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The U.S. Department of Transportation estimates that \(10 \%\) of Americans carpool. Does that imply that \(10 \%\) of cars will have two or more occupants? A sample of 300 cars traveling southbound on the New Jersey Turnpike yesterday revealed that 63 had two or more occupants. At the .01 significance level, can we conclude that \(10 \%\) of cars traveling on the New Jersey Turnpike have two or more occupants?

Short Answer

Expert verified
Reject null hypothesis; proportion is not 10%.

Step by step solution

01

Define the Hypotheses

We begin by stating the null and alternative hypotheses. The null hypothesis, \( H_0 \), assumes that 10% of cars have two or more occupants: \( p = 0.10 \). The alternative hypothesis, \( H_a \), reflects that the percentage of cars with two or more occupants is different from 10%: \( p eq 0.10 \).
02

Determine the Test Statistic

Next, calculate the test statistic using the formula for the z-test for proportions: \[ z = \frac{\hat{p} - p_0}{\sqrt{\frac{p_0(1-p_0)}{n}}} \]Where \( \hat{p} = \frac{63}{300} \), \( p_0 = 0.10 \), and \( n = 300 \). Substituting these values, we find \( \hat{p} = 0.21 \).
03

Calculate the Test Statistic

Plug the values into the formula:\[ z = \frac{0.21 - 0.10}{\sqrt{\frac{0.10 \times 0.90}{300}}} \]Calculate the denominator first: \[ \sqrt{\frac{0.10 \times 0.90}{300}} = 0.01732 \]Then compute the z-value:\[ z = \frac{0.21 - 0.10}{0.01732} \approx 6.36 \]
04

Find Critical Value and Decision

With a significance level of \( \alpha = 0.01 \), the critical z-value(s) for a two-tailed test from the Z-distribution table is approximately ±2.576. Compare this with our calculated z-value.
05

Conclusion of the Test

Since the computed z-value of approximately 6.36 is greater than ±2.576, we reject the null hypothesis. This indicates that we have sufficient evidence at the 0.01 significance level to conclude that the proportion of cars with two or more occupants is not 10%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-test for proportions
The Z-test for proportions is a statistical method used to determine if there is a significant difference between an observed sample proportion and a known population proportion.
It helps us understand if any observed deviation could be attributed to random chance or if it suggests a real effect.

In the context of the exercise, we want to see if the proportion of cars with two or more occupants on the New Jersey Turnpike is different from the stated 10%.
  • To perform this test, we set up our sample proportion, \(\hat{p}\), which is calculated by dividing the number of successes (here, cars with two or more occupants) by the total sample size (in this exercise, it’s 63 out of 300).
  • We then use the population proportion \(p_0\) (0.10 in this exercise) and compare \(\hat{p}\) to \(p_0\).
  • The Z-test formula measures how many standard deviations our sample proportion \(\hat{p}\) is from the population proportion \(p_0\).
Paying attention to these calculations ensures we correctly interpret whether the observed difference is statistically significant.
Null and alternative hypotheses
In hypothesis testing, we always start with two opposing hypotheses.
The null hypothesis is a statement assuming there is no change or difference, while the alternative hypothesis is what we want to gather evidence for.
  • Null Hypothesis (\(H_0\)): This is a commonly accepted fact unless proven otherwise. In this exercise, \(H_0\) states that 10% of cars have two or more occupants: \(p = 0.10\).
  • Alternative Hypothesis (\(H_a\)): This suggests that there is a significant effect or difference. Here, \(H_a\) posits that the actual proportion of cars is different from 10%: \(p eq 0.10\).
By testing these hypotheses, we seek to either reject the null hypothesis in favor of the alternative or fail to provide enough evidence against the null hypothesis. This process involves calculating test statistics and comparing them to critical values derived from significance levels.
Significance level
The significance level, denoted by \( \alpha \), is a threshold used to determine whether the results are statistically significant.
It is the probability of rejecting the null hypothesis when it is actually true, also known as the Type I error.

In most hypothesis tests, a common significance level used is 0.05; however, in this exercise, we use a stricter level of 0.01.
  • A lower \( \alpha \) level, like 0.01, necessitates stronger evidence to reject the null hypothesis. This means the test is more stringent and less likely to yield false positives.
  • When the p-value (calculated probability) is below the significance level, we reject the null hypothesis.
In the exercise, since our calculated \(z\)-value is beyond the threshold of ±2.576 (which corresponds to a 0.01 significance level in a two-tailed test), it means our findings are statistically significant, and hence, we reject the null hypothesis, indicating a different proportion of cars with two or more occupants.

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Most popular questions from this chapter

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