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Use the following data. An automobile company tested a new electric engine, and found the following results. In twenty tests of the range (in mi) that a certain model car could travel (under specified conditions) before the batteries needed recharging. $$\begin{aligned}&143,148,146,144,149,144,150,148,148,144\\\&153,146,147,146,147,149,145,151,149,148\end{aligned}$$ Form a frequency distribution table with five classes.

Short Answer

Expert verified
The frequency distribution table divides the data into four classes with frequencies 4, 8, 6, and 2 respectively.

Step by step solution

01

Find the Range

First, calculate the range of the data by subtracting the smallest value from the largest value. The smallest value is 143 and the largest value is 153. Therefore, the range is:\[\text{Range} = 153 - 143 = 10\]
02

Determine Class Width

Divide the range by the desired number of classes (5 in this case) to find the class width. Ensure to round up to the nearest whole number because class width should be an integer:\[\text{Class Width} = \left\lceil \frac{10}{5} \right\rceil = 2\]
03

Define Class Intervals

Using the smallest data value (143) as the starting point, define each class interval by adding the class width to the class limit until all five classes are established: 1. 143 - 145 2. 146 - 148 3. 149 - 151 4. 152 - 154
04

Tally Frequency for Each Class

Count how many data points fall into each class interval: 1. 143 - 145: 4 data points (143, 144, 144, 145) 2. 146 - 148: 8 data points (146, 146, 147, 146, 147, 148, 148, 148) 3. 149 - 151: 6 data points (149, 149, 149, 150, 151) 4. 152 - 154: 2 data points (153)
05

Construct Frequency Distribution Table

Create the table using the class intervals and their corresponding frequencies:\[\begin{array}{|c|c|}\hline\text{Class Interval} & \text{Frequency} \\hline143 - 145 & 4 \146 - 148 & 8 \149 - 151 & 6 \152 - 154 & 2 \\hline\end{array}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Range Calculation
The range in a frequency distribution table gives a quick picture of how data is spread out. To calculate the range, you subtract the smallest data value from the largest data value. It's a straightforward measure that helps you understand the span of your data. For example, if the smallest number in your data set is 143 and the largest is 153, the range is \[ \text{Range} = 153 - 143 = 10\] The range doesn't provide any information on the distribution of data between the extreme values, but it's an essential first step. Knowing the range helps you set up your class intervals, which is crucial for organizing and analyzing your data effectively.
Defining Class Intervals
Class intervals are the ranges you set to group your data. They make it easier to analyze and interpret. To create class intervals, you use the range calculated earlier. The class interval size, or class width, is found by dividing the range by the desired number of classes. For example, to have five classes:\[ \text{Class Width} = \left\lceil \frac{10}{5} \right\rceil = 2\] Rounded up to the nearest whole number, this ensures that your intervals capture all the data points without overlap.
Starting with the smallest data point, 143, you define each class interval by adding the class width to create successive ranges like 143-145 and so on.
  • 143 - 145
  • 146 - 148
  • 149 - 151
  • 152 - 154
This step is vital for structuring a well-organized frequency distribution table.
Simplifying Data Analysis
A frequency distribution table aids in simplifying data analysis. It helps visualize the data to see patterns and trends. By tallying how many data points fall into each class interval, you can quickly discern where data concentrations are.
For instance:
  • 143 - 145: 4 data points
  • 146 - 148: 8 data points
  • 149 - 151: 6 data points
  • 152 - 154: 2 data points
The table shows that most of the car's range data is concentrated within 146-148 miles. This overview is helpful in identifying how test results in different categories compare to one another in terms of frequency.
It reduces large volumes of data into a format that is easier to interpret and analyze, especially useful in spotting characteristics and tendencies that might not be obvious from raw numbers alone.
Enhancing Mathematics Education
Frequency distribution tables play a significant role in mathematics education. They provide a hands-on approach to learning concepts like data organization, statistical analysis, and mathematical reasoning skills.
These tables are practical tools for:
  • standing as a first introduction to the world of statistics
  • showing real-world applications of mathematical calculations
  • developing analytical and critical-thinking skills
Working through an exercise to develop a frequency distribution table involves several steps that mirror real-world problem-solving. Students learn to calculate, organize, and analyze data—key skills that are transferable to many fields and everyday decision-making.
Additionally, understanding the connection between mathematical theory and application improves engagement and retention, fostering a deeper appreciation for mathematics.

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Most popular questions from this chapter

Find the indicated quantities. The alcohol contents (in \(\%\) ) in the blood-streams of those charged with DUI at a police check point were as follows: 0.15,0.11,0.13,0.16,0.12,0.09,0.10,0.11,0.13,0.06,0.12, 0.11,0.09,0.17,0.14,0.15,0.11,0.14,0.12,0.15,0.10,0.11,0.13 Draw a frequency polygon using six classes.

Find the indicated quantities. In testing a braking system, the distance required to stop a car from \(70 \mathrm{mi} / \mathrm{h}\) was measured in 120 trials. The results are shown in the following distribution table: $$\begin{array}{l|c|c|c|c}\text {Stopping Distance (ft)} & 155-159 & 160-164 & 165-169 & 170-174 \\ \hline \text {Times Car Stopped} & 2 & 15 & 32 & 36 \\\\\text {Stopping Distance (ft)} & 175-179 & 180-184 & 185-189 \\\\\hline \text {Times Car Stopped} & 24 & 10 & 1\end{array}$$ Form a relative frequency distribution table for these data.

Use the following data. Five AC adaptors that are used to charge batteries of a cellular phone are taken from the production line each 15 minutes and tested for their direct- current output voltage. The output voltages for 24 sample subgroups are as follows: $$\begin{array}{c|ccccc} \text {Subgroup} & \multicolumn{3}{|c} {\text {Output Voltages of Five Adaptors}} \\ \hline 1 & 9.03 & 9.08 & 8.85 & 8.92 & 8.90 \\ 2 & 9.05 & 8.98 & 9.20 & 9.04 & 9.12 \\ 3 & 8.93 & 8.96 & 9.14 & 9.06 & 9.00 \\ 4 & 9.16 & 9.08 & 9.04 & 9.07 & 8.97 \\ 5 & 9.03 & 9.08 & 8.93 & 8.88 & 8.95 \\ 6 & 8.92 & 9.07 & 8.86 & 8.96 & 9.04 \\ 7 & 9.00 & 9.05 & 8.90 & 8.94 & 8.93 \\ 8 & 8.87 & 8.99 & 8.96 & 9.02 & 9.03 \\ 9 & 8.89 & 8.92 & 9.05 & 9.10 & 8.93 \\ 10 & 9.01 & 9.00 & 9.09 & 8.96 & 8.98 \\ 11 & 8.90 & 8.97 & 8.92 & 8.98 & 9.03 \\ 12 & 9.04 & 9.06 & 8.94 & 8.93 & 8.92 \\ 13 & 8.94 & 8.99 & 8.93 & 9.05 & 9.10 \\ 14 & 9.07 & 9.01 & 9.05 & 8.96 & 9.02 \\ 15 & 9.01 & 8.82 & 8.95 & 8.99 & 9.04 \\ 16 & 8.93 & 8.91 & 9.04 & 9.05 & 8.90 \\ 17 & 9.08 & 9.03 & 8.91 & 8.92 & 8.96 \\ 18 & 8.94 & 8.90 & 9.05 & 8.93 & 9.01 \\ 19 & 8.88 & 8.82 & 8.89 & 8.94 & 8.88 \\ 20 & 9.04 & 9.00 & 8.98 & 8.93 & 9.05 \\ 21 & 9.00 & 9.03 & 8.94 & 8.92 & 9.05 \\ 22 & 8.95 & 8.95 & 8.91 & 8.90 & 9.03 \\ 23 & 9.12 & 9.04 & 9.01 & 8.94 & 9.02 \\ 24 & 8.94 & 8.99 & 8.93 & 9.05 & 9.07 \end{array}$$ Plot an \(\bar{x}\) chart.

The weekly salaries (in dollars) for the workers in a small factory are as follows: 600,750,625,575,525,700,550, 750,625,800,700,575,600,700 Find the median and the mode of the salaries.

Find the equation of the least-squares line for the given data. Graph the line and data points on the same graph. A particular muscle was tested for its speed of shortening as a function of the force applied to it. The results appear below. Find the speed as a function of the force. $$\begin{array}{l|r|r|r|r|r}\text { Force (N) } & 60.0 & 44.2 & 37.3 & 24.2 & 19.5 \\\\\hline \text {Speed (m/s)} & 1.25 & 1.67 & 1.96 & 2.56 & 3.05\end{array}$$

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