron moves in an electric field according to the equations \(x=8.0 / \sqrt{1+t^{2}}\) and \(y=8.0 t / \sqrt{1+t^{2}}(x \text { and } y \text { in } \mathrm{Mm} \text { and } t\) in \(s\) ). Find the velocity of the electron when \(t=0.5 \mathrm{s}\)
Short Answer
Step by step solution
Find the Velocity Equation in X-direction
Calculate Velocity in X-direction at t=0.5s
Find the Velocity Equation in Y-direction
Calculate Velocity in Y-direction at t=0.5s
Find the Velocity Vector at t=0.5s
Final Step: Calculate Magnitude of Velocity
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Differentiation
Differentiation is typically done using specific rules to simplify the process and make it more accurate.
Chain Rule
This rule was used to differentiate the equations given in the problem effectively. It allowed us to find the rate of change of the position functions of the electron related to time. For example, the x-position function \( x(t) \) was differentiated by applying the chain rule to produce an accurate formula for the velocity.
Velocity Vector
For our electron, we calculated the velocity vector by finding derivatives of its x and y position functions. At time \( t = 0.5s \), we found the velocity vector to be \( \mathbf{v}(0.5) = (-3.58, 5.36) \text{ Mm/s} \). This vector tells us two things:
- The electron is moving negatively along the x-axis, meaning it could be moving left.
- It moves positively along the y-axis, suggesting upward movement.
Magnitude of Velocity
To find the magnitude, we take the square root of the sum of the squares of the velocity components. For instance, with the components \( -3.58 \text{ Mm/s} \) and \( 5.36 \text{ Mm/s} \), the magnitude of the velocity vector is computed as:
\[ v = \sqrt{(-3.58)^2 + (5.36)^2} \approx 6.45 \text{ Mm/s} \]
This gives a straightforward answer to how fast the electron is moving overall, and it's a key aspect in analyzing movement in physics and engineering.