/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 In Exercises \(3-26,\) find the ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In Exercises \(3-26,\) find the derivative of each of the functions by using the definition. $$y=\frac{2}{x^{2}}$$

Short Answer

Expert verified
The derivative of \( y = \frac{2}{x^2} \) is \( y' = -\frac{4}{x^3} \).

Step by step solution

01

Understanding the Definition of a Derivative

The derivative of a function \( y = f(x) \) at a point \( x \) is defined as \( f'(x) = \lim_{{h \to 0}} \frac{{f(x+h) - f(x)}}{h} \). We will use this definition to find the derivative of \( y = \frac{2}{x^2} \).
02

Setting Up the Expression for \( y(x+h) \)

Let \( f(x) = \frac{2}{x^2} \). First, find \( f(x+h) \):\[ f(x+h) = \frac{2}{(x+h)^2} \]
03

Substitute into the Derivative Formula

Substitute \( f(x) \) and \( f(x+h) \) into the derivative definition:\[ f'(x) = \lim_{{h \to 0}} \frac{\frac{2}{(x+h)^2} - \frac{2}{x^2}}{h} \]
04

Simplify the Expression

To simplify \( \frac{2}{(x+h)^2} - \frac{2}{x^2} \), use a common denominator:\[ \frac{2x^2 - 2(x+h)^2}{x^2(x+h)^2} \]This equals:\[ \frac{2x^2 - 2(x^2 + 2xh + h^2)}{x^2(x+h)^2} = \frac{2x^2 - 2x^2 - 4xh - 2h^2}{x^2(x+h)^2} = \frac{-4xh - 2h^2}{x^2(x+h)^2} \]
05

Factor and Simplify Further

Factor out \( h \) from the numerator:\[ \frac{-2h(2x + h)}{x^2(x+h)^2} \]This simplifies into the limit:\[ \lim_{{h \to 0}} \frac{-2h(2x + h)}{hx^2(x+h)^2} = \lim_{{h \to 0}} \frac{-2(2x + h)}{x^2(x+h)^2} \]
06

Apply the Limit

As \( h \to 0 \), the expression simplifies to:\[ \frac{-2 imes 2x}{x^2(x)^2} = \frac{-4x}{x^4} = \frac{-4}{x^3} \]
07

Conclusion: The Derivative

Thus, the derivative of \( y = \frac{2}{x^2} \) is:\[ y' = -\frac{4}{x^3} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limit Definition of Derivative
In calculus, the derivative of a function at a certain point gives us the rate of change or the slope of the tangent line at that particular point. The limit definition of a derivative is a fundamental concept where we define the derivative of a function \( y=f(x) \) as:
  • \( f'(x) = \lim_{{h \to 0}} \frac{{f(x+h) - f(x)}}{h} \)
This means that the derivative is the result of taking the limit as the difference \( h \) approaches zero in the difference quotient.
In simpler terms, it calculates how much the function \( f(x) \) changes as \( x \) changes by a tiny amount \( h \).
By applying this definition to the function \( y=\frac{2}{x^2} \), we seek to understand how \( y \) changes when \( x \) changes very slightly.
This process involves substituting and simplifying fractions to eventually solve the limit and find the derivative.
Rational Functions Derivatives
Rational functions are simply fractions with polynomials in both the numerator and the denominator. Finding derivatives of these functions can be a bit tricky, but with some practice, it becomes intuitive.The function \( y = \frac{2}{x^2} \) is a rational function with a polynomial numerator and an \( x^2 \) term in the denominator.
To find its derivative using the limit definition, one must:
  • Find \( f(x+h) \) by substituting \( x+h \) into the function: \( \frac{2}{(x+h)^2} \).
  • Set up the difference \( \frac{2}{(x+h)^2} - \frac{2}{x^2} \) which you simplify using a common denominator.
Simplifying these terms helps eliminate \( h \) from the fraction.
Finally, solve the limit to find the derivative. Especially for rational functions, it’s essential to perform algebraic simplification to handle the expression efficiently.
Differentiation Techniques
Beyond using the limit definition, differentiation involves several techniques to make finding derivatives easier. While the exercise used the limit definition, here are some useful differentiation techniques.
  • Power Rule: For any function of the form \( x^n \), the derivative is \( nx^{n-1} \). For example, \( \frac{d}{dx}(x^2)=2x \).
  • Quotient Rule: Useful for rational functions, if \( y = \frac{u}{v} \), the derivative \( y' = \frac{u'v - uv'}{v^2} \), where \( u' \) and \( v' \) are derivatives of \( u \) and \( v \).
  • Product Rule: If \( y = uv \), the derivative \( y' = u'v + uv' \).
Using these rules can simplify calculations significantly for more complex functions.
While the limit definition builds a deep understanding of what a derivative is, these techniques provide practical tools for efficiency and accuracy in calculus.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solve the given problems by using implicit differentiation.The pressure \(P\), volume \(V\), and temperature \(T\) of a gas are related by \(P V=n(R T+a P-b P / T),\) where \(a, b, n,\) and \(R\) are \(c \subset\) stants. For constant \(V\), find \(d P / d T\).

Evaluate the second derivative of the given function for the given value of \(x\). $$y=3(1+2 x)^{4}, x=\frac{1}{2}$$

\(\lim _{x \rightarrow a^{-}} f(x)\) means to find the limit as x approaches a from the left only, and \(\lim _{x \rightarrow a^{+}} f(x)\) means to find the limit as \(x\) approaches a from the right only. These are called one-sided limits. Solve the following problems. Is there a difference between \(\lim _{x \rightarrow 2^{-}} \frac{1}{\sqrt{x-2}}\) and \(\lim _{x \rightarrow 2^{+}} \frac{1}{\sqrt{x-2}} ?\)

In Exercises \(65-72, \lim _{x \rightarrow a^{-}} f(x)\) means to find the limit as \(x\) approaches a from the left only, and \(\lim _{x \rightarrow a^{+}} f(x)\) means to find the limit as \(x\) approaches a from the right only. These are called one-sided limits. Solve the following problems. Is there a difference between \(\lim _{x \rightarrow 2^{-}} \frac{1}{\sqrt{x-2}}\) and \(\lim _{x \rightarrow 2^{+}} \frac{1}{\sqrt{x-2}} ?\)

\(\lim _{x \rightarrow a^{-}} f(x)\) means to find the limit as x approaches a from the left only, and \(\lim _{x \rightarrow a^{+}} f(x)\) means to find the limit as \(x\) approaches a from the right only. These are called one-sided limits. Solve the following problems. In Einstein's theory of relativity, the length \(L\) of an object moving at a velocity \(v\) is \(L=L_{0} \sqrt{1-\frac{v^{2}}{c^{2}}},\) where \(c\) is the speed of light and \(L_{0}\) is the length of the object at rest. Find lim \(L\) and explain why a limit from the left is used.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.