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Consider these six values a population: \(13,3,8,10,8,\) and 6 a. Determine the mean of the population. b. Determine the variance.

Short Answer

Expert verified
Mean is 8; Variance is approximately 9.67.

Step by step solution

01

Calculate the Mean

First, find the mean of the population by adding together all the values and then dividing by the number of values. Compute the sum: \[ 13 + 3 + 8 + 10 + 8 + 6 = 48 \]Now, divide by the total number of values (6):\[ \text{Mean} = \frac{48}{6} = 8 \]
02

Find Squared Deviations

Subtract the mean from each value and square the result:\[ (13 - 8)^2 = 25 \]\[ (3 - 8)^2 = 25 \]\[ (8 - 8)^2 = 0 \]\[ (10 - 8)^2 = 4 \]\[ (8 - 8)^2 = 0 \]\[ (6 - 8)^2 = 4 \]
03

Calculate Variance

For population variance, take the average of these squared deviations. Sum the squared deviations:\[ 25 + 25 + 0 + 4 + 0 + 4 = 58 \]Now, divide by the number of values (6):\[ \text{Variance} = \frac{58}{6} \approx 9.67 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean Calculation
When calculating the mean of a population, you're essentially finding the average value of all entries. To find the mean, add up all the numbers in your dataset, and then divide by the total number of values. Using our exercise example, we add up the numbers \( 13, 3, 8, 10, 8, \) and \( 6 \), resulting in a sum of \( 48 \).
The next step is to divide this sum by the number of values, which in this case is 6:
  • Sum of Values: \( 48 \)
  • Number of Values: \( 6 \)
Therefore, the mean \( \mu \) is given by:
\[ \mu = \frac{48}{6} = 8 \]This "8" now represents the average or central value of the set of data. It's a useful measure because it gives a single number that sums up the entire dataset.
Variance Calculation
Variance provides insight into how much the values in a population deviate, on average, from the mean. Calculating variance involves several steps. First, we need the squared deviations of each data point from the mean. Then, these squared values are averaged.
Variance is essential for understanding the spread or variability of the data.
With the squared deviations already computed in the original exercise, we find the sum:
  • Squaring the deviations of each value gives us: \( 25, 25, 0, 4, 0, 4 \).
  • Sum of Squared Deviations: \( 25 + 25 + 0 + 4 + 0 + 4 = 58 \)
  • Since we are treating this as a complete population, divide by the number of data points:
  • Population Variance: \[ \sigma^2 = \frac{58}{6} \approx 9.67 \]
Variance is a valuable statistic because it tells how far data points tend to be from the mean by this average squared amount.
Squared Deviations
The concept of squared deviations is pivotal in statistical analysis, especially when calculating variance. To find these deviations, subtract the mean from each individual value and square the result.
This squaring ensures that deviations do not cancel each other out (since squaring makes all numbers positive), maintaining accuracy in measuring variabilities.
Let's take the set of values and compute:
  • For 13: \((13 - 8)^2 = 25\)
  • For 3: \((3 - 8)^2 = 25\)
  • For 8: \((8 - 8)^2 = 0\)
  • For 10: \((10 - 8)^2 = 4\)
  • For 8: \((8 - 8)^2 = 0\)
  • For 6: \((6 - 8)^2 = 4\)
These squared deviations are crucial because they become the building blocks for calculating variance and standard deviation, statistical measures that describe how spread out the data points are in your dataset.

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Most popular questions from this chapter

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