/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 A representative of the Environm... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A representative of the Environmental Protection Agency (EPA) wants to select samples from 10 landfills. The director has 15 landfills from which she can collect samples. How many different samples are possible?

Short Answer

Expert verified
3003

Step by step solution

01

Understanding the Problem

We need to find how many different groups (samples) of 10 landfills can be chosen from a total of 15 landfills. This is a combinatorial problem where the order of selection does not matter.
02

Choosing the Method

Since the order does not matter, we use the combination formula to select 10 landfills from 15. The combination formula is given by \( C(n, k) = \frac{n!}{k!(n-k)!} \) where \( n \) is the total number of items, and \( k \) is the number of items to choose.
03

Applying the Combination Formula

Here, \( n = 15 \) and \( k = 10 \). Thus, the formula becomes \( C(15, 10) = \frac{15!}{10!(15-10)!} = \frac{15!}{10! \, 5!} \).
04

Calculating Factorials

Calculate the factorials: \( 15! = 15 \times 14 \times 13 \times 12 \times 11 \times 10! \). Since we will divide by \( 10! \), they cancel out in the combination formula. We then calculate \( 15 \times 14 \times 13 \times 12 \times 11 \) to consider and divide by \( 5! \).
05

Simplification and Calculation

First, calculate \( 15 \times 14 \times 13 \times 12 \times 11 = 360360 \). Then calculate \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \). Finally, divide \( \frac{360360}{120} \) to get 3003.
06

Conclusion

Thus, the number of different samples possible is 3003.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is a fascinating branch of mathematics focused on counting, arranging, and selecting items. It deals with problems where you need to determine how many ways you can arrange or select things under certain conditions.

In our sample scenario, the problem involves selecting specific quantities of items, specifically landfills, from a larger set. Here's where the idea of combinations comes into play. When the order of selection doesn't matter — meaning selecting one landfill first and another second is the same as selecting the second landfill first and the first second — we use combinations to count possibilities.

The notion of combinations contrasts with permutations, where the order does matter. This distinction is crucial for solving problems like our landfill example. By understanding whether order is significant, you learn which mathematical tools to use — like combinations for the landfill example!

Mastering combinatorial principles can significantly enhance problem-solving skills across various disciplines, such as computer science, finance, and biology.
Factorials
Factorials are a mathematical function represented by an exclamation mark \(n!\). They are fundamental in calculating permutations and combinations. A factorial of a number, say 5, denoted as \(5!\), means that you multiply 5 times all whole numbers less than it: \(5 \times 4 \times 3 \times 2 \times 1\).

In combination calculations, like in our landfill problem, you often need to cancel out a large part of the factorial calculation. For instance, in finding combinations where you need to choose 10 landfills out of 15 (15 C 10 ), the factorial of 15 (15! ) includes a factor of 10!. As such, much of the factorial computation cancels, simplifying to only the relevant terms. This efficiency makes factorials a powerful tool for combinatorial calculations.

Whenever you see a problem involving counting selection arrangements, factorials are likely creeping behind the scenes, helping to keep calculations manageable.
Sample Selection
Sample selection is the process of choosing a smaller subset from a larger set. In scenarios like the EPA's landfill project, we're interested in forming groups without concern for order, hence combinations come into play.

The main goal of sample selection is often to ensure representation or to make calculations more practical. For instance, examining all landfills might be unfeasible, so selecting a representative sample becomes necessary. Using combinatorics, selections ensure that every possible combination is considered once and only once.

In mathematical terms, the combination formula \( C(n, k) = \frac{n!}{k!(n-k)!} \) gets utilized to determine how many groups can be formed. This formula evaluates all potential samples without worrying about order, offering an exhaustive count of all possible sample sets.

Understanding sample selection not only aids in mathematics but also proves vital in statistical experiments, surveys, and any field where making sense of large datasets is critical.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A new sports car model has defective brakes 15 percent of the time and a defective steering mechanism 5 percent of the time. Let's assume (and hope) that these problems occur independently. If one or the other of these problems is present, the car is called a "lemon." If both of these problems are present, the car is a "hazard." Your instructor purchased one of these cars yesterday. What is the probability it is: a. A lemon? b. A hazard?

A large company that must hire a new president prepares a final list of five candidates, all of whom are equally qualified. Two of these candidates are members of a minority group. To avoid bias in the selection of the candidate, the company decides to select the president by lottery. a. \(2 / 5\) or.4 b. Classical a. What is the probability one of the minority candidates is hired? b. Which concept of probability did you use to make this estimate?

Two components, \(A\) and \(B\), are in series. (Being in series means that for the system to operate, both components \(A\) and \(B\) must work.) Assume the two components are independent. What is the probability the system works under these conditions? The probability \(A\) works is .90 and the probability \(B\) functions is also .90 .

Solve the following: a. \(40 ! / 35 !\) b. \({ }_{7} P_{4}\) c. \({ }_{5} C_{2}\)

There are 20 families living in the Willbrook Farms Development. Of these families 10 prepared their own federal income taxes for last year, 7 had their taxes prepared by a local professional, and the remaining 3 by H\&R Block. a. What is the probability of selecting a family that prepared their own taxes? b. What is the probability of selecting two families both of which prepared their own taxes? c. What is the probability of selecting three families, all of which prepared their own taxes? d. What is the probability of selecting two families, neither of which had their taxes prepared by H\&R Block?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.