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A recent survey reported that the average American adult eats ice cream 28 times per year. The same survey indicated 33 percent of the respondents said vanilla was their favorite flavor of ice cream. Nineteen percent said chocolate was their favorite flavor. There are 10 customers waiting for ice cream at the Highway 544 Ben and Jerry's ice cream and frozen yogurt store. a. How many would you expect to purchase vanilla ice cream? b. What is the probability exactly three will select vanilla ice cream? c. What is the probability exactly three will select chocolate ice cream? d. What is the probability at least one will select chocolate ice cream?

Short Answer

Expert verified
a. About 3; b. 0.2617; c. 0.2245; d. 0.883.

Step by step solution

01

Understand the Problem

We have a total of 10 customers, and we need to find out how many are likely to purchase vanilla or chocolate ice cream based on the survey percentages. We will use this data to calculate various probabilities.
02

Calculate Expected Vanilla Purchasers

The probability that a customer selects vanilla ice cream is 33% or 0.33. To find out how many out of 10 customers might choose vanilla, multiply the total number of customers by this probability:\[E_\text{vanilla} = 10 \times 0.33\]This gives us the expected number of customers choosing vanilla.
03

Calculate Expected Number

Perform the calculation from Step 2:\[E_\text{vanilla} = 10 \times 0.33 = 3.3\]So, approximately 3 customers are expected to purchase vanilla ice cream.
04

Calculate Probability of Exactly Three Vanilla Selections

We need to find the probability that exactly 3 out of 10 customers choose vanilla. We'll use the binomial probability formula:\[P(X = 3) = \binom{n}{x} p^x (1-p)^{n-x}\]where \(n = 10\), \(x = 3\), and \(p = 0.33\).
05

Compute Probability for Exactly Three Vanilla Selections

Plug in the values to the binomial formula:\[P(X = 3) = \binom{10}{3} (0.33)^3 (0.67)^7 \approx 0.2617\]This is the probability that exactly 3 will choose vanilla.
06

Calculate Probability of Exactly Three Chocolate Selections

For chocolate, \(p = 0.19\). Using the binomial probability formula:\[P(Y = 3) = \binom{10}{3} (0.19)^3 (0.81)^7\]Calculate this probability.
07

Compute Probability for Exactly Three Chocolate Selections

Plug in the values to the formula:\[P(Y = 3) = \binom{10}{3} (0.19)^3 (0.81)^7 \approx 0.2245\]This is the probability that exactly 3 will choose chocolate.
08

Calculate Probability of At Least One Chocolate Selection

The probability of at least one choosing chocolate is the complement of none choosing it. Calculate using:\[P(Z \geq 1) = 1 - P(Z = 0)\]where \(P(Z = 0)\) is calculated via the binomial probability formula with \(x = 0\).
09

Compute Complement for At Least One Chocolate Selection

Plug in the values for \(x = 0\) with \(p = 0.19\):\[P(Z = 0) = \binom{10}{0} (0.19)^0 (0.81)^{10} = (0.81)^{10} \approx 0.117\]Now compute:\[P(Z \geq 1) = 1 - 0.117 = 0.883\]Thus, the probability at least one chooses chocolate is 0.883.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Expected Value
To understand the concept of expected value in survey data, let's consider it as a prediction of the average outcome based on probabilities. In the case of the ice cream survey, we know that the probability of a customer selecting vanilla ice cream is 33% or 0.33. With 10 customers, we want to calculate how many would likely choose vanilla. The expected value helps us make this prediction. We calculate it by multiplying the total number of customers by the probability of them picking vanilla:\[E_\text{vanilla} = 10 \times 0.33 = 3.3\]This means that we expect approximately 3 customers to choose vanilla ice cream. The expected value provides an average when looking at large numbers of similar scenarios. It's important to note that you can't have 3.3 customers, but in statistical terms, this average helps us plan and understand likely outcomes.
Probability Theory
Probability theory is fundamental to understanding how likely specific outcomes are based on given data. It involves using known probabilities to predict the chances of various events. In our ice cream survey, we apply this to determine the probability of exactly three customers choosing vanilla ice cream using binomial probability.The binomial probability formula calculates the probability of an exact number of successes (like choosing vanilla) in a certain number of trials (like 10 customers) where each trial has two possible outcomes:\[P(X = x) = \binom{n}{x} p^x (1-p)^{n-x}\]Here,
  • \(n = 10\) (the number of customers),
  • \(x = 3\) (the exact number of customers choosing vanilla),
  • \(p = 0.33\) (the probability of choosing vanilla).
Plugging these into the formula gives:\[P(X = 3) = \binom{10}{3} (0.33)^3 (0.67)^7 \approx 0.2617\]This result shows there's about a 26.17% chance that exactly three customers will select vanilla. The same method can be adapted to calculate probabilities for any other number of customers choosing chocolate, or even none at all.
Survey Data Analysis
Survey data analysis involves interpreting results from data collection efforts to make predictions or understand patterns. In our ice cream example, this means turning survey responses into expected behaviors like flavor choice.For chocolate lovers, where 19% prefer this flavor, we use similar principles of binomial probability as we did for vanilla. Using a probability of 0.19 for chocolate, we perform calculations to find the chance that exactly three customers choose it:\[P(Y = 3) = \binom{10}{3} (0.19)^3 (0.81)^7 \approx 0.2245\]This means there’s a 22.45% chance exactly three will choose chocolate. Moreover, survey analysis often involves calculating complementary probabilities, like at least one customer choosing chocolate. Using the formula:\[P(Z \geq 1) = 1 - P(Z = 0)\]First, calculate the probability that none choose chocolate, then subtract from 1:\[P(Z = 0) = \binom{10}{0} (0.19)^0 (0.81)^{10} \approx 0.117\]So, \[P(Z \geq 1) = 1 - 0.117 = 0.883\]This gives us an 88.3% probability that at least one customer will opt for chocolate, highlighting how survey data gives insights into consumer preferences and shapes decision-making.

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