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You plan to conduct a survey to find what proportion of the workforce has two or more jobs. You decide on the \(95 \%\) confidence level and a margin of error of \(2 \% .\) A pilot survey reveals that 5 of the 50 sampled hold two or more jobs. How many in the workforce should be interviewed to meet your requirements?

Short Answer

Expert verified
You need to survey at least 865 people.

Step by step solution

01

Understand the Required Formula

To calculate the necessary sample size for a proportion, we use the formula:\[ n = \left( \frac{Z^2 \times p \times (1-p)}{E^2} \right) \]where \( Z \) is the critical value for the confidence level, \( p \) is the estimated proportion, and \( E \) is the margin of error.
02

Determine Known Values

From the pilot survey, 5 out of 50 individuals hold two or more jobs. This gives the estimated proportion \( p = \frac{5}{50} = 0.1 \).For a \(95\%\) confidence level, the critical value \( Z \approx 1.96 \).The margin of error \( E \) is \( 0.02 \).
03

Substitute Known Values into Formula

Substitute the known values into the sample size formula:\[ n = \left( \frac{(1.96)^2 \times 0.1 \times (1 - 0.1)}{(0.02)^2} \right) \]
04

Perform the Calculations

Calculate each component inside the formula:1. \( Z^2 = (1.96)^2 = 3.8416 \)2. \( p(1-p) = 0.1 \times 0.9 = 0.09 \)3. \( E^2 = (0.02)^2 = 0.0004 \)Now substitute into the equation:\[ n = \left( \frac{3.8416 \times 0.09}{0.0004} \right) \approx 864.36\]
05

Conclude with the Required Sample Size

Since the sample size must be a whole number, round up \(864.36\) to \(865\).Therefore, you should survey at least 865 people to meet your requirements of a \(95\%\) confidence level and a margin of error of \(2\%\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Level
When you hear the term "confidence level," think about how certain you want to be about your survey results. In our exercise, we have chosen a 95% confidence level, which is quite common. This means that if we were to repeat the survey many times, 95 out of 100 similar surveys would produce results that fall within the margin of error. In simple terms, it's your level of assurance that the survey reflects the true opinions of the entire workforce.
The confidence level affects the sample size. The higher the confidence level, the larger the sample needed. This is because a higher confidence level means you want to be more sure about your findings, which requires more data to minimize variability.
  • 95% is a standard choice, offering a good balance between certainty and practical sample sizes.
  • Higher confidence (like 99%) would require surveying more people.
Margin of Error
The margin of error represents how much you're allowed to be wrong. In our example, it's set at 2%. This 2% margin of error tells you how close the survey's results will be to the actual population's results. A margin of error lets us know the range within which the true value lies.
Let's say your survey finds that 10% of the workforce holds two jobs, but with a margin of error of 2%, you're saying the real value is likely between 8% and 12%.
  • Smaller margins of error require larger sample sizes.
  • It gives the maximum expected difference between the survey result and the actual population value.
This 2% margin is reasonable for many surveys but requiring a smaller margin (like 1%) would mean you need a much larger sample.
Proportion Estimation
Proportion estimation is about figuring out what fraction of your population has a particular characteristic. In our survey example, we're estimating what proportion of the workforce has two or more jobs. We found from the pilot survey data, 5 out of 50 people, which translates to 10%. This is the estimated proportion (denoted as \( p \)).
Keep in mind, the better your initial estimate, the more accurate your overall survey will be. If you don't have any prior data, you might assume it's a 50/50 split, but this is only an educated guess.
  • The closer \( p \) is to 0.5, the larger the sample size needed for precision.
  • Using previous data helps refine this estimate.
Critical Value
The critical value \( Z \) is associated with the confidence level. It acts like a multiplier that helps determine how straightforward or rigorous the estimates need to be. In our sample size calculation, a 95% confidence level corresponds to a critical value \( Z \) of approximately 1.96.
The critical value forms a part of the formula:
  • The higher the confidence level, the larger the \( Z \).
  • For 95%, use 1.96. For 99%, use approximately 2.576.
These values come from the standard normal distribution (think of the bell curve). They represent not just our desired accuracy, but how spread out or tight we wish our data to be within that margin of error. Understanding critical values is crucial in creating reliable statistical results.

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Most popular questions from this chapter

Based on a sample of 50 U.S. citizens, the American Film Institute found that a typical American spent 78 hours watching movies last year. The standard deviation of this sample was 9 hours. a. Develop a \(95 \%\) confidence interval for the population mean number of hours spent watching movies last year. b. How large a sample should be used to be \(90 \%\) confident the sample mean is within 1\. O hour of the population mean?

A sample of 81 observations is taken from a normal population with a standard deviation of \(5 .\) The sample mean is \(40 .\) Determine the \(95 \%\) confidence interval for the population mean.

The owner of Britten's Egg Farm wants to estimate the mean number of eggs produced per chicken. A sample of 20 chickens shows they produced an average of 20 eggs per month with a standard deviation of 2 eggs per month. a. What is the value of the population mean? What is the best estimate of this value? b. Explain why we need to use the \(t\) distribution. What assumption do you need to make? c. For a \(95 \%\) confidence interval, what is the value of \(t ?\) d. Develop the \(95 \%\) confidence interval for the population mean. e. Would it be reasonable to conclude that the population mean is 21 eggs? What about 25 eggs?

A sample of 250 observations is selected from a normal population with a population standard deviation of \(25 .\) The sample mean is 20 . a. Determine the standard error of the mean. b. Explain why we can use formula \((9-1)\) to determine the \(95 \%\) confidence interval. c. Determine the \(95 \%\) confidence interval for the population mean.

A random sample of 85 group leaders, supervisors, and similar personnel at General Motors revealed that, on average, they spent 6.5 years in a particular job before being promoted. The standard deviation of the sample was 1.7 years. Construct a \(95 \%\) confidence interval.

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