Chapter 19: Problem 22
Find the first four terms of the indicated expansions. $$\left(2 a-x^{-1}\right)^{11}$$
Short Answer
Expert verified
2048a^{11} - 11264a^{10}x^{-1} + 28160a^9x^{-2} - 42240a^8x^{-3}.
Step by step solution
01
Identify the Binomial Theorem
The binomial theorem is used for expanding expressions of the form \((a+b)^n\). According to the theorem: \[(a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\] where \(\binom{n}{k}\) is the binomial coefficient \(\frac{n!}{k!(n-k)!}\).
02
Assign Values to Variables
Identify \(a\) and \(b\) in the expression \((2a-x^{-1})^{11}\). Here, \(a = 2a\), \(b = -x^{-1}\), and \(n = 11\).
03
Calculate the First Term
The first term is for \(k = 0\): \(\binom{11}{0} (2a)^{11-0} (-x^{-1})^0 = 1 \cdot (2a)^{11} \cdot 1 = (2a)^{11}.\) Calculating it gives: \((2a)^{11} = 2^{11}a^{11} = 2048a^{11}.\)
04
Calculate the Second Term
The second term is for \(k = 1\): \(\binom{11}{1} (2a)^{11-1} (-x^{-1})^1 = 11 \cdot (2a)^{10} \cdot (-x^{-1}).\)Calculating: \(11 \cdot 2^{10}a^{10}(-x^{-1}) = -11 \cdot 1024a^{10}x^{-1} = -11264a^{10}x^{-1}.\)
05
Calculate the Third Term
The third term is for \(k = 2\): \(\binom{11}{2} (2a)^{11-2} (-x^{-1})^2 = 55 \cdot (2a)^9 \cdot x^{-2}.\)Calculating: \(55 \cdot 2^9a^9x^{-2} = 55 \cdot 512a^9x^{-2} = 28160a^9x^{-2}.\)
06
Calculate the Fourth Term
The fourth term is for \(k = 3\): \(\binom{11}{3} (2a)^{11-3} (-x^{-1})^3 = 165 \cdot (2a)^8 \cdot (-x^{-1})^3.\)Calculating: \(165 \cdot 2^8a^8(-x^{-3}) = -165 \cdot 256a^8x^{-3} = -42240a^8x^{-3}.\)
07
Write the First Four Terms
Combine the results of each term calculated: - First term: \(2048a^{11}\)- Second term: \(-11264a^{10}x^{-1}\)- Third term: \(28160a^9x^{-2}\)- Fourth term: \(-42240a^8x^{-3}\).Thus, the first four terms are: \[2048a^{11} - 11264a^{10}x^{-1} + 28160a^9x^{-2} - 42240a^8x^{-3}.\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Coefficient
The binomial coefficient is a crucial part of the binomial theorem. It's the numerical factor that multiplies the terms in a binomial expansion. For any non-negative integers, the binomial coefficient is written as \(\binom{n}{k}\), representing the number of ways to choose \(k\) items out of \(n\) total items without regard to the order of selection.
This coefficient is calculated using the formula:
This coefficient is calculated using the formula:
- \(\binom{n}{k} = \frac{n!}{k!(n-k)!}\)
Expansion of Expressions
The Binomial Theorem provides a method for expanding an expression raised to a power, specifically those of the form \((a + b)^n\). This theorem turns a potentially complex calculation into a structured process.To apply this theorem, consider the expression \((2a - x^{-1})^{11}\). Here, you identify \(a\) as \(2a\) and \(b\) as \(-x^{-1}\), with \(n = 11\).
Through the expansion:
Through the expansion:
- Each term is calculated as \(\binom{n}{k} a^{n-k} b^k\).
- For the first four terms, \(k\) takes values from 0 to 3.
- Each term involves raising \(a\) to a power that decreases as \(k\) increases, and \(b\) is raised to a power matching \(k\).
Polynomial Terms
In binomial expansions, especially when applying the binomial theorem, each result of the expansion is a term in a polynomial. Each term is a distinct part of the whole polynomial structure, combining variables raised to various powers with a constant coefficient.Considering \((2a - x^{-1})^{11}\), let's break down the polynomial terms:
- **First Term**: \(2048a^{11}\) is derived from \((2a)^{11}\), dominating due to the large exponent on \(a\).
- **Second Term**: \(-11264a^{10}x^{-1}\) shows the combined effect of \(a\) and \(-x^{-1}\), with the negative sign from \(-x^{-1}\).
- **Third Term**: \(28160a^9x^{-2}\) further reduces the power of \(a\) while increasing the influence of \(x^{-1}\).
- **Fourth Term**: \(-42240a^8x^{-3}\), synthesizing higher powers of \(-x^{-1}\) leading to larger negative contributions.