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In Exercises solve the given problems. The altitude to the hypotenuse of a right triangle divides the triangle into two smaller triangles. What do you conclude about these two triangles?

Short Answer

Expert verified
The two smaller triangles are similar to each other and to the original triangle.

Step by step solution

01

Identify the Right Triangle and its Components

We begin with a right triangle, labeling its vertices as \(A\), \(B\), and \(C\), where \(\angle C\) is the right angle. The hypotenuse, \(AB\), is the longest side, and the altitude from \(C\) to \(AB\) meets \(AB\) at point \(D\). Thus, point \(D\) divides \(\triangle ABC\) into two smaller triangles, \(\triangle ACD\) and \(\triangle BCD\).
02

Apply the Similarity Principle

The altitude from a right angle to the hypotenuse in a right triangle divides the triangle into two smaller triangles that are similar to each other and to the original triangle. We use the criterion that if two triangles have one equal angle, and the sides surrounding the angle are proportional, then the triangles are similar.
03

Verify the Angle Congruences

In \(\triangle ABC\), \(\angle ACB = 90^\circ\). Likewise, \(\triangle ACD\) and \(\triangle BCD\) both have an angle \(\angle ACD\) and \(\angle BCD\) which are also \(90^\circ\). Thus, these two angles are equal in the smaller triangles.
04

Confirm Proportional Angle-Side Relationships

\(\angle ACB = \angle ACD\) and \(\angle BCD = \angle ACB\), ensuring that the angles in all triangles are the same or add up to the same measurement (completing a 180-degree half-plane). Thus, the angles are congruent in different triangles.
05

Conclude Triangle Similarity

Since \(\triangle ACD\) and \(\triangle BCD\) have the corresponding angles congruent with \(\triangle ABC\) and with each other, they are similar by the AA (Angle-Angle) similarity criterion. Thus, \(\triangle ACD \sim \triangle BCD \sim \triangle ABC\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Right Triangle
A right triangle is a type of triangle that one might encounter often in geometry. Its distinguishing feature is one 90-degree angle, meaning it has one angle that's right. This right angle is usually denoted as \( \angle C \) when labeling the vertices as \( A \), \( B \), and \( C \). The side opposite this right angle, known as the hypotenuse (\( AB \) if placed properly), represents the triangle's longest side due to its direct opposition to the maximal angle.Helping one visualize this, picture the triangle as having two other sides: what we call the "legs," \( AC \) and \( BC \). A right triangle serves as a foundational concept in trigonometry as well as in various similarity and congruency rules of geometry. By examining a right triangle, particularly when understanding its components and characteristics, you grasp a crucial building block of geometric study.
Altitude to Hypotenuse
Imagine a line drawn from the right angle vertex of a triangle down to the hypotenuse. This is known as the altitude. In a right triangle, dropping an altitude from the right angle, usually labeled\( C \), divides the triangle into two smaller ones. For our right triangle labeled as \( \triangle ABC \), if you draw the line to create point \( D \) on \( AB \), you create two new triangles: \( \triangle ACD \) and \( \triangle BCD \).
  • The original triangle: \( \triangle ABC \)
  • The two smaller triangles created: \( \triangle ACD \) and \( \triangle BCD \)
This concept is fascinating because the altitude creates triangles that help form complex geometric relationships, particularly focusing on similar triangles. This simple imaginary or drawn line becomes crucial in proving various geometric properties and problems, making the understanding of the altitude's impact meaningful.
AA Similarity Criterion
In geometry, the AA similarity criterion is a powerful tool. It dictates that if two angles of one triangle are equal to two angles of another triangle, the triangles are similar. Why is this important? Because when dealing with right triangles and particularly engaging with altitudes, this rule comes into play.For \( \triangle ABC \), where \( \angle ACB = 90^\circ \), drawing an altitude from \( C \) creates angles in \( \triangle ACD \) and \( \triangle BCD \) matching those in the entire triangle, making all these triangles similar.
  • \( \triangle ACD \sim \triangle ABC \)
  • \( \triangle BCD \sim \triangle ABC \)
This criterion allows us to conclude similarity reliably without needing every side's proportion. Using the rule, we leverage angles in counter balanced smaller triangles, reassuring that the shapes mirror each other in ratios and general form without full measures.
Angle Congruence
Understanding angle congruence is essential in the context of triangle similarity. In our right triangle example, it's necessary to check that corresponding angles in divided sections of the original triangle are equal. When a right triangle is divided by an altitude as discussed, angles in \( \triangle ACD \) and \( \triangle BCD \) can be matched based on the original. Between these smaller triangles and the full triangle:
  • \( \angle ACD = 90^\circ \)
  • \( \angle BCD = 90^\circ \)
These congruent angles confirm how the pieces fit together, helping to establish the relation -Reinforcing how these angles and their congruence are pivotal in ensuring that, through reorganizing the sides or structure results aspire towards geometric truths like similarity and other congruency-related discoveries.

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Most popular questions from this chapter

Solve the given problems. Spaceship Earth (shown in Fig. 2.125 ) at Epcot Center in Florida is a sphere of \(165 \mathrm{ft}\) in diameter. What is the volume of Spaceship Earth?

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calculate the indicated areas. All data are accurate to at least two significant digits. Using aerial photography, the widths of an area burned by a forest fire were measured at 0.5 -mi intervals, as shown in the following table: $$\begin{array}{l|r|r|r|r|r|r|r|r|r}\text {Distance (mi) } & 0.0 & 0.5 & 1.0 & 1.5 & 2.0 & 2.5 & 3.0 & 3.5 & 4.0 \\\\\hline \text {Width}(\mathrm{mi}) & 0.6 & 2.2 & 4.7 & 3.1 & 3.6 & 1.6 & 2.2 & 1.5 & 0.8 \end{array}$$ Determine the area burned by the fire by using the trupezoidal rule.

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