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The Bank of Hawaii reports that 7 percent of its credit card holders will default at some time in their life. The Hilo branch just mailed out 12 new cards today. a. How many of these new cardholders would you expect to default? What is the standard deviation? b. What is the likelihood that none of the cardholders will default? c. What is the likelihood at least one will default?

Short Answer

Expert verified
a. Expected defaults = 0.84, Standard deviation ≈ 0.7986. b. Probability none default ≈ 0.4116. c. Probability at least one defaults ≈ 0.5884.

Step by step solution

01

Understand the Distribution

We are dealing with a binomial distribution as we have a fixed number of trials (12 new cardholders), two possible outcomes (default or not default), a constant probability of defaulting (7% or 0.07), and independent trials. We will use the binomial distribution formulas to solve the problem.
02

Calculate the Expected Number of Defaults

The expected number, or mean, of defaults in a binomial distribution can be calculated using the formula \( \mu = n \cdot p \), where \( n \) is the number of trials and \( p \) is the probability of success (defaulting). Here, \( n = 12 \) and \( p = 0.07 \). So, \( \mu = 12 \cdot 0.07 = 0.84 \).
03

Find the Standard Deviation

The standard deviation for a binomial distribution is found using the formula \( \sigma = \sqrt{n \cdot p \cdot (1 - p)} \). Plugging in the values, we get \( \sigma = \sqrt{12 \cdot 0.07 \cdot 0.93} \approx 0.7986 \).
04

Calculate the Probability of None Defaulting

The probability that exactly \( k \) successes occur (here, defaults) in \( n \) trials is given by \( P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \). For no defaults (\( k = 0 \)), we use \( P(X = 0) = \binom{12}{0} (0.07)^0 (0.93)^{12} = 1 \cdot (0.93)^{12} \approx 0.4116 \).
05

Find the Probability of At Least One Default

The probability of at least one default is the complement of the probability of no defaults. Thus, \( P(X \geq 1) = 1 - P(X = 0) \) which is \( 1 - 0.4116 = 0.5884 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a fundamental concept in statistics that helps us measure the likelihood of different outcomes. In a binomial distribution, probability refers to the chance of a particular outcome happening in a set number of trials. For example, if we're interested in whether credit card holders default or not, probability lets us quantify that event's likelihood.
In this example, we're given a 7% probability (0.07) that a cardholder will default. Using probability rules, such as for calculating the likelihood there's zero defaulting, involves the binomial probability formula. Here, probability becomes our tool for predicting events under uncertainty and involves concepts like probability mass function and cumulative probability.
Expected Value
Expected value is a key concept that provides a measure of the center of a probability distribution and is synonymous with the mean of the distribution. For a binomial distribution, the expected value is calculated as the number of trials multiplied by the probability of success.
In our exercise, we're curious about how many cardholders out of 12 new applicants we'd expect to default. We use the formula: \[ E(X) = n \cdot p \]where \( n = 12 \) and \( p = 0.07 \). This gives an expected value of 0.84, indicating we expect 0.84 cardholders to default. Expected value helps us manage expectations and make forecasts in decision-making scenarios.
Standard Deviation
Standard deviation is an important measure that tells us how much individual values in a dataset vary from the expected value or mean. In a binomial distribution, it helps us understand the variability and uncertainty in the number of successful outcomes.
To find the standard deviation, we use the formula:\[ \sigma = \sqrt{n \cdot p \cdot (1-p)} \]Plugging our numbers in (\[ n = 12, p = 0.07 \], and \[ 1-p = 0.93 \]), we calculate the standard deviation to be approximately 0.7986. This illustrates our expected outcomes' variability and helps assess the consistency of data from our predictions.
Complement Rule
The complement rule is a useful probability principle that helps calculate the likelihood of an event not happening by instead determining the probability of its complement – the event happening.
For instance, if we want to know the probability that at least one of the cardholders defaults, we first find the probability of none defaulting and subtract it from 1:
\[ P(X \geq 1) = 1 - P(X = 0) \]In our case, the probability of no defaults is approximately 0.4116, so the probability that at least one defaults is 0.5884. The complement rule simplifies probability problems by offering a different approach to solve them.

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