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Solve the problems in related rates. The magnetic field \(B\) due to a magnet of length \(l\) at a distance \(r\) is given by \(B=\frac{k}{\left[r^{2}+(l / 2)^{2}\right]^{3 / 2}},\) where \(k\) is a constant for a given magnet. Find the expression for the time rate of change of \(B\) in terms of the time rate of change of \(r\).

Short Answer

Expert verified
\(\frac{dB}{dt} = -\frac{3kr \cdot \frac{dr}{dt}}{\left[r^{2}+(l/2)^{2}\right]^{5/2}}\).

Step by step solution

01

Identify Given Variables and Derivatives

We are given the expression for the magnetic field as a function of distance: \[B = \frac{k}{\left[r^{2}+(l/2)^{2}\right]^{3/2}}.\]We need to find \(\frac{dB}{dt}\) in terms of \(\frac{dr}{dt}\). This is a related rates problem, where both \(B\) and \(r\) are functions of time \(t\).
02

Differentiate Implicitly with Respect to Time

We differentiate both sides of the given equation with respect to time \(t\). Applying the chain rule, the derivative of \(B\) with respect to \(t\) is:\[ \frac{d}{dt}\left( B \right) = \frac{dB}{dB} \cdot \frac{dB}{dt}.\]Differentiating the right side of the equation:\[ \frac{d}{dt} \left( \frac{k}{\left[r^{2}+(l/2)^{2}\right]^{3/2}} \right).\]
03

Apply Chain Rule and Simplify

Using the chain rule and quotient rule for derivatives, calculate:\[\frac{dB}{dt} = \frac{d}{dt} \left( \frac{k}{f(r)} \right),\] where \(f(r) = \left[r^{2}+(l/2)^{2}\right]^{3/2} \).The derivative using the chain rule is:\[ -k \cdot \frac{1}{(f(r))^2} \cdot \frac{d}{dt}[f(r)].\]Now, we differentiate \(f(r)\):\[\frac{d}{dt}[f(r)] = \frac{d}{dt}\left[r^{2}+(l/2)^{2}\right]^{3/2} = \frac{3}{2} \times \left[r^{2}+(l/2)^{2}\right]^{1/2} \cdot \frac{d}{dt}[r^{2}].\]
04

Differentiate r-squared and Conclude

Differentiate \(r^2\) with respect to \(t\):\[\frac{d}{dt}[r^2] = 2r \frac{dr}{dt}.\]Substitute this back into the result from Step 3:\[\frac{d}{dt}[f(r)] = \frac{3}{2} \times \left[r^{2}+(l/2)^{2}\right]^{1/2} \cdot 2r \frac{dr}{dt}.\]Simplify:\[\frac{dB}{dt} = -k \cdot \frac{3r \cdot \frac{dr}{dt}}{\left[r^{2}+(l/2)^{2}\right]^{5/2}}.\]
05

Result Interpretation

The final expression for the time rate of change of the magnetic field \( B \) in terms of the time rate of change of the distance \( r \) is:\[\frac{dB}{dt} = -\frac{3kr \cdot \frac{dr}{dt}}{\left[r^{2}+(l/2)^{2}\right]^{5/2}}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Field
The magnetic field is a fundamental concept in physics, representing the magnetic influence of electrical currents and magnetic materials. In this particular exercise, we examine how the magnetic field, denoted as \( B \), changes due to a magnet as its distance \( r \) varies. The initial formula for the magnetic field given in the exercise is:
\[ B = \frac{k}{[r^2 + (l/2)^2]^{3/2}}, \]where:
  • \( B \) is the magnetic field strength,
  • \( k \) is a constant that depends on the specific physical properties of the magnet,
  • \( r \) is the distance from the magnet, and
  • \( l \) is the length of the magnet.
This formula highlights the inverse relationship between the magnetic field strength and the distance \( r \). As \( r \) increases, the denominator of the fraction becomes larger, thus decreasing \( B \). Understanding how the magnetic field behaves with distance is essential for applications in electromagnetism and helps to model real-world magnetic scenarios effectively.
Calculus
Calculus is an essential mathematical tool used to study change and motion, often dealing with derivatives and integrals. In this exercise, we employ calculus, specifically derivatives, to find the rate at which the magnetic field \( B \) changes over time. The expression we aim to find is \( \frac{dB}{dt} \), the rate of change of \( B \) with respect to time \( t \).To tackle the problem, we start by differentiating the given formula for \( B \) with respect to time, using implicit differentiation. The technique involves treating \( B \) and \( r \) as functions of time and allowing us to apply the derivative to both sides of the equation.Implicit differentiation allows us to account for how \( r \) changes over time, leading us to the expression:
\[ \frac{dB}{dt} = -\frac{3kr \cdot \frac{dr}{dt}}{[r^2 + (l/2)^2]^{5/2}}. \]This equation reflects how the change in distance impacts the magnetic field, demonstrating the power of calculus in linking concepts through derivatives.
Chain Rule
The chain rule is a fundamental principle in calculus used to find the derivative of composite functions. It is crucial in solving this related rates problem involving the magnetic field.When the distance \( r \) varies with time \( t \), both \( r \) and \( B \) depend on \( t \), making it necessary to use the chain rule. The chain rule states that if a variable \( z \) is a function of \( y \), which is in turn a function of \( x \), then \( \frac{dz}{dx} = \frac{dz}{dy} \cdot \frac{dy}{dx} \).In this problem, differentiate \( B \) concerning \( r \) first and then multiply this derivative by \( \frac{dr}{dt} \), the derivative of \( r \) concerning \( t \). This application effectively links the rate of change of \( r \) to the rate of change of \( B \), showing:
\[ \frac{dB}{dt} = \frac{dB}{dr} \cdot \frac{dr}{dt}. \]It allows us to solve how \( B \) changes as \( r \) varies with time, an essential step in understanding the behavior of the magnetic field.

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Most popular questions from this chapter

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