Chapter 18: Problem 52
Solve the given applied problems involving variation. The time \(t\) required to test a computer memory unit varies directly as the square of the number \(n\) of memory cells in the unit. If a unit with 4800 memory cells can be tested in 15.0 s, how long does it take to test a unit with 8400 memory cells?
Short Answer
Step by step solution
Understand Direct Variation
Establish the Equation
Solve for Constant k
Calculate Time for 8400 Cells
Solve the Final Equation
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Proportionality Constant
- If the number of memory cells doubles, the time taken will increase by the square of two, provided \( k \) remains unchanged.
- The value of \( k \) can be found by using any known pair of \( (n, t) \) such as when \( n = 4800 \) and \( t = 15.0 \), resulting in an equation to solve for \( k \).
- This constant can then be utilized to find unknown values of \( t \) for any given \( n \).
Applied Mathematics
- It allows predictions to be made without physically testing every scenario, saving both time and resources.
- By understanding relationships like the one between test time and the number of cells, companies can optimize their processes to become more efficient.
- Engineers and scientists rely on these mathematical concepts to design scalable systems that anticipate future needs.
Memory Cells Testing
- Each memory cell needs to be checked for errors, reliability, and speed under various conditions.
- The square relationship indicates that test time grows significantly as the count of cells increases.
- Understanding this relationship allows for efficient scheduling and resource allocation in data centers.
Problem Solving Steps
- Derive the relevant equation: Begin with the general form \( t = k \cdot n^2 \).
- Calculate the proportionality constant: Use given values to solve for \( k \). In our case: \[k = \frac{15.0}{4800^2}\]
- Use \( k \) to find unknowns: With \( k \) determined, apply it to different scenarios, like testing 8400 cells using \( t = k \cdot (8400)^2 \).