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In a Poisson distribution \(\mu=0.4\). a. What is the probability that \(x=0 ?\) b. What is the probability that \(x>0 ?\)

Short Answer

Expert verified
a. \( P(X=0) \approx 0.67032 \); b. \( P(X>0) \approx 0.32968 \).

Step by step solution

01

Identify Parameters

We are given that the mean \( \mu \) of the Poisson distribution is 0.4. This is a parameter of the distribution.
02

Poisson Probability Formula

The probability of observing \( x \) events in a Poisson distribution is calculated using the formula: \[P(X=x) = \frac{e^{-\mu} \mu^x}{x!}\] where \( e \) is approximately equal to 2.71828.
03

Calculate P(X=0)

To find the probability that \( x = 0 \), substitute \( x = 0 \) and \( \mu = 0.4 \) into the Poisson probability formula: \[P(X=0) = \frac{e^{-0.4} \times 0.4^0}{0!} = e^{-0.4} \times 1 = e^{-0.4}\] Use a calculator to find \( e^{-0.4} \approx 0.67032 \). So, \( P(X=0) \approx 0.67032 \).
04

Probability for x>0

To find the probability that \( x > 0 \), calculate the complement of \( P(X=0) \): \[P(X>0) = 1 - P(X=0)\] Substitute \( P(X=0) \approx 0.67032 \) into the equation: \[P(X>0) = 1 - 0.67032 = 0.32968\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Probability in Poisson Distribution
In the context of a Poisson distribution, the concept of probability is essential for predicting how likely we observe a certain number of events in a given time frame. For example, if we're given a mean (\( \mu \)) value that represents the average occurrence of events, we apply the probability formula to determine how likely each possible event count is.

The formula for the probability of observing exactly \(x\) occurrences is:
  • \(P(X=x) = \frac{e^{-\mu} \mu^x}{x!} \)
Here's a quick breakdown:- \(e^{-\mu}\) handles the exponential decay, regulating how quickly probabilities decrease as the number of events increases.- \(\mu^x\) uses the mean to scale the distribution's focus on expected values.- \(x!\) normalizes the result by accounting for all permutations of the \(x\) events without repetition.

This equation reflects the discrete nature of the Poisson distribution and helps calculate how often we'd see zero events or more.
The Role of Mean (\(\mu\)) in Poisson Distribution
The mean, denoted as \(\mu\), plays a crucial role in the Poisson distribution. It describes the average rate at which events occur over a specific interval of time or space. In our specific problem, we have \(\mu = 0.4\), indicating that, on average, 0.4 events are expected per interval.

The mean is instrumental in shaping the distribution:
  • It is central to the probability formula \(P(X=x)\), affecting both the exponential term (\(e^{-\mu}\)) and the mean-specific scaling (\(\mu^x\)).
  • As the mean (\(\mu\)) increases or decreases, the variance of the distribution, which measures how spread out the values are around the mean, also increases or decreases.
Understanding \(\mu\) helps set expectations for the first few values of \(x\), allowing you to determine likely outcomes in both tails of the distribution.

In practice, it guides our predictions about the likelihood of different scenarios when analyzing phenomena that follow this distribution pattern.
Euler's Number (\(e\)) and Its Importance
Euler's number \(e\) is approximately 2.71828 and is a fundamental constant in mathematics. It is the base of the natural logarithm and plays a vital role in the Poisson distribution due to its involvement in the formula for probability.

In the context of probability distributions like Poisson, \(e\) functions as the base for exponential decay:
  • It appears in the term \(e^{-\mu}\), which diminishes the impact of higher events counts as \(\mu\) determines their weight. The larger the mean, the slower this decay.
  • This property assists in creating a realistic model of random events diminishing in likelihood with increasing number of occurrences.
Therefore, \(e\) ensures the Poisson distribution remains exponential, accurately reflecting the real-world range of event frequencies. Treating \(e\) as a critical mathematical constant allows us to grasp processes that involve growth or decay, fitting scenarios captured by the Poisson model.
Understanding the Complement Rule in Probability
The complement rule in probability is a straightforward yet powerful concept: it helps you find the probability of an event not occurring by subtracting the probability of it occurring from one.

For instance, if we’re interested in finding \(P(X>0)\), we consider it the complement of \(P(X=0)\):
  • The equation \(P(X>0) = 1 - P(X=0)\) effectively converts knowing one probability into knowing its opposite.
  • This approach simplifies scenarios where calculating the complement directly is easier than calculating the desired probability directly.
Using the complement rule is useful when dealing with exhaustive probabilities and scenarios, where you are sure that all potential outcomes have been considered.

This is especially practical in Poisson distributions, where the cumbersome calculations for multiple non-zero outcomes can be bypassed, simplifying probability evaluations.

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Most popular questions from this chapter

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