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As a condition of employment, Fashion Industries applicants must pass a drug test. Of the last 220 applicants 14 failed the test. Develop a 99 percent confidence interval for the proportion of applicants that fail the test. Would it be reasonable to conclude that more than 10 percent of the applicants are now failing the test? In addition to the testing of applicants, Fashion Industries randomly tests its employees throughout the year. Last year in the 400 random tests conducted, 14 employees failed the test. Would it be reasonable to conclude that less than 5 percent of the employees are not able to pass the random drug test?

Short Answer

Expert verified
For applicants, it is not clear over 10% fail, and for employees, it is not clear under 5% fail.

Step by step solution

01

Identify the Proportion of Applicants That Failed the Test

First, calculate the proportion of applicants who failed the test out of the total number of applicants:\[ p = \frac{14}{220} \approx 0.0636 \]
02

Compute the Standard Error for the Proportion

Calculate the standard error (SE) for the sample proportion using the formula:\[ SE = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.0636 \times (1 - 0.0636)}{220}} \approx 0.0165 \]
03

Determine the Z-value for 99% Confidence Level

For a 99% confidence level, the Z-value (critical value) is approximately 2.576.
04

Calculate the Confidence Interval

Now, calculate the confidence interval for the proportion:\[ CI = p \pm Z \times SE = 0.0636 \pm 2.576 \times 0.0165 \]This results in:\[ CI \approx (0.0210, 0.1062) \]
05

Interpret if More Than 10% Failed

Since the upper bound of the 99% confidence interval for applicants is 0.1062, close to 10%, but not above, it is not reasonable to conclude that more than 10% of applicants fail.
06

Identify the Proportion of Employees That Failed the Test

Compute the proportion of employees who failed the random tests:\[ p_{employees} = \frac{14}{400} = 0.035 \]
07

Compute the Standard Error for the Employees' Proportion

Calculate the standard error for the employees' sample proportion:\[ SE_{employees} = \sqrt{\frac{0.035 \times (1 - 0.035)}{400}} \approx 0.0092 \]
08

Calculate the Confidence Interval for Employees

Use the same Z-value for 99% confidence to calculate the confidence interval for employees:\[ CI_{employees} = 0.035 \pm 2.576 \times 0.0092 \]This gives:\[ CI \approx (0.0112, 0.0588) \]
09

Interpret if Less Than 5% Failed

Since 0.05 falls within the confidence interval for employees, it is not reasonable to conclude that less than 5% of the employees fail the random drug tests.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportion
When we talk about a proportion in statistics, we refer to a fraction or percentage that represents part of a whole. In the context of the exercise with drug tests at Fashion Industries, we are calculating the proportion of applicants or employees who have failed the test. It is basically the ratio of the number of failures to the total number tested.

Here's how you find it:
  • Identify the number of individuals who failed the test. For applicants, it is 14; for employees, it is also 14.
  • Find the total number of individuals tested. For applicants, this is 220, and for employees, it is 400.
  • Use the formula for the proportion, which is: \[ p = \frac{\text{Number of Failures}}{\text{Total Number Tested}} \]
  • For applicants, the proportion is: \[ p = \frac{14}{220} \approx 0.0636 \]
  • For employees, the proportion is: \[ p = \frac{14}{400} = 0.035 \]
This shows how proportions relate parts of a group to the whole group, giving a clear idea about the prevalence of a characteristic, like failing a test, within a population.
Standard Error
The concept of Standard Error (SE) is crucial in statistics, particularly when you're working with proportions. The standard error helps you understand the variability or "spread" of your sample proportion over repeated sampling. It depicts how much your sample proportion is expected to fluctuate from the true population proportion due to chance.

To calculate the standard error of a proportion, there's a specific formula you can use:
  • Start with the proportion, \( p \), that you calculated earlier.
  • Consider \( n \), the total number of observations in your sample.
  • Apply the formula:\[ SE = \sqrt{\frac{p(1-p)}{n}} \]
For instance, for the applicants at Fashion Industries:
  • Proportion \( p = 0.0636 \)
  • The total number of applicants \( n = 220 \)
  • The standard error is:\[ SE = \sqrt{\frac{0.0636 \times (1 - 0.0636)}{220}} \approx 0.0165 \]
Similarly, for employees:
  • Proportion \( p = 0.035 \)
  • The total number of employees \( n = 400 \)
  • The standard error is:\[ SE = \sqrt{\frac{0.035 \times (1 - 0.035)}{400}} \approx 0.0092 \]
Essentially, the standard error provides insight into how different the proportion could be when considering other random samples.
Z-value
The Z-value or Z-score is a statistical measure that signifies the number of standard deviations a data point is from the mean. When dealing with confidence intervals, the Z-value helps determine the "spread" or range around a sample proportion, allowing for a degree of confidence in our estimates.

For the example at Fashion Industries, the 99% confidence level was used, which corresponds to a Z-value of roughly 2.576. This is because the Z-value for a 99% confidence interval is derived from statistical tables, showing that we have a 1% chance of error. This value means you're 99% confident that the true proportion falls within the calculated range of values.

Here is how it impacts the confidence interval:
  • The larger the Z-value, the wider your confidence interval for a given standard error, indicating a higher level of confidence that the true proportion falls within this range.
  • In our calculation, the Z-value is multiplied by the standard error to give the margin of error around the proportion.
  • This margin is then added and subtracted from the proportion to create the confidence interval.
In summary, the Z-value essentially stretches or compresses the range of your confidence interval, depending on the level of confidence you are aiming for.
Hypothesis Testing
Hypothesis testing is a statistical method that enables us to use sample data to assess a hypothesis about a population. In the Fashion Industries example, we have hypotheses about the true proportions of applicants and employees who fail drug tests.

The process involves:
  • Setting a null hypothesis (H_{0}) and an alternative hypothesis (H_{a}).
  • The null hypothesis typically states that the observed effect is due to random chance. For applicants, H_{0}: At most, 10% fail (\( p \leq 0.10 \)). For employees, H_{0}: At least, 5% fail (\( p \geq 0.05 \)).
  • Calculate a statistic (such as a Z-value) to see how well the sample data fits the null hypothesis.
  • Determine a confidence interval to see if it supports rejecting the null hypothesis.
  • If the value concerning your hypothesis lies outside the interval, you reject H_{0}; otherwise, you fail to reject it.
In this case:
  • For applicants, since 10% is within the 99% confidence interval, we don't have grounds to reject H_{0}. Hence, it's not reasonable to say over 10% fail.
  • For employees, since 5% is within the interval, we again fail to reject H_{0}, meaning we can't conclusively say less than 5% fail.
This structured decision-making process is crucial in statistical science, helping draw conclusions about populations based on sample data.

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