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There are five sales associates at Mid-Motors Ford. The five representatives and the number of cars they sold last week are: $$ \begin{array}{|lr|} \hline {\text { Sales }} & \\ \text { Representative } & \text { Cars Sold } \\ \hline \text { Peter Hankish } & 8 \\ \text { Connie Stallter } & 6 \\ \text { Juan Lopez } & 4 \\ \text { Ted Barnes } & 10 \\ \text { Peggy Chu } & 6 \\ \hline \end{array} $$ a. How many different samples of size 2 are possible? b. List all possible samples of size 2 , and compute the mean of each sample. c. Compare the mean of the sampling distribution of sample means with that of the population. d. On a chart similar to Chart \(8-1\), compare the dispersion in sample means with that of the population.

Short Answer

Expert verified
There are 10 samples of size 2. Each has a mean; the sample mean matches the population mean of 6.8.

Step by step solution

01

Calculate Number of Samples

To find how many different samples of size 2 are possible, we use the combination formula. The formula for combinations is given by \( C(n, r) = \frac{n!}{r!(n-r)!} \), where \( n \) is the total number of items to choose from, and \( r \) is the number of items to choose at a time. Here, \( n = 5 \) and \( r = 2 \). Thus, \( C(5, 2) = \frac{5 \times 4}{2 \times 1} = 10 \). Therefore, there are 10 different possible samples.
02

List All Possible Samples

The possible samples of size 2 from the five representatives are: (Peter, Connie), (Peter, Juan), (Peter, Ted), (Peter, Peggy), (Connie, Juan), (Connie, Ted), (Connie, Peggy), (Juan, Ted), (Juan, Peggy), and (Ted, Peggy). Each sample should be considered without regard to order as we are choosing combinations.
03

Compute the Sample Means

For each sample from Step 2, calculate the mean:1. Peter and Connie: \( \frac{8 + 6}{2} = 7 \)2. Peter and Juan: \( \frac{8 + 4}{2} = 6 \)3. Peter and Ted: \( \frac{8 + 10}{2} = 9 \)4. Peter and Peggy: \( \frac{8 + 6}{2} = 7 \)5. Connie and Juan: \( \frac{6 + 4}{2} = 5 \)6. Connie and Ted: \( \frac{6 + 10}{2} = 8 \)7. Connie and Peggy: \( \frac{6 + 6}{2} = 6 \)8. Juan and Ted: \( \frac{4 + 10}{2} = 7 \)9. Juan and Peggy: \( \frac{4 + 6}{2} = 5 \)10. Ted and Peggy: \( \frac{10 + 6}{2} = 8 \).
04

Calculate Population Mean

The population mean is calculated by averaging the number of cars sold by all representatives: \( \frac{8 + 6 + 4 + 10 + 6}{5} = 6.8 \).
05

Compare Means

The mean of all sample means from Step 3 is \( \frac{7 + 6 + 9 + 7 + 5 + 8 + 6 + 7 + 5 + 8}{10} = 6.8 \). The mean of the population (Step 4) is also 6.8. Thus, the mean of the sampling distribution matches the population mean.
06

Analyze Dispersion

The dispersion of sample means can be visually analyzed using a frequency distribution chart (similar to Chart 8-1). While the sample means are discrete and centered around the population mean, they tend to have less dispersion. The variance and standard deviation of the sampling distribution is usually smaller than that of the population, indicating reduced variability.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean is the average of a set of data points selected from a larger population.
It helps us get an idea, or an estimate, of what the population mean might be, using a smaller subset of data.
Calculating the sample mean is straightforward: you add up all numbers in your sample and then divide by the sample size.
For example, if two sales associates, Peter and Connie, sold 8 and 6 cars respectively, the sample mean is calculated as follows:
\( \text{Sample Mean} = \frac{8 + 6}{2} = 7 \)
This single figure summarizes the typical sales performance for the pair you’ve chosen.
Even though it only includes Peter and Connie, it indicates how they compare with the others in the larger group they belong to.
This calculation leads us to understanding larger patterns without necessarily looking at every individual case.
Population Mean
The population mean is the average of all data points in a set.
This is important because it gives insight into the general behavior or outcome for the entire group you are examining.
Unlike the sample mean which uses a subset, the population mean includes every single observation.
For the Mid-Motors Ford sales associates, the population mean involves all five representatives.
By adding the total cars sold and dividing by the number of sales representatives, the population mean can be understood as:
\( \text{Population Mean} = \frac{8 + 6 + 4 + 10 + 6}{5} = 6.8 \)
Having this value gives a more rounded and reliable summary of what was sold overall.
In essence, it tells us: "On average, each associate sold this many cars." This provides a benchmark, helping to identify deviations when individual or sample means differ from the population mean.
Combination Formula
To find out how many different samples of a certain size you can draw from a population, the combination formula is invaluable.
This formula calculates how many groups you can form given a set population.
It is expressed as:
\[ C(n, r) = \frac{n!}{r!(n-r)!} \]
where \( n \) is the total number of items and \( r \) is the number of selections per group.
For example, with five sales associates, we want to know how many unique pairs can be formed:
\( C(5, 2) = \frac{5 \times 4}{2 \times 1} = 10 \)
This formula shows us there are 10 different ways to select 2 representatives out of the 5.
Understanding this concept is essential when sampling, as it ensures no combination is overlooked and that every possible pairing is considered.
Dispersion Analysis
Dispersion analysis involves measuring the spread or variability among data points in a data set.
The key tools for this are variance and standard deviation.
They measure how much the data points differ from the mean (average) value.
For the sampling distribution, the means of the sample themselves are analyzed for spread.
Typically, sample means will show less dispersion than individual data points from the full population.
This is because each sample mean is an average of observations, softening the effect of outliers and extreme values.
For this exercise, the sample means ranged from 5 to 9.
When represented visually, their dispersion is narrower than the individual sales, indicating more reliability in understanding "typical" behaviors.
Less dispersion in sample means suggests more certainty and stability when generalizing results from small samples to the bigger picture.

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Most popular questions from this chapter

Suppose your statistics instructor gave six examinations during the semester. You received the following grades (percent correct): \(79,64,84,82,92,\) and 77 . Instead of averaging the six scores, the instructor indicated he would randomly select two grades and report that grade to the student records office. a. How many different samples of two test grades are possible? b. List all possible samples of size two and compute the mean of each. c. Compute the mean of the sample means and compare it to the population mean. d. If you were a student, would you like this arrangement? Would the result be different from dropping the lowest score? Write a brief report.

The mean rent for a one-bedroom apartment in Southern California is \(\$ 2,200\) per month. The distribution of the monthly costs does not follow the normal distribution. In fact, it is positively skewed. What is the probability of selecting a sample of 50 one-bedroom apartments and finding the mean to be at least \(\$ 1,950\) per month? The standard deviation of the sample is \(\$ 250 .\)

According to an IRS study, it takes an average of 330 minutes for taxpayers to prepare, copy, and electronically file a 1040 tax form. A consumer watchdog agency selects a random sample of 40 taxpayers and finds the standard deviation of the time to prepare, copy, and electronically file form 1040 is 80 minutes. a. What assumption or assumptions do you need to make about the shape of the population? b. What is the standard error of the mean in this example? c. What is the likelihood the sample mean is greater than 320 minutes? d. What is the likelihood the sample mean is between 320 and 350 minutes? e. What is the likelihood the sample mean is greater than 350 minutes?

At the downtown office of First National Bank there are five tellers. Last week the tellers made the following number of errors each: \(2,3,5,3,\) and \(5 .\) a. How many different samples of 2 tellers are possible? b. List all possible samples of size 2 and compute the mean of each. c. Compute the mean of the sample means and compare it to the population mean.

The Crossett Trucking Company claims that the mean weight of their delivery trucks when they are fully loaded is 6,000 pounds and the standard deviation is 150 pounds. Assume that the population follows the normal distribution. Forty trucks are randomly selected and weiqhed. Within what limits will 95 percent of the sample means occur?

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