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A normal distribution has a mean of 50 and a standard deviation of \(4 .\) a. Compute the probability of a value between 44.0 and 55.0 . b. Compute the probability of a value greater than 55.0 c. Compute the probability of a value between 52.0 and 55.0 .

Short Answer

Expert verified
a. 0.8276, b. 0.1056, c. 0.2029

Step by step solution

01

Understanding the Normal Distribution

The problem specifies that we are dealing with a normal distribution with a mean (\(\mu\) of 50 and a standard deviation (\(\sigma\) of 4. We need to find probabilities associated with certain ranges of values around this mean.
02

Standardizing Values for Part a

To compute the probability of a value between 44.0 and 55.0, first calculate the z-scores for 44.0 and 55.0. The formula for a z-score is \(z = \frac{x - \mu}{\sigma}\).For 44.0:\(z_1 = \frac{44 - 50}{4} = -1.5\).For 55.0:\(z_2 = \frac{55 - 50}{4} = 1.25\).
03

Calculating Probability for Part a

Using the standard normal distribution table, find the probabilities for these z-scores:- Probability for \(z_1 = -1.5\) is approximately 0.0668.- Probability for \(z_2 = 1.25\) is approximately 0.8944.The probability of a value between 44.0 and 55.0 is \(0.8944 - 0.0668 = 0.8276\).
04

Standardizing Values for Part b

For the probability of a value greater than 55.0, calculate the z-score for 55 as in Step 2:\(z_2 = 1.25\).
05

Calculating Probability for Part b

Using the table again, the probability for \(z_2 = 1.25\) from the mean to 55 is 0.8944. Since we want greater than 55, we calculate:Probability \(P(Z > 1.25) = 1 - 0.8944 = 0.1056\).
06

Standardizing Values for Part c

Calculate the z-scores for 52.0 and 55.0:For 52.0:\(z_3 = \frac{52 - 50}{4} = 0.5\).55.0's z-score was calculated earlier as \(z_2 = 1.25\).
07

Calculating Probability for Part c

Using the standard normal distribution table again:- Probability for \(z_3 = 0.5\) is approximately 0.6915.Thus, the probability of a value between 52.0 and 55.0 is \(0.8944 - 0.6915 = 0.2029\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Calculating probability in a normal distribution involves determining the likelihood of a value or range of values occurring. You start by understanding the distribution you're dealing with. In our example, the mean is 50 and the standard deviation is 4. The aim is to find out how likely it is for an observation to fall within a specified range.

Steps for Probability Calculation:
  • Determine the range or specific values for which probability is required. For example, between 44 and 55.
  • Compute a z-score for each boundary value to transform them into the standard normal distribution context.
  • Use the standard normal distribution table to find probabilities for these z-scores.
  • Compute differences or complements to find the desired probability, depending on whether it's a range or a single direction (greater than or less than).
These steps form the backbone of calculating probabilities for any normal distribution.
Z-score
The z-score is a measure of how many standard deviations away a particular value is from the mean of the distribution. It's a crucial concept in statistics, allowing you to standardize any value in a normal distribution.

The formula to calculate the z-score is \(z = \frac{x - \mu}{\sigma}\). In this formula:
  • \(x\) is the value you're examining, such as 44 or 55 in our exercise.
  • \(\mu\) is the mean of the distribution, here it's 50.
  • \(\sigma\) is the standard deviation, which is 4 in this case.
For example, the z-score for 44 is \(z = \frac{44 - 50}{4} = -1.5\), indicating that 44 is 1.5 standard deviations below the mean.

Z-scores thus help in interpreting values in the context of the overall distribution, making it easier to compute probabilities.
Standard Normal Distribution
The standard normal distribution is a special case of a normal distribution with a mean of 0 and a standard deviation of 1. It serves as a universal reference point for comparing z-scores.

Why is it important? Well, the standard normal distribution allows us to use z-score tables which provide probabilities for values between any z-score and the mean. By translating real-world values into z-scores, we can effortlessly read their probabilities using this universal distribution. For instance, when finding the probability between z-scores of -1.5 and 1.25, the corresponding probabilities 0.0668 and 0.8944 are found using the standard normal table.

In business statistics or any field that involves data analysis, understanding and using the standard normal distribution lets you find probabilities and make decisions based on statistical evidence efficiently.
Statistics for Business
Statistics play a critical role in business decision-making. By interpreting data correctly, businesses can make informed decisions to minimize risks and maximize profits.

Consider the application of normal distribution and probability in inventory management. A business could predict the likelihood of demand falling within a certain range, guiding how much stock to prepare. Utilizing the normal distribution, businesses transform real-world values into actionable insights through tools like the z-score and probabilities.

For effective use, businesses must:
  • Collect accurate data to ensure meaningful analysis.
  • Understand the context and assumptions behind statistical tools, like assuming normality in data distribution.
  • Regularly translate statistical findings into strategic business decisions, helping gain a competitive edge.
So, mastering these statistics tools isn't just academic; it's practically invaluable for enhancing business operations and success.

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Most popular questions from this chapter

Customers experiencing technical difficulty with their internet cable hookup may call an 800 number for technical support. It takes the technician between 30 seconds to 10 minutes to resolve the problem. The distribution of this support time follows the uniform distribution. a. What are the values for \(a\) and \(b\) in minutes? b. What is the mean time to resolve the problem? What is the standard deviation of the time? c. What percent of the problems take more than 5 minutes to resolve? d. Suppose we wish to find the middle 50 percent of the problem-solving times. What are the end points of these two times?

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According to a government study among adults in the 25- to 34-year age group, the mean amount spent per year on reading and entertainment is \(\$ 2,130\) (www.infoplease.com/ipa/ A0908759.html). Assume that the distribution of the amounts spent follows the normal distribution with a standard deviation of \(\$ 450 .\) a. What percent of the adults spend more than \(\$ 2,500\) per year on reading and entertainment? b. What percent spend between \(\$ 2,500\) and \(\$ 3,000\) per year on reading and entertainment? c. What percent spend less than \(\$ 1,000\) per year on reading and entertainment?

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A recent article in the Cincinnati Enquirer reported that the mean labor cost to repair a heat pump is \(\$ 90\) with a standard deviation of \$22. Monte's Plumbing and Heating Service completed repairs on two heat pumps this morning. The labor cost for the first was \(\$ 75\) and it was \(\$ 100\) for the second. Assume the distribution of labor costs follows the normal probability distribution. Compute \(z\) values for each and comment on your findings.

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