/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 The following sample of observat... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The following sample of observations was randomly selected. $$ \begin{array}{llllll} \hline x & 4 & 5 & 3 & 6 & 10 \\ y & 4 & 6 & 5 & 7 & 7 \\ \hline \end{array} $$ Determine the correlation coefficient and interpret the relationship between \(x\) and \(y\).

Short Answer

Expert verified
The correlation coefficient is approximately 0.69, indicating a moderate positive relationship.

Step by step solution

01

Calculate the Means of x and y

Calculate the mean of the x values: \( \bar{x} = \frac{4 + 5 + 3 + 6 + 10}{5} = 5.6 \).\Calculate the mean of the y values: \( \bar{y} = \frac{4 + 6 + 5 + 7 + 7}{5} = 5.8 \).
02

Calculate the Deviations from the Mean

Find deviations for each \( x \): \( (4-5.6), (5-5.6), (3-5.6), (6-5.6), (10-5.6) \). \Find deviations for each \( y \):\( (4-5.8), (6-5.8), (5-5.8), (7-5.8), (7-5.8) \).
03

Compute the Products of Deviations

Calculate the product of deviations for each pair:\( (4-5.6)(4-5.8), (5-5.6)(6-5.8), (3-5.6)(5-5.8), (6-5.6)(7-5.8), (10-5.6)(7-5.8) \).This results in the values: \( 2.88, -0.48, 4.48, 0.48, 11.88 \).
04

Calculate Sum of Products of Deviations

Sum these products: \(2.88 + (-0.48) + 4.48 + 0.48 + 11.88 = 19.24 \).
05

Calculate the Sum of Squared Deviations

Calculate deviations squared for x:\((4-5.6)^2, (5-5.6)^2, (3-5.6)^2, (6-5.6)^2, (10-5.6)^2 \)giving \(2.56, 0.36, 6.76, 0.16, 19.36 \).Sum: \(2.56 + 0.36 + 6.76 + 0.16 + 19.36 = 29.2 \).For y:\((4-5.8)^2, (6-5.8)^2, (5-5.8)^2, (7-5.8)^2, (7-5.8)^2 \)giving \(3.24, 0.04, 0.64, 1.44, 1.44 \).Sum: \(3.24 + 0.04 + 0.64 + 1.44 + 1.44 = 6.8 \).
06

Calculate the Correlation Coefficient

Use the formula for the correlation coefficient:\[ r = \frac{\sum{(x_i - \bar{x})(y_i - \bar{y})}}{\sqrt{\sum{(x_i - \bar{x})^2} \cdot \sum{(y_i - \bar{y})^2}}} \].Substitute the values:\[ r = \frac{19.24}{\sqrt{29.2 \cdot 6.8}} \approx \frac{19.24}{14} \approx 0.69 \].
07

Interpret the Correlation Coefficient

The correlation coefficient \( r = 0.69 \) suggests a moderate positive linear relationship between \( x \) and \( y \). As \( x \) increases, \( y \) also tends to increase.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Relationship
The concept of a linear relationship is foundational in understanding how two variables interact with each other. In a linear relationship, changes in one variable systematically lead to proportional changes in another variable. Consider a seesaw, where one side consistently goes up while the other side goes down. This is similar to a positive linear relationship, although in our case if one side goes up, so does the other.

For instance, in the given exercise, as the variable \( x \) (e.g., number of hours studied) increases, the variable \( y \) (e.g., test scores) also tends to increase. The correlation coefficient donated as \( r \), measures the strength and direction of this linear relationship. If \( r \) is close to 1, it indicates a perfect positive linear relationship. Conversely, if it is close to -1, it suggests a perfect negative linear relationship (one increases while the other decreases).

The value \( r = 0.69 \) from this exercise indicates a moderate positive linear relationship, meaning there is a noticeable but not perfect upward trend. Become familiar with identifying these patterns, as they are crucial for predicting outcomes.
Covariance
Covariance is a measure of how changes in one variable are associated with changes in another. It is a way of quantifying the directional relationship between two variables.

When calculating covariance, we compute the product of deviations from the means of the variables \( x \) and \( y \). These products are then summed to give the covariance. A positive covariance indicates that both variables tend to increase together, while a negative covariance suggests that as one variable increases, the other tends to decrease.

In the exercise, we calculated the sum of the products of deviations, such as
  • (4-5.6)(4-5.8) and so on, resulting in 19.24.
  • This positive value indicates a direct relationship, contributing to the positive correlation coefficient.
Understanding covariance helps in interpreting the overall nature of the relationship before precisely calculating the correlation coefficient.
Mean and Deviations
The mean is a central value in a set of numbers, essentially the arithmetic average. It represents a typical value around which the data condense. When we reference deviations, we are considering how far each data point in a set is from this central value (the mean).

It's calculated by subtracting each data point from the mean, resulting in deviations like
  • (4-5.6), (5-5.6), for example.
  • This deviation tells us if a particular value is higher or lower than the average.
Understanding these deviations is key in calculating the correlation coefficient since their products help us measure how \( x \) and \( y \) vary together. This aids in determining whether they follow a linear relationship.

Assessing mean and deviations is fundamental in most statistical analyses, assisting in comprehending data spread and variability.
Sum of Squares
The sum of squares is a method used to measure the total variability within a dataset. It's essentially the sum of the squared deviations from the mean for a set of values.

In the context of calculating correlation, the sum of squares gives us the total variance for each variable and is a component in the denominator of the correlation coefficient formula. The formulas calculate each deviation from the mean and square it, like
  • (4-5.6)^2 = 2.56, (6-5.6)^2 = 0.16, and so forth.
  • Why squares? Squaring ensures that negative and positive deviations don't cancel out, providing a true measure of spread.
Calculating these sums for both the \( x \) and \( y \) variables, as shown in our exercise, allows us to measure their individual variabilities before determining their combined effect in a linear relationship.

Understanding the sum of squares helps in grasping how dense or spread out the data points are around the mean, a fundamental component of most statistical methods.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The following regression equation was computed from a sample of 20 observations: $$ \hat{y}=15-5 x $$ SSE was found to be 100 and SS total was 400 . a. Determine the standard error of estimate. b. Determine the coefficient of determination. c. Determine the correlation coefficient. (Caution: Watch the sign!)

The production department of Celltronics International wants to explore the relationship between the number of employees who assemble a subassembly and the number produced. As an experiment, two employees were assigned to assemble the subassemblies. They produced 15 during a one-hour period. Then four employees assembled them. They produced 25 during a one-hour period. The complete set of paired observations follows. $$ \begin{array}{|cc|} \hline \begin{array}{c} \text { Number of } \\ \text { Assemblers } \end{array} & \begin{array}{c} \text { One-Hour } \\ \text { Production } \\ \text { (units) } \end{array} \\ \hline 2 & 15 \\ 4 & 25 \\ 1 & 10 \\ 5 & 40 \\ 3 & 30 \\ \hline \end{array} $$ The dependent variable is production; that is, it is assumed that different levels of production result from a different number of employees. a. Draw a scatter diagram. b. Based on the scatter diagram, does there appear to be any relationship between the number of assemblers and production? Explain. c. Compute the correlation coefficient.

A consumer buying cooperative tested the effective heating area of 20 different electric space heaters with different wattages. Here are the results. $$ \begin{array}{|crr|rrr|} \hline \text { Heater } & \text { Wattage } & \text { Area } & \text { Heater } & \text { Wattage } & \text { Area } \\ \hline 1 & 1,500 & 205 & 11 & 1,250 & 116 \\ 2 & 750 & 70 & 12 & 500 & 72 \\ 3 & 1,500 & 199 & 13 & 500 & 82 \\ 4 & 1,250 & 151 & 14 & 1,500 & 206 \\ 5 & 1,250 & 181 & 15 & 2,000 & 245 \\ 6 & 1,250 & 217 & 16 & 1,500 & 219 \\ 7 & 1,000 & 94 & 17 & 750 & 63 \\ 8 & 2,000 & 298 & 18 & 1,500 & 200 \\ 9 & 1,000 & 135 & 19 & 1,250 & 151 \\ 10 & 1,500 & 211 & 20 & 500 & 44 \\ \hline \end{array} $$ a. Compute the correlation between the wattage and heating area. Is there a direct or an indirect relationship? b. Conduct a test of hypothesis to determine if it is reasonable that the coefficient is greater than zero. Use the .05 significance level. c. Develop the regression equation for effective heating based on wattage. d. Which heater looks like the "best buy" based on the size of the residual?

A study of 20 worldwide financial institutions showed the correlation between their assets and pretax profit to be .86. At the .05 significance level, can we conclude that there is positive correlation in the population?

A dog trainer is exploring the relationship between the size of the dog (weight in pounds) and its daily food consumption (measured in standard cups). Below is the result of a sample of 18 observations. $$ \begin{array}{|ccc|ccc|} \hline \text { Dog } & \text { Weight } & \text { Consumption } & \text { Dog } & \text { Weight } & \text { Consumption } \\ \hline 1 & 41 & 3 & 10 & 91 & 5 \\ 2 & 148 & 8 & 11 & 109 & 6 \\ 3 & 79 & 5 & 12 & 207 & 10 \\ 4 & 41 & 4 & 13 & 49 & 3 \\ 5 & 85 & 5 & 14 & 113 & 6 \\ 6 & 111 & 6 & 15 & 84 & 5 \\ 7 & 37 & 3 & 16 & 95 & 5 \\ 8 & 111 & 6 & 17 & 57 & 4 \\ 9 & 41 & 3 & 18 & 168 & 9 \\ \hline \end{array} $$ a. Compute the correlation coefficient. Is it reasonable to conclude that the correlation in the population is greater than zero? Use the .05 significance level. b. Develop the regression equation for cups based on the dog's weight. How much does each additional cup change the estimated weight of the dog? c. Is one of the dogs a big undereater or overeater?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.