/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Express the ratios in the simple... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Express the ratios in the simplest form. $$18 \mathrm{V} \text { to } 3 \mathrm{V}$$

Short Answer

Expert verified
The ratio 18V to 3V simplifies to 6:1.

Step by step solution

01

Write the Ratio as a Fraction

Start by expressing the given ratio in fractional form. The ratio of 18V to 3V can be written as \( \frac{18V}{3V} \).
02

Cancel Common Units

In the fraction \( \frac{18V}{3V} \), the units \( V \) appear in both the numerator and the denominator, so we can cancel them out. This simplifies the fraction to \( \frac{18}{3} \).
03

Simplify the Fraction

Now simplify the fraction \( \frac{18}{3} \). Divide both the numerator and the denominator by their greatest common divisor, which is 3. \( 18 \div 3 = 6 \) and \( 3 \div 3 = 1 \). Thus, \( \frac{18}{3} = \frac{6}{1} \).
04

Express as a Ratio

The simplified fraction \( \frac{6}{1} \) translates back to a ratio of 6:1.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simplification of Fractions
Simplifying fractions is a crucial skill in mathematics that helps in making complex fractions easier to work with. When you simplify a fraction, you are essentially reducing it to its smallest possible equivalent form. Here's how you can achieve that:
  • Identify the numerator and the denominator of the fraction. For example, in the fraction \( \frac{18}{3} \), 18 is the numerator and 3 is the denominator.
  • Find a number that divides both the numerator and the denominator without leaving a remainder. This number is known as the Greatest Common Divisor, or GCD.
  • Divide both the numerator and the denominator by their GCD. This will give you the simplified form of the fraction.
For example, to simplify \( \frac{18}{3} \):- The GCD of 18 and 3 is 3.- Dividing both by 3, you get \( \frac{18 \div 3}{3 \div 3} = \frac{6}{1} \).The simplified form \( \frac{6}{1} \) is much easier to work with and understand. Simplifying fractions helps in comparing, adding, subtracting, and converting fractions into different forms.
Greatest Common Divisor
The Greatest Common Divisor (GCD) is a key concept when simplifying fractions. It is the largest number that divides both the numerator and the denominator of a fraction without leaving a remainder. To find the GCD:
  • List the factors of both the numerator and the denominator.
  • Identify the largest factor that both numbers share.
For example, let's find the GCD of 18 and 3: - Factors of 18 are 1, 2, 3, 6, 9, and 18. - Factors of 3 are 1 and 3. - The greatest common factor they share is 3. Once you know the GCD, you can simplify fractions more easily since dividing by this number ensures both the numerator and denominator will end in integers. Knowing how to find the GCD is extremely helpful in reducing fractions to their simplest form and is a fundamental part of fraction and ratio calculations.
Fraction to Ratio Conversion
Converting a simplified fraction back into a ratio is the last step in the process of working with ratios in simplest form. Ratios are essentially fractions written in a different way, making them useful for comparing two quantities. Here's how you can convert a fraction to a ratio:
  • Start with your simplified fraction. For example, \( \frac{6}{1} \).
  • Read the fraction as "6 over 1," which can be translated into the ratio 6:1.
  • The numbers in the ratio represent a comparison between two quantities. Here, "6:1" means for every 6 units of one quantity, there is 1 unit of the other.
This conversion process follows from the steps of simplifying the fraction because when a fraction's denominator is 1, it effectively becomes the unit comparison within a ratio. Mastery of converting fractions to ratios helps in solving real-world problems where comparisons are crucial, such as recipes, models, or scaling designs. Understanding this transformation enhances your ability to interpret and apply mathematical concepts in daily life scenarios.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Solve the given applied problems involving variation. The electric resistance \(R\) of a wire varies directly as its length \(l\) and inversely as its cross-sectional area \(A\). Find the relation between resistance, length, and area for a wire that has a resistance of \(0.200 \Omega\) for a length of \(225 \mathrm{ft}\) and crosssectional area of 0.0500 in. \(^{2}\)The general gas law states that the pressure \(P\) of an ideal gas varies directly as the thermodynamic temperature \(T\) and inversely as the volume \(V\). If \(P=610 \mathrm{kPa}\) for \(V=10.0 \mathrm{cm}^{3}\) and \(T=290 \mathrm{K},\) find \(V\) for \(P=400 \mathrm{kPa}\) and \(T=400 \mathrm{K}\)

Solve the given applied problems involving variation. The distance \(d\) that can be seen from horizon to horizon from an airplane varies directly as the square root of the altitude \(h\) of the airplane. If \(d=133 \mathrm{mi}\) for \(h=12,000 \mathrm{ft},\) find \(d\) for \(h=16,000 \mathrm{ft}\)

Answer the given questions by setting up and solving the appropriate proportions. When a bullet is fired from a loosely held rifle, the ratio of the mass of the bullet to that of the rifle equals the negative of the reciprocal of the ratio of the velocity of the bullet to that of the rifle. If a \(3.0 \mathrm{kg}\) rifle fires a \(5.0 \mathrm{g}\) bullet and the velocity of the bullet is \(300 \mathrm{m} / \mathrm{s}\) what is the recoil velocity of the rifle?

Solve the given applied problems involving variation. The escape velocity \(v\) a spacecraft needs to leave the gravitational field of a planet varies directly as the square root of the product of the planet's radius \(R\) and its acceleration due to gravity \(g .\) For Mars and earth, \(R_{M}=0.533 R_{e}\) and \(g_{M}=0.400 g_{e^{*}}\) Find \(v_{M}\) for Mars if \(v_{e}=11.2 \mathrm{km} / \mathrm{s}\)

$$\text { Find the required ratios.}$$ The percent grade of a road is the ratio of vertical rise to the horizontal change in distance (expressed in percent). If a highway rises \(75 \mathrm{m}\) for each \(1.2 \mathrm{km}\) along the horizontal, what is the percent grade?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.