Chapter 9: Problem 43
HighTech Inc. randomly tests its employees about company policies. Last year, in the 400 random tests conducted, 14 employees failed the test. Develop a \(99 \%\) confidence interval for the proportion of applicants that fail the test. Would it be reasonable to conclude that \(5 \%\) of the employees cannot pass the company policy test? Explain.
Short Answer
Step by step solution
Determine the Sample Proportion
Find the Standard Error
Determine the Z-Score for 99% Confidence
Calculate the Margin of Error
Construct the Confidence Interval
Compare with the 5% Failing Rate
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sample Proportion
\[ \hat{p} = \frac{x}{n} \]where \(x\) is the number of successes (or failures, in this case), and \(n\) is the total sample size. For HighTech Inc., \( \hat{p} = \frac{14}{400} = 0.035 \).
- It's a straightforward calculation that provides a basic understanding of the data set's part conforming to a specific trait.
- The sample proportion is often denoted as \( \hat{p} \).
Standard Error
The formula for the standard error of a proportion is:\[ SE = \sqrt{ \frac{\hat{p}(1-\hat{p})}{n} } \]where \( \hat{p} \) is the sample proportion and \( n \) is the sample size. In the context of our exercise, substituting \( \hat{p} = 0.035 \) and \( n = 400 \), we find:
\[ SE = \sqrt{ \frac{0.035(1-0.035)}{400} } \approx 0.00915 \]
- The standard error helps assess the precision of our sample proportion estimate.
- A smaller standard error indicates a more precise estimate of the population parameter.
Z-Score
For a 99% confidence interval, we find the z-score that corresponds to how many standard deviations away our sample statistic could be from the true population parameter. The value from the z-distribution table for a 99% confidence is approximately 2.576.
- The z-score bridges the sample data and the population estimate, aiding in calculating the confidence interval.
- It's used to accommodate the desired level of confidence, providing a range within which the true parameter lies.
Margin of Error
To find the margin of error (ME) for a proportion, you multiply the standard error (SE) by the z-score. In HighTech Inc.'s scenario, it looks like this:\[ ME = z \times SE = 2.576 \times 0.00915 \approx 0.0236 \]
- The margin of error provides a cushion for our sample estimate, accounting for likely sampling variability.
- It allows us to construct confidence intervals, offering a range of values around the sample statistic.