Chapter 16: Problem 37
Solve the given problems. For the matrix \(A=\left[\begin{array}{ll}a & b \\ c & d\end{array}\right],\) show that $$\frac{1}{a d-b c}\left[\begin{array}{cc} a & b \\ c & d \end{array}\right]\left[\begin{array}{rr} d & -b \\ -c & a \end{array}\right]=\left[\begin{array}{ll} 1 & 0 \\ 0 & 1 \end{array}\right]$$
Short Answer
Step by step solution
Write the Expression for the Matrix Product
Multiply Matrices
Simplify with the Scalar Pre-Multiplication
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Adjugate Matrix
- The transpose step is particularly simple here because the adjugate of a 2x2 matrix is another 2x2 matrix where elements just swap places. - Understanding how the adjugate is formed helps in computational problems where you need the inverse of a matrix since this is directly used in the computation of the matrix inverse. - In essence, the adjugate transforms the original matrix in such a way that when it is used in conjunction with a scalar derived from the determinant, it yields the identity matrix.
Determinant
- If the determinant is non-zero, the matrix is invertible (i.e., it has an inverse).
- A zero determinant indicates that the matrix does not have an inverse, making it singular.
Identity Matrix
- Any matrix multiplied by the identity matrix of compatible dimensions results in the original matrix, essentially acting like multiplying a number by 1.
- When verifying inverses, as in the problem at hand, showing that a matrix times its inverse produces the identity matrix confirms the correctness of the inverse.
Matrix Multiplication
- For a 2x2 matrix multiplication, such as \( A = \begin{bmatrix} a & b \ c & d \end{bmatrix} \) and its adjugate, the resulting product is another 2x2 matrix.
- Each entry is computed by multiplying elements from the corresponding row of the first matrix and column of the second. For instance, the top-left of the resulting matrix comes from multiplying the top row of the first by the first column of the second.