Chapter 17: Problem 38
Solve the given problems. If \(|x-1|>4,\) find \(a\) and \(b\) if \(x+1>a\) and \(x-1
Short Answer
Expert verified
\(a > -2\) and \(b > 4\).
Step by step solution
01
Understand Absolute Inequality
The inequality \(|x-1| > 4\) tells us that the distance between \(x\) and 1 is greater than 4. This means \(x\) is either less than \(1-4\) or greater than \(1+4\). The inequality can be expanded to \(x-1 > 4\) or \(x-1 < -4\).
02
Solve and Split the Inequality
Solve the inequalities separately. For \(x-1 > 4\), solve to find \(x > 5\). For \(x-1 < -4\), solve to find \(x < -3\). Therefore, \(x\) is in the intervals \((-, -3)\cup(5, )\).
03
Identify Requirements for a and b
We need to find \(a\) and \(b\) such that \(x+1 > a\) and \(x-1 < b\) considering our values of \(x\) from the previous step, which leads to two separate cases.
04
Calculate a for both cases
For the first case \(x < -3\), \(x+1 < -2\), so we must have \(a < -2\). For the second case \(x > 5\), \(x+1 > 6\), so we must have \(a < 6\). Thus, the valid range for \(a\) is both conditions combined.
05
Calculate b for both cases
For the first case \(x < -3\), \(x-1 < -4\), so we must have \(b > -4\). For the second case \(x > 5\), \(x-1 < 4\), so we must have \(b > 4\). Thus, \(b\) needs to satisfy these conditions.
06
Compile Results
Combining the results, for \(a\), conditions \(-2 < a < 6\) hold since \(x < -3\) gives \(a < -2\) or \(x > 5\) gives \(a > 6\). For \(b\), conditions \(b > -4\) or \(b > 4\) lead to \(b > 4\) being the stricter condition.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Inequality Solving
When solving inequalities, we're trying to find all the possible values of a variable that make the inequality true. Inequalities show us ranges of values that aren't necessarily equal. Take \( |x-1| > 4 \) for example.
This absolute inequality means the distance between \(x\) and 1 is more than 4, leading us to two possible situations: either \(x\) is greater than \(5\) or \(x\) is less than \(-3\).
This gives two pieces of the solution, which we can write as three separate inequalities:
This absolute inequality means the distance between \(x\) and 1 is more than 4, leading us to two possible situations: either \(x\) is greater than \(5\) or \(x\) is less than \(-3\).
This gives two pieces of the solution, which we can write as three separate inequalities:
- For \(x - 1 > 4\), solve to get \(x > 5\).
- For \(x - 1 < -4\), solve to end up with \(x < -3\).
Interval Notation
Interval notation is a neat, concise way to express a range of values. For instance, let's consider the solution to our inequality \( |x-1| > 4 \). Once we solve it, we find that \(x\) can be in any of two ranges: less than \(-3\) or more than 5.
In interval notation, this looks like this: \((-\infty, -3) \cup (5, \infty)\). The parentheses are key here:
In interval notation, this looks like this: \((-\infty, -3) \cup (5, \infty)\). The parentheses are key here:
- They mean the endpoints, such as \(-3\) and 5, are not included in the solution set.
- Square brackets \([ ]\) would mean the endpoints are included.
Mathematical Concepts
Understanding these mathematical concepts like inequalities and intervals can unlock a deeper understanding of math. It all connects to how we organize and describe the world using numbers:
- Absolute inequalities show us how to measure distances between numbers.
- By splitting these inequalities, we discuss different scenarios that can occur.
- With interval notation, we represent complex solution sets simply and visually.