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In a binomial situation \(n=4\) and \(\pi=.25 .\) Determine the probabilities of the following events using the binomial formula. a. \(x=2\) b. \(x=3\)

Short Answer

Expert verified
a: P(X=2) = 0.21, b: P(X=3) = 0.05.

Step by step solution

01

Introduction to Binomial Formula

The binomial formula is used to find the probability of obtaining exactly \(k\) successes in \(n\) independent Bernoulli trials, with a probability of success \(\pi\) on each trial. The formula is given by: \( P(X = k) = \binom{n}{k} \pi^k (1 - \pi)^{n-k} \), where \(\binom{n}{k}\) is the binomial coefficient.
02

Calculate Binomial Coefficient for x=2

For \(x = 2\), calculate the binomial coefficient: \( \binom{n}{2} = \binom{4}{2} = \frac{4 \times 3}{2 \times 1} = 6 \).
03

Apply Binomial Formula for x=2

Using the binomial formula, substitute the values: \( P(X = 2) = \binom{4}{2} \times (0.25)^2 \times (0.75)^{4-2} = 6 \times 0.0625 \times 0.5625 = 0.2109375 \).
04

Calculate Binomial Coefficient for x=3

For \(x = 3\), calculate the binomial coefficient: \( \binom{n}{3} = \binom{4}{3} = \frac{4 \times 3 \times 2}{3 \times 2 \times 1} = 4 \).
05

Apply Binomial Formula for x=3

Using the binomial formula, substitute the values: \( P(X = 3) = \binom{4}{3} \times (0.25)^3 \times (0.75)^{4-3} = 4 \times 0.015625 \times 0.75 = 0.046875 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Coefficient
The binomial coefficient is an essential part of the binomial formula, which helps us calculate the number of ways to choose a certain number of successes (or outcomes) from a fixed number of trials. It's denoted as \( \binom{n}{k} \), where \( n \) is the total number of trials, and \( k \) is the number of successful trials you are interested in. To calculate it, you use the formula:- \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \)- The factorial expression \( n! \) means the product of all natural numbers up to \( n \).In our problem, when we want the coefficient for \( x=2 \), it's expressed as \( \binom{4}{2} \), which we computed to be 6. This means there are 6 possible combinations of achieving exactly 2 successes out of 4 trials. Understanding how to calculate this coefficient is crucial when working with binomial distributions because it tells us how probabilities stack up across different potential outcomes.
Probability
Probability is the measure of how likely an event is to occur and it's a foundational concept in statistics and probability theory. For a binomial distribution, probability helps us determine the likelihood of achieving exactly a certain number of successes in a series of trials. The formula for calculating this in a binomial scenario is:- \( P(X = k) = \binom{n}{k} \pi^k (1 - \pi)^{n-k} \)- Here, \( \pi \) represents the probability of success on an individual trial.When calculating probabilities for our examples with \( x=2 \) and \( x=3 \):- For \( x=2 \), the probability is \( 0.2109375 \), meaning there's a 21.09% chance of getting exactly 2 successes.- For \( x=3 \), the probability is \( 0.046875 \), or a 4.69% chance of 3 successes.By using this formula, you can better understand the distribution of probabilities across different scenarios in your binomial trials.
Bernoulli Trials
Bernoulli trials are a series of experiments or trials involving only two possible outcomes—usually termed "success" and "failure." These trials are foundational to understanding binomial distribution because the distribution itself is built upon multiple Bernoulli trials. The key characteristics of Bernoulli trials include:- Each trial has only two outcomes.- The probability of success remains consistent across all trials.- Each trial is independent, meaning one trial's outcome doesn't affect another.In our example, where \( n = 4 \) and \( \pi = 0.25 \), we are examining 4 independent trials with a 25% chance of success on each trial. This structure allows us to apply the binomial formula effectively to find the likelihood of exactly 2 or 3 successes. Understanding Bernoulli trials is crucial for addressing problems involving binomial distributions, as it sets the stage for how outcomes and probabilities are organized and calculated across each trial.

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Most popular questions from this chapter

Three tables listed below show "random variables" and their "probabilities." However, only one of these is actually a probability distribution. a. Which is it? $$\begin{array}{|rc|}\hline {\boldsymbol{X}} & \boldsymbol{P}(\boldsymbol{x}) \\\\\hline 5 & .3 \\\10 & .3 \\\15 & .2 \\\20 & .4 \\\\\hline\end{array}$$ $$\begin{array}{|rc|}\hline {x} & P(x) \\\\\hline 5 & .1 \\\10 & .3 \\\15 & .2 \\\20 & .4 \\\\\hline\end{array}$$ $$\begin{array}{|rr|}\hline {\boldsymbol{x}} & \boldsymbol{P}(\boldsymbol{x}) \\\\\hline 5 & .5 \\\10 & .3 \\ 15 & -.2 \\\20 & .4 \\\\\hline\end{array}$$ b. Using the correct probability distribution, find the probability that \(x\) is: (1) Exactly 15 . (2) No more than 10 . (3) More than 5 . c. Compute the mean, variance, and standard deviation of this distribution.

A federal study reported that 7.5 percent of the U.S. workforce has a drug problem. A drug enforcement official for the State of Indiana wished to investigate this statement. In his sample of 20 employed workers: a. How many would you expect to have a drug problem? What is the standard deviation? b. What is the likelihood that none of the workers sampled has a drug problem? c. What is the likelihood at least one has a drug problem?

Croissant Bakery, Inc. offers special decorated cakes for birthdays, weddings, and other occasions. They also have regular cakes available in their bakery. The following table gives the total number of cakes sold per day and the corresponding probability. Compute the mean, variance, and standard deviation of the number of cakes sold per day. $$\begin{array}{|cc|}\hline \text { Number of Cakes } & \\\\\text { Sold in a Day } & \text { Probability } \\\\\hline 12 & .25 \\\13 & .40 \\\14 & .25 \\\15 & .10 \\\\\hline\end{array}$$

Which of these variables are discrete and which are continuous random variables? a. The number of new accounts established by a salesperson in a year. b. The time between customer arrivals to a bank ATM. c. The number of customers in Big Nick's barber shop. d. The amount of fuel in your car's gas tank last week. e. The number of minorities on a jury. f. The outside temperature today.

In a recent study 90 percent of the homes in the United States were found to have largescreen TVs. In a sample of nine homes, what is the probability that: a. All nine have large-screen TVs? b. Less than five have large-screen TVs? c. More than five have large-screen TVs? d. At least seven homes have large-screen TVs?

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