Chapter 20: Problem 22
Evaluate the indicated functions. Find the value of \(\cos \left(\frac{\alpha}{2}\right)\) if \(\sin \alpha=-\frac{4}{5}\left(180^{\circ} < \alpha < 270^{\circ}\right)\)
Short Answer
Expert verified
\(\cos \left(\frac{\alpha}{2}\right) = -\sqrt{\frac{2}{5}}\).
Step by step solution
01
Determine the quadrant
Since \(180^{\circ} < \alpha < 270^{\circ}\), \(\alpha\) is in the third quadrant. In the third quadrant, sine is negative, which is consistent with \(\sin \alpha = -\frac{4}{5}\). Cosine is also negative in this quadrant.
02
Use the Pythagorean identity
We know \(\sin^2 \alpha + \cos^2 \alpha = 1\). Given \(\sin \alpha = -\frac{4}{5}\), we calculate \(\cos \alpha\) as follows: \[\cos^2 \alpha = 1 - \sin^2 \alpha = 1 - \left(-\frac{4}{5}\right)^2 = \frac{9}{25}\]Thus, \(\cos \alpha = -\frac{3}{5}\) since cosine is negative in the third quadrant.
03
Use the half-angle identity
The half-angle identity for cosine is \[\cos \left(\frac{\alpha}{2}\right) = \pm \sqrt{\frac{1 + \cos \alpha}{2}}\]Substituting \(\cos \alpha = -\frac{3}{5}\), we get \[\cos \left(\frac{\alpha}{2}\right) = \pm \sqrt{\frac{1 - \frac{3}{5}}{2}} = \pm \sqrt{\frac{2}{5}}\]To determine the sign, since \(\frac{90^{\circ}} < \frac{\alpha}{2} < 135^{\circ}\) (this calculation falls in the second quadrant), cosine here is negative.
04
Conclusion
Given the quadrant determination for \(\frac{\alpha}{2}\), conclude \(\cos \left(\frac{\alpha}{2}\right) = -\sqrt{\frac{2}{5}}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Half-Angle Identities
Half-angle identities are invaluable tools in trigonometry for simplifying expressions involving angles that are half of a given angle. For instance, if you know the trigonometric value of an angle \( \alpha \), you can figure out the value of its half angle, \( \frac{\alpha}{2} \).
The half-angle identity for cosine is particularly useful. It can be expressed as:
However, the ‘\( \pm \)’ indicates that the result can be either positive or negative depending on the quadrant where \( \frac{\alpha}{2} \) lies. In this exercise, we determined the sign based on which trigonometric quadrant the angle \( \frac{\alpha}{2} \) falls into. In our case, it was the second quadrant, where the cosine function is negative.
The half-angle identity for cosine is particularly useful. It can be expressed as:
- \( \cos \left( \frac{\alpha}{2} \right) = \pm \sqrt{ \frac{1 + \cos \alpha}{2} } \)
However, the ‘\( \pm \)’ indicates that the result can be either positive or negative depending on the quadrant where \( \frac{\alpha}{2} \) lies. In this exercise, we determined the sign based on which trigonometric quadrant the angle \( \frac{\alpha}{2} \) falls into. In our case, it was the second quadrant, where the cosine function is negative.
Exploring the Pythagorean Identity
The Pythagorean identity is a cornerstone of trigonometry. It connects the squares of sine and cosine of the same angle, forming a vital relationship:
In the exercise, the angle \( \alpha \) was given in the third quadrant with \( \sin \alpha = -\frac{4}{5} \). We could then find \( \cos \alpha \) using:
Thus, the Pythagorean identity helps us to bridge the gap between sine and cosine, giving us a comprehensive tool for solving trigonometric equations.
- \( \sin^2 \alpha + \cos^2 \alpha = 1 \)
In the exercise, the angle \( \alpha \) was given in the third quadrant with \( \sin \alpha = -\frac{4}{5} \). We could then find \( \cos \alpha \) using:
- \( \cos^2 \alpha = 1 - \sin^2 \alpha = 1 - \left(-\frac{4}{5}\right)^2 = \frac{9}{25} \)
Thus, the Pythagorean identity helps us to bridge the gap between sine and cosine, giving us a comprehensive tool for solving trigonometric equations.
Understanding Trigonometric Quadrants
Trigonometric quadrants play a crucial role in determining the sign of trigonometric functions based on the angle's position on the coordinate plane. The plane is divided into four quadrants:
- First Quadrant (\(0^\circ\) to \(90^\circ\)): All trigonometric functions are positive.
- Second Quadrant (\(90^\circ\) to \(180^\circ\)): Sine is positive, while cosine and tangent are negative.
- Third Quadrant (\(180^\circ\) to \(270^\circ\)): Tangent is positive, while sine and cosine are negative.
- Fourth Quadrant (\(270^\circ\) to \(360^\circ\)): Cosine is positive, while sine and tangent are negative.