/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 50 Assume the likelihood that any f... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Assume the likelihood that any flight on Northwest Airlines arrives within 15 minutes of the scheduled time is .90. We select four flights from yesterday for study. a. What is the likelihood all four of the selected flights arrived within 15 minutes of the scheduled time? b. What is the likelihood that none of the selected flights arrived within 15 minutes of the scheduled time? c. What is the likelihood at least one of the selected flights did not arrive within 15 minutes of the scheduled time?

Short Answer

Expert verified
a. 0.6561 b. 0.0001 c. 0.3439

Step by step solution

01

Define Probability Notations

Let the probability that a flight arrives within 15 minutes of the scheduled time be denoted by \( p = 0.9 \). The probability that a flight does not arrive within 15 minutes is \( 1 - p = 0.1 \).
02

Calculate Probability of All Flights On Time

The probability that all four flights arrived within 15 minutes of the scheduled time is the product of probabilities that each individual flight arrived on time. This is given by: \( (0.9)^4 = 0.6561 \).
03

Calculate Probability of No Flights On Time

The probability that none of the four flights arrived within 15 minutes of the scheduled time is the product of probabilities that each individual flight did not arrive on time. This is given by: \( (0.1)^4 = 0.0001 \).
04

Calculate Probability of At Least One Late Flight

The probability that at least one flight did not arrive within 15 minutes is the complement of all flights arriving on time. This is given by: \( 1 - (0.9)^4 = 1 - 0.6561 = 0.3439 \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculations
Probability is the measure of how likely an event is to occur. It ranges between 0 and 1, where 0 indicates an impossible event, and 1 indicates a certain event. In probability calculations, you often multiply the likelihood of independent events to find the probability of all events happening together. For example, to calculate the probability that all four flights arrive on time from the problem, each flight is an independent event with a probability of 0.9 (since each flight has a 90% chance of being on time). The combined probability of all flights being on time is obtained by multiplying:
  • The probability of the first flight being on time: 0.9,
  • times the probability of the second flight being on time: 0.9,
  • times the probability of the third flight: 0.9,
  • times the probability of the fourth flight: 0.9.
This calculation results in: \[(0.9)^4 = 0.6561\]As shown, multiplication is key to solving probability of consecutive independent events.
Complementary Probability
Complementary probability refers to the probability of an event not occurring. It's an important concept because sometimes it's easier to calculate the chance of something not happening and then subtracting it from 1 to find the likelihood of the event happening. In the exercise, we use this when calculating probabilities such as the chance that at least one flight did not arrive on time. If the probability that all flights arrive on time is 0.6561, the probability that at least one flight did not arrive on time will complement it:
  • The probability of all events occurring is 0.6561.
  • The complementary probability (the chance that at least one does not occur) is:\[1 - 0.6561 = 0.3439\]
Understanding complementary probability is very useful, especially in cases where calculating the direct probability can be complex or cumbersome.
Binomial Probability
Binomial probability involves situations where there are only two possible outcomes for each trial, such as success or failure. This suits our exercise because a flight can either arrive on time (success) or not (failure). The situation here involves four flights, and each one can independently be on time or late. This setup perfectly fits a binomial experiment. The formula for binomial probability is used to calculate the probability of getting a certain number of successes in a fixed number of trials. It is expressed as:\[P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\]where:
  • \(n\) is the number of trials (4 flights),
  • \(k\) is the number of successes we are interested in (such as all four flights on time),
  • \(p\) is the probability of success (0.9),
  • \(1-p\) is the probability of failure (0.1).
This formula can be adapted to answer various questions about probabilities in scenarios like this.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Several years ago Wendy's Hamburgers advertised that there are 256 different ways to order your hamburger. You may choose to have, or omit, any combination of the following on your hamburger: mustard, ketchup, onion, pickle, tomato, relish mayonnaise, and lettuce. Is the advertisement correct? Show how you arrive at your answer.

Two coins are tossed. If \(A\) is the event "two heads" and \(B\) is the event "two tails," are \(A\) and \(B\) mutually exclusive? Are they complements?

.A computer password consists of four characters. The characters can be one of the 26 letters of the alphabet. Each character may be used more than once. How many different passwords are possible?

Reynolds Construction Company has agreed not to erect all "look-alike" homes in a new subdivision. Five exterior designs are offered to potential home buyers. The builder has standardized three interior plans that can be incorporated in any of the five exteriors. How many different ways can the exterior and interior plans be offered to potential home buyers?

During the 1970 s the qame show Let's Make a Deal had a long run on TV. In the show a contestant was given a choice of three doors, behind one of which was a prize. The other two doors contained a gag gift of some type. After the contestant selected a door, the host of the show then revealed to them one of the doors from among the two not selected. The host asked the contestant if they wished to switch doors to one of those not chosen. Should the contestant switch? Are the odds of winning increased by switching doors?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.