Chapter 12: Problem 10
An ac circuit contains the given combination of circuit elements from among a resistor \((R=45.0 \Omega),\) a capacitor \((C=86.2 \mu \mathrm{F}),\) and an inductor \((L=42.9 \mathrm{mH}) .\) If the frequency in the circuit is \(f=60.0 \mathrm{Hz},\) find \((a)\) the magnitude of the impedance and (b) the phase angle between the current and the voltage. The circuit has the resistor, the inductor, and the capacitor (an \(R L C\) circuit).
Short Answer
Step by step solution
Calculate the Inductive Reactance
Calculate the Capacitive Reactance
Calculate the Total Impedance
Calculate the Phase Angle
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Impedance Calculation
- \[ Z = \sqrt{R^2 + (X_L - X_C)^2} \]
Phase Angle Determination
- \[ \phi = \tan^{-1}\left(\frac{X_L - X_C}{R}\right) \]
Inductive Reactance
- \[ X_L = 2\pi f L \]
Capacitive Reactance
- \[ X_C = \frac{1}{2\pi f C} \]
AC Circuit Analysis
- Resistors show steady opposition (resistance) unaffected by frequency.
- Inductors and capacitors show varying opposition (reactance) depending on the AC's frequency.
- Inductive reactance rises with frequency, while capacitive reactance falls.
- These differences in reactance can cause shifts in phase angles, affecting circuit performance.