Chapter 8: Problem 33
Recent studies indicate that the typical 50 -year-old woman spends \(\$ 350\) per year for personal-care products. The distribution of the amounts spent follows a normal distribution with a standard deviation of \(\$ 45\) per year. We select a random sample of 40 women. The mean amount spent for those sampled is \(\$ 335 .\) What is the likelihood of finding a sample mean this large or larger from the specified population?
Short Answer
Step by step solution
Define the Parameters
Calculate the Standard Error of the Mean
Compute the Z-Score
Find the Probability from Z-Table
Interpret the Probability
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Standard Error
- \( \sigma \) is the population standard deviation
- \( n \) is the sample size
Z-Score
- \( \bar{x} \) is the sample mean
- \( \mu \) is the population mean
- \( \text{SE} \) is the standard error