/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 The probabilities of the events ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The probabilities of the events \(A\) and \(B\) are .20 and .30 , respectively. The probability that both \(A\) and \(B\) occur is \(.15 .\) What is the probability of elther \(A\) or \(B\) occurring?

Short Answer

Expert verified
The probability of either event A or B occurring is 0.35.

Step by step solution

01

Identify Relevant Probability Formula

For two events, the probability of either event \( A \) or \( B \) occurring (the union of \( A \) and \( B \)) is given by the formula: \( P(A \cup B) = P(A) + P(B) - P(A \cap B) \). This formula accounts for the possibility that both events can occur at the same time.
02

Substitute Values into Formula

Let's substitute the given probabilities into the formula: \( P(A) = 0.20 \), \( P(B) = 0.30 \), and \( P(A \cap B) = 0.15 \). Thus, \( P(A \cup B) = 0.20 + 0.30 - 0.15 \).
03

Perform Calculations

Now, perform the arithmetic operations: \( 0.20 + 0.30 = 0.50 \) and \( 0.50 - 0.15 = 0.35 \). Therefore, \( P(A \cup B) = 0.35 \).
04

Conclusion: State the Probability

The probability of either event \( A \) or \( B \) occurring is 0.35.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Events in Probability
In probability theory, an event is any collection of outcomes from a probability trial or experiment. Simply put, it's something that can happen or not happen. For example, when you toss a coin, getting a 'head' is an event. Similarly, events can be more complex, like the arrival of a bus within the next 5 minutes.

Events are often denoted by capital letters such as \( A \), \( B \), or \( C \). Probabilities are numbers that measure the chance of these events occurring, ranging from 0 (the event will not occur) to 1 (the event will certainly occur).

When dealing with multiple events, we can explore their interactions. There are specific terms used in probability to describe such interactions, like the **union of events** and whether events are **independent or dependent**. These concepts help us compute probabilities in scenarios involving more than one event.
Union of Events
The union of two events \(A\) and \(B\) is the set of outcomes that are in either event, or both. In mathematical terms, it's expressed as \( A \cup B \).

To find the probability of the union \( P(A \cup B) \), we add the probabilities of the two events and subtract the probability that both events happen at the same time. This subtraction is necessary because adding the probabilities alone would count the overlapping outcomes twice. The formula is given by:
  • Probability of the union: \( P(A \cup B) = P(A) + P(B) - P(A \cap B) \)

In our example, since \( P(A) = 0.20 \), \( P(B) = 0.30 \), and \( P(A \cap B) = 0.15 \), we substitute these values into the formula. Performing the arithmetic gives us \( P(A \cup B) = 0.20 + 0.30 - 0.15 = 0.35 \). This result represents the probability that either event \( A \) or event \( B \) occurs.
Independent and Dependent Events
Understanding whether events are independent or dependent is crucial in probability. **Independent events** are those whose outcomes do not affect one another. For instance, flipping a coin and rolling a die are independent actions. The result of one does not change the probability of the other.

In contrast, **dependent events** have outcomes that affect each other. Imagine drawing a card from a deck, then drawing a second card without replacing the first. The probability of drawing a specific card the second time depends on what happened with the first draw.

In our exercise, knowing the probability of both \( A \) and \( B \) happening is critical. The event of both happening simultaneously, \( P(A \cap B) \), is considered in calculating their union. This aspect can indicate dependence if changes in one event influence the other. However, without additional context from the problem, we might not explicitly classify the events in the exercise as independent or dependent. Understanding these conditions aids in accurate probability computations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Ninety students will graduate from Lima Shawnee High School this spring. Of the 90 students, 50 are planning to attend college. Two students are to be picked at random to carry flags at the graduation. a. What is the probability both of the selected students plan to attend college? b. What is the probability one of the two selected students plans to attend college?

During the 1970 s the game show Let's Make a Deal had a long run on TV. In the show a contestant was given a choice of three doors, behind one of which was a prize. The other two doors contained a gag gift of some type. After the contestant selected a door, the host of the show then revealed to them one of the doors from among the two not selected. The host asked the contestant if they wished to switch doors to one of those not chosen. Should the contestant switch? Are the odds of winning increased by switching doors? Go to the following website, which is administered by the Department of Statistics at the University of South Carolina, and try your strategy: http://www.stat.sc.edu/ west/applets/ LetsMakeaDeal.html; Go to the following website and read about the odds for the game: http://www.stat.sc.edu/ west/javahtml/LetsMakeaDeal.html. Was your strategy correct?

A study by the National Park Service revealed that 50 percent of vacationers going to the Rocky Mountain region visit Yellowstone Park, 40 percent visit the Tetons, and 35 percent yisit both. a. What is the probability a vacationer will visit at least one of these attractions? b. What is the probability .35 called? c. Are the events mutually exclusive? Explain.

A juggler has a bag containing four blue balls, three green balls, two yellow balls, and one red ball. The juggler picks a ball at random. Then, without replacing it, he chooses a second ball. What is the probability the juggler first draws a yellow ball followed by a blue ball?

The board of directors of Saner Automatic Door Company consists of 12 members, 3 of whom are women. A new policy and procedures manual is to be written for the company. A committee of 3 is randomly selected from the board to do the writing. a. What is the probability that all members of the committee are men? b. What is the probability that at least 1 member of the committee is a woman?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.