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Find the equation of the least-squares line for the given data. Graph the line and data points on the same graph. The altitude \(h\) (in \(\mathrm{m}\) ) of a rocket was measured at several positions at a horizontal distance \(x\) (in \(\mathrm{m}\) ) from the launch site, shown in the table. Find the least-squares line for \(h\) as a function of \(x\). $$\begin{array}{c|c|r|c|c|c|c}x(\mathrm{m}) & 0 & 500 & 1000 & 1500 & 2000 & 2500 \\\\\hline h(\mathrm{m}) & 0 & 1130 & 2250 & 3360 & 4500 & 5600\end{array}$$

Short Answer

Expert verified
The least-squares line is \( h = 10.04x - 9743.33 \).

Step by step solution

01

Organize the Data

First, list the given data points as ordered pairs \((x, h)\): \[(0, 0), (500, 1130), (1000, 2250), (1500, 3360), (2000, 4500), (2500, 5600) \]
02

Use the Least-Squares Formula

The equation of the least-squares line is given by \( h = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. To find \( m \), use the formula: \[ m = \frac{n(\sum x_i y_i) - (\sum x_i)(\sum y_i)}{n(\sum x_i^2) - (\sum x_i)^2} \]And to find \( b \): \[ b = \frac{\sum y_i - m(\sum x_i)}{n} \]Where \( n \) is the number of data points.
03

Calculate Required Sums

Calculate the following sums using the data: - \( \sum x_i = 0 + 500 + 1000 + 1500 + 2000 + 2500 = 7500 \)- \( \sum y_i = 0 + 1130 + 2250 + 3360 + 4500 + 5600 = 16840 \)- \( \sum x_i y_i = (0)(0) + (500)(1130) + (1000)(2250) + (1500)(3360) + (2000)(4500) + (2500)(5600) = 34,862,500 \)- \( \sum x_i^2 = 0^2 + 500^2 + 1000^2 + 1500^2 + 2000^2 + 2500^2 = 10,750,000 \) - \( n = 6 \) (number of data points)
04

Calculate the Slope (\(m\))

Plug the sums into the formula for \( m \):\[ m = \frac{6(34,862,500) - (7500)(16840)}{6(10,750,000) - (7500)^2} \]After simplifying, \[ m = \frac{209,175,000 - 126,300,000}{64,500,000 - 56,250,000} = \frac{82,875,000}{8,250,000} = 10.04 \]
05

Calculate the Y-Intercept (\(b\))

Substitute the values in the formula for \( b \): \[ b = \frac{16840 - 10.04(7500)}{6} \]Simplify this expression: \[ b = \frac{16840 - 75300}{6} = \frac{-58460}{6} = -9743.33 \]
06

Form the Least-Squares Line Equation

Now that you have \( m \) and \( b \), the least-squares line equation becomes: \[ h = 10.04x - 9743.33 \]
07

Graph the Line and Data Points

Plot the given data points on a graph. Then, using the least-squares equation \( h = 10.04x - 9743.33 \), draw the line on the same graph. The x-axis will represent the horizontal distance \( x \) in meters, and the y-axis will represent the altitude \( h \) in meters. The line captures the trend of the data points.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Regression
Linear regression is a fundamental method used in statistics for modeling the relationship between two variables by fitting a linear equation to the data. This process helps us understand how one variable affects another, which is particularly useful for predictions and trend analysis. In the least-squares approach, our goal is to find the line that best fits our data by minimizing the sum of the squares of the vertical distances of the points from the line.

This line is called the least-squares line, and it is represented by the equation \( h = mx + b \), where \( h \) is the dependent variable (altitude in our exercise), \( x \) is the independent variable (distance), \( m \) is the slope, and \( b \) is the y-intercept. The slope \( m \) indicates how much \( h \) changes for a one-unit change in \( x \), and the y-intercept \( b \) is the value of \( h \) when \( x \) is zero. The essence of linear regression is to make predictions for \( h \) based on different values of \( x \).

By calculating the least-squares line, we aim to find a balance between all data points to predict new values as accurately as possible. This offers a powerful tool for making informed decisions based on trends we observe from the data.
Data Analysis
Data analysis involves inspecting, cleaning, transforming, and modeling data to discover useful information and support decision-making. In linear regression, data analysis begins with organizing data points into a format that can be analyzed. For the least-squares method, we arrange our observed values into pairs \((x, h)\) and calculate necessary sums to determine the line of best fit.

  • The sum of all \( x \) values (\( \sum x_i \)) tells us about the collective measure of our independent variable.
  • The sum of all \( h \) values (\( \sum y_i \)) helps us understand the total of our dependent outcomes.
  • \( \sum x_i y_i \) is the sum of the product of each pair \((x, h)\), which is crucial in calculating the slope \( m \).
  • Finally, \( \sum x_i^2 \) is the sum of squares of \( x \) values, a component needed to compute both \( m \) and \( b \).
Each of these sums helps us model how the independent variable (distance) relates to the dependent variable (altitude). By systematically analyzing our data using these metrics, we apply statistical rigor to draw reliable conclusions.
Mathematical Modelling
Mathematical modelling is the process of representing real-world phenomena through mathematics to analyze and solve problems. In our exercise, we model the trajectory of a rocket flight using a linear equation. This involves making an abstract representation of the flight path based on empirical data. By applying mathematical formulas, we estimate the path and make predictions about the rocket's altitude at various horizontal distances.

We use the slopes and intercepts calculated through linear regression to form a predictive model. In this context, the least-squares line \( h = 10.04x - 9743.33 \) acts as our model. This equation doesn't just fit the current data; it also allows extrapolation to determine altitudes for distances beyond those initially measured.

Mathematical modelling is critical for translating complex patterns into understandable terms. This process not only aids in visualization and interpretation but also enhances our ability to make predictions and understand how variables are connected. Consequently, models like the least-squares line are instrumental in fields ranging from engineering and science to economics and social sciences, providing a quantitative framework to address various challenges.

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Most popular questions from this chapter

Find the equation of the least-squares line for the given data. Graph the line and data points on the same graph. In an electrical experiment, the following data were found for the values of current and voltage for a particular element of the circuit. Find the voltage \(V\) as a function of the current \(i\). $$\begin{array}{l|r|r|r|r|r}\text {Current }(\mathrm{mA}) & 15.0 & 10.8 & 9.30 & 3.55 & 4.60 \\\\\hline \text {Voltage}(\mathrm{V}) & 3.00 & 4.10 & 5.60 & 8.00 & 10.50\end{array}$$

Find the equation of the least-squares line for the given data. Graph the line and data points on the same graph. In testing an air-conditioning system, the temperature \(T\) in a building was measured during the afternoon hours with the results shown in the table. Find the least-squares line for \(T\) as a function of the time \(t\) from noon. $$\begin{array}{l|r|r|r|r|r|r}t \text { (h) } & 0.0 & 1.0 & 2.0 & 3.0 & 4.0 & 5.0 \\\\\hline T\left(^{\circ} \mathrm{C}\right) & 20.5 & 20.6 & 20.9 & 21.3 & 21.7 & 22.0\end{array}$$

Solve the given problems. With \(75.8 \%\) of the area under the normal curve to the right of \(z\) find the \(z\) -value.

Find the indicated measure of central tendency. In a particular month, the electrical usage, rounded to the nearest \(100 \mathrm{kW} \cdot \mathrm{h}\) (kilowatt-hours), of 1000 homes in a certain city was summarized as follows: $$\begin{array}{l|c|c|c|c|c|c|c|c} \text {Usage} & 500 & 600 & 700 & 800 & 900 & 1000 & 1100 & 1200 \\ \hline \text {No. Homes} & 22 & 80 & 106 & 185 & 380 & 122 & 90 & 15 \end{array}$$ Find the mean of the electrical usage.

Use the following data. Five automobile engines are taken from the production line each hour and tested for their torque (in \(\mathrm{N} \cdot \mathrm{m}\) ) when rotating at a constant frequency. The measurements of the sample torques for 20 h of testing are as follows: $$\begin{aligned} &1\\\ &\begin{array}{c|ccccc} \text {Hour} & \multicolumn{3}{|c} { \text {Torques (in }\mathrm{N} \cdot \mathrm{m}) \text {of Five Engines}} \\ \hline 1 & 366 & 352 & 354 & 360 & 362 \\ 2 & 370 & 374 & 362 & 366 & 356 \\ 3 & 358 & 357 & 365 & 372 & 361 \\ 4 & 360 & 368 & 367 & 359 & 363 \\ 5 & 352 & 356 & 354 & 348 & 350 \\ 6 & 366 & 361 & 372 & 370 & 363 \\ 7 & 365 & 366 & 361 & 370 & 362 \\ 8 & 354 & 363 & 360 & 361 & 364 \\ 9 & 361 & 358 & 356 & 364 & 364 \\ 10 & 368 & 366 & 368 & 358 & 360 \\ 11 & 355 & 360 & 359 & 362 & 353 \\ 12 & 365 & 364 & 357 & 367 & 370 \\ 13 & 360 & 364 & 372 & 358 & 365 \\ 14 & 348 & 360 & 352 & 360 & 354 \\ 15 & 358 & 364 & 362 & 372 & 361 \\ 16 & 360 & 361 & 371 & 366 & 346 \\ 17 & 354 & 359 & 358 & 366 & 366 \\ 18 & 362 & 366 & 367 & 361 & 357 \\ 19 & 363 & 373 & 364 & 360 & 358 \\ 20 & 372 & 362 & 360 & 365 & 367 \end{array} \end{aligned}$$ Plot an \(R\) chart.

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