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Let \(P(X)=.55\) and \(P(Y)=.35 .\) Assume the probability that they both occur is .20. What is the probability of either \(X\) or \(Y\) occurring?

Short Answer

Expert verified
The probability of either \( X \) or \( Y \) occurring is 0.70.

Step by step solution

01

Understanding the Problem

We need to find the probability of either event \( X \) or \( Y \) occurring given the individual probabilities \( P(X) = 0.55 \), \( P(Y) = 0.35 \), and the probability that both events occur \( P(X \cap Y) = 0.20 \).
02

Applying the Addition Rule

To find the probability of either \( X \) or \( Y \) occurring, we use the formula: \[ P(X \cup Y) = P(X) + P(Y) - P(X \cap Y) \]This rule accounts for the overlap between the events, which is \( P(X \cap Y) \).
03

Substitute the Given Values

Substitute the known values into the formula: \[ P(X \cup Y) = 0.55 + 0.35 - 0.20 \]
04

Calculate the Probability

Perform the calculations: \[ 0.55 + 0.35 = 0.90 \]\[ 0.90 - 0.20 = 0.70 \]Thus, the probability of either \( X \) or \( Y \) occurring is 0.70.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Addition Rule for Probabilities
The Addition Rule for Probabilities helps us find the probability that at least one of several events occurs. This is particularly useful when dealing with two overlapping events, like events X and Y in our example.
To use this rule properly, you must consider the entire overlap, which is when both events happen simultaneously.
The formula you use is:
  • \( P(X \cup Y) = P(X) + P(Y) - P(X \cap Y) \)
The subtraction part \( P(X \cap Y) \) corrects for the double-counting of the intersection where both events happen.
This ensures that the total probability calculation is accurate and considers the overlapping possibilities rightfully.
Remember, events must be from the same sample space for the addition rule to work. It's always important to confirm if probabilities are independent or interdependent before applying.
Probability of Either Event
Often, you may seek to determine the likelihood of at least one of two events taking place instead of both or neither.
This is referred to as the "probability of either event" occurring. In mathematical terms, it is denoted by \( P(X \cup Y) \).
We can use the addition rule to find this probability, as seen in the previous section. It lets you compute not just the probability of each separate event, but also accounts for their simultaneous occurrence.
Using our example:
  • The probability \( P(X) \) is 0.55, meaning event X is expected to occur 55% of the time.
  • The probability \( P(Y) \) is 0.35, meaning event Y is expected to occur 35% of the time.
However, when both X and Y can occur together with \( P(X \cap Y) \) being 0.20, you should adjust the total probability by subtracting this overlap.
Ultimately, the probability of either X or Y, \( P(X \cup Y) \), is 0.70, indicating a 70% chance of one or both occurring.
Intersection of Events
The intersection of events refers to the scenario where two events occur simultaneously.
In probability terms, this intersection is denoted \( P(X \cap Y) \). The intersection is a crucial part of understanding dependent events and plays a significant role when using the Addition Rule for Probabilities.
For the example at hand, \( P(X \cap Y) \) is given as 0.20, meaning that both X and Y occur together 20% of the time.
Identifying this overlap allows us to ensure that our probability calculations for either event (or both) remain accurate and are not artificially inflated due to double-counting.
In practical tasks, evaluating intersections is pivotal for designing systems and predictions where two outcomes or phenomena occur together. This understanding assists in decision-making under uncertainty and making informed predictions.

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Most popular questions from this chapter

A new sports car model has defective brakes 15 percent of the time and a defective steering mechanism 5 percent of the time. Let's assume (and hope) that these problems occur independently. If one or the other of these problems is present, the car is called a "lemon." If both of these problems are present, the car is a "hazard." Your instructor purchased one of these cars yesterday. What is the probability it is: a. A lemon? b. A hazard?

In each of the following cases, indicate whether classical, empirical, or subjective probability is used. a. A baseball player gets a hit in 30 out of 100 times at bat. The probability is .3 that he gets a hit in his next at bat. b. A seven-member committee of students is formed to study environmental issues. What is the likelihood that any one of the seven is chosen as the spokesperson? c. You purchase one of 5 million tickets sold for Lotto Canada. What is the likelihood you win the \(\$ 1\) million jackpot? d. The probability of an earthquake in northern California in the next 10 years is . 80 .

The chair of the board of directors says, "There is a 50 percent chance this company will earn a profit, a 30 percent chance it will break even, and a 20 percent chance it will lose money next quarter." a. Use an addition rule to find the probability the company will not lose money next quarter. b. Use the complement rule to find the probability it will not lose money next quarter.

The events \(A\) and \(B\) are mutually exclusive. Suppose \(P(A)=.30\) and \(P(B)=.20 .\) What is the probability of either \(A\) or \(B\) occurring? What is the probability that neither \(A\) nor \(B\) will happen?

The first card selected from a standard 52 -card deck is a king. a. If it is returned to the deck, what is the probability that a king will be drawn on the second selection? b. If the king is not replaced, what is the probability that a king will be drawn on the second selection? c. What is the probability that a king will be selected on the first draw from the deck and another king on the second draw (assuming that the first king was not replaced)?

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