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The Kamp family has twins, Rob and Rachel. Both Rob and Rachel graduated from college 2 years ago, and each is now earning \(\$ 50,000\) per year. Rachel works in the retail industry, where the mean salary for executives with less than 5 years' experience is \(\$ 35,000\) with a standard deviation of \(\$ 8,000 .\) Rob is an engineer. The mean salary for engineers with less than 5 years' experience is \(\$ 60,000\) with a standard deviation of \(\$ 5,000\). Compute the \(z\) values for both Rob and Rachel and comment on your findings.

Short Answer

Expert verified
Rachel earns more than the average in her field; Rob earns less than the average in his.

Step by step solution

01

Understand Z-score Formula

The Z-score formula is used to determine how many standard deviations a data point is from the mean. The formula is: \[ z = \frac{X - \mu}{\sigma} \] where \( X \) is the individual score, \( \mu \) is the mean, and \( \sigma \) is the standard deviation.
02

Calculate Rachel's Z-score

Rachel's salary is \\(50,000. The mean salary in her field is \\)35,000 with a standard deviation of \$8,000. Plug these values into the Z-score formula:\[ z = \frac{50,000 - 35,000}{8,000} = \frac{15,000}{8,000} = 1.875 \]Thus, Rachel's Z-score is 1.875.
03

Calculate Rob's Z-score

Rob's salary is \\(50,000. The mean salary in engineering is \\)60,000 with a standard deviation of \$5,000. Use the Z-score formula:\[ z = \frac{50,000 - 60,000}{5,000} = \frac{-10,000}{5,000} = -2 \]Hence, Rob's Z-score is -2.
04

Interpret the Z-scores

Rachel's Z-score of 1.875 indicates her salary is 1.875 standard deviations above the mean salary in her field, suggesting she earns more than the average executive. Rob's Z-score of -2 indicates his salary is 2 standard deviations below the mean salary for engineers, suggesting he earns less than the average engineer.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
Standard deviation is an important concept in statistics. It measures the amount of variation or dispersion in a set of values. It tells us how spread out numbers are around the mean. For example, in a dataset, if the numbers are very close to the average, the standard deviation will be small. On the other hand, if the numbers are spread out over a wide range, the standard deviation will be larger.

Standard deviation is a useful tool when comparing two different sets of data. It helps us understand how much individual data points differ from the average. In the context of salaries, a high standard deviation means there is a wide variation in salaries among employees. Meanwhile, a low standard deviation means salaries are similar to one another.
In the exercise, the standard deviation helps determine if Rachel and Rob's earnings are typical in their fields. By comparing their salaries to the standard deviation, we can see how exceptional or ordinary their pay is.
Mean Salary
The mean salary is the average salary within a particular group or industry. To find the mean, you sum up all the salaries and divide by the number of employees. This measure provides a central value that represents the entire group. But, it does not show how salaries are distributed around this point.

In our example, the mean salary for retail industry executives with less than 5 years of experience is $35,000. This means that when you look at salaries in this sector, the average amount executives earn is that number. For engineers in the same experience bracket, the mean salary is $60,000. These averages help us understand how competitive different fields are in terms of salary potential.
Having a high mean salary is generally attractive. However, one should also consider the range of salaries (using standard deviation) to understand actual earning possibilities. This is especially helpful when comparing job offers across industries.
Engineering Salaries
Engineering salaries are known for being quite competitive. For engineers with less than 5 years of experience, the mean salary described in our exercise is $60,000. This suggests that engineering is a lucrative field even for those who are relatively new in their careers.

Engineers are often highly sought after due to their specialized skills and expertise. However, as shown by the standard deviation of $5,000 in this field, salaries can vary. In Rob's case, his salary is significantly below the mean, indicating that despite the high earning potential, there are exceptions. It may suggest a deeper look into factors such as his role, industry segment, or employment terms.
Understanding engineering salaries in depth requires looking not only at the average pay but also at the distribution of salaries. This gives insights into how much variation exists and whether certain roles consistently pay more or less.
Retail Industry Salaries
Retail industry salaries can vary widely. For executives with less than 5 years of experience, the mean salary is $35,000 according to the exercise. This reflects the average pay scale within the industry for new executives, but it doesn't capture the full picture.

The retail industry is characterized by high earning variability, as suggested by a $8,000 standard deviation observed here. This means that while some executives may earn much lower than the mean, others like Rachel can earn significantly more. Rachel's salary is above average, which might be due to her position, skills, or specific company norms.
In comparing retail salaries to other industries, new professionals should weigh average earnings alongside other personal and career goals. Retail can be rewarding, offering career growth and opportunities that may also affect earning potential over time. Understanding salary structure, including mean and deviation, provides a clearer picture for making informed career decisions.

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Most popular questions from this chapter

A recent report in USA Today indicated a typical family of four spends \(\$ 490\) per month on food. Assume the distribution of food expenditures for a family of four follows the normal distribution, with a mean of \(\$ 490\) and a standard deviation of \(\$ 90 .\) a. What percent of the families spend more than \(\$ 30\) but less than \(\$ 490\) per month on food? b. What percent of the families spend less than \(\$ 430\) per month on food? c. What percent spend between \(\$ 430\) and \(\$ 600\) per month on food? d. What percent spend between \(\$ 500\) and \(\$ 600\) per month on food?

A normal population has a mean of 20.0 and a standard deviation of \(4.0 .\) a. Compute the \(z\) value associated with 25.0 . b. What proportion of the population is between 20.0 and \(25.0 ?\) c. What proportion of the population is less than \(18.0 ?\)

The April rainfall in Flagstaff, Arizona, follows a uniform distribution between 0.5 and 3.00 inches. a. What are the values for \(a\) and \(b\) ? b. What is the mean amount of rainfall for the month? What is the standard deviation? c. What is the probability of less than an inch of rain for the month? d. What is the probability of "exactly" 1.00 inch of rain? e. What is the probability of more than 1.50 inches of rain for the month?

Shaver Manufacturing, Inc. offers dental insurance to its employees. A recent study by the Human Resource Director shows the annual cost per employee per year followed the normal distribution, with a mean of \(\$ 1,280\) and a standard deviation of \(\$ 420\) per year. a. What fraction of the employees cost more than \(\$ 1,500\) per year for dental expenses? b. What fraction of the employees cost between \(\$ 1,500\) and \(\$ 2,000\) per year? c. Estimate the percent that did not have any dental expense. d. What was the cost for the 10 percent of employees who incurred the highest dental expense?

America West Airlines reports the flight time from Los Angeles International Airport to Las Vegas is 1 hour and 5 minutes, or 65 minutes. Suppose the actual flying time is uniformly distributed between 60 and 70 minutes. a. Show a graph of the continuous probability distribution. b. What is the mean flight time? What is the variance of the flight times? c. What is the probability the flight time is less than 68 minutes? d. What is the probability the flight takes more than 64 minutes?

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