/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 The events \(A\) and \(B\) are m... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The events \(A\) and \(B\) are mutually exclusive. Suppose \(P(A)=.30\) and \(P(B)=.20 .\) What is the probability of either \(A\) or \(B\) occurring? What is the probability that neither \(A\) nor \(B\) will happen?

Short Answer

Expert verified
The probability of either A or B is 0.50; the probability of neither A nor B is 0.50.

Step by step solution

01

Understand the Definition of Mutually Exclusive Events

Two events are mutually exclusive if they cannot happen at the same time. This means that the probability of both events occurring together, i.e., \( P(A \cap B) \), is zero.
02

Determine the Probability Formula for Either A or B

The formula to find the probability of either event \( A \) or \( B \) occurring for mutually exclusive events is given by: \[ P(A \cup B) = P(A) + P(B) \]
03

Apply the Probability Values for Either A or B

Given \( P(A) = 0.30 \) and \( P(B) = 0.20 \), substitute these values into the formula: \[ P(A \cup B) = 0.30 + 0.20 = 0.50 \] This gives us the probability of either \( A \) or \( B \) occurring.
04

Determine the Probability Formula for Neither A nor B

The probability of neither event \( A \) nor \( B \) happening is the complement of the probability of either occurring: \[ P(\text{neither } A \text{ nor } B) = 1 - P(A \cup B) \]
05

Apply the Complement Formula for Neither A nor B

Using the value found for \( P(A \cup B) = 0.50 \), the probability of neither \( A \) nor \( B \) is: \[ P(\text{neither } A \text{ nor } B) = 1 - 0.50 = 0.50 \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mutually Exclusive Events
When we talk about mutually exclusive events, we're referring to events that cannot happen at the same time. Imagine tossing a single coin: you can either get a heads or a tails, but not both. In other words, mutually exclusive events are those where if one happens, the other cannot.
For these types of events, the probability of both events occurring together is zero. This is mathematically expressed as \( P(A \cap B) = 0 \). In our example, since events \(A\) and \(B\) are mutually exclusive, we know immediately that \( P(A \cap B) = 0 \).
Understanding the concept of mutually exclusive events helps us use and trust certain probability rules when calculating likelihoods of outcomes.
Complement Rule
The Complement Rule is a handy concept in probability that helps us figure out the chance of something not happening, based on what we know about what happening. It's like flipping our thinking; if we know the probability of an event happening, the probability of it not happening can be easily calculated.
Mathematically, the complement rule is stated as: \( P( ext{not } A) = 1 - P(A) \). Using this rule is often about finding what's missing to make the total probability 1, since the total probability of all possible outcomes must sum to 1.
In our exercise, once we found the probability of either \(A\) or \(B\) occurring, we used the complement rule to find the probability of neither \(A\) nor \(B\) happening: \( P( ext{neither } A ext{ nor } B) = 1 - P(A \cup B) \). This simple subtraction gives us the probability of the complement of the union of events \(A\) and \(B\).
Probability Formulas
Calculating probabilities requires understanding and appropriately applying specific formulas. When dealing with mutually exclusive events, we can add their probabilities to find the probability of either event occurring.
For mutually exclusive events \(A\) and \(B\), the probability of either \(A\) or \(B\) is given by:
  • \( P(A \cup B) = P(A) + P(B) \)
In our scenario with \(P(A) = 0.30\) and \(P(B) = 0.20\), we simply add these probabilities: \(0.30 + 0.20 = 0.50\).
There's also a formula to calculate the probability of neither event happening—using the complement rule:
  • \( P( ext{neither } A ext{ nor } B) = 1 - P(A \cup B) \)
This formula works by understanding that the overall probability of an event plus its complement is always 1.
These formulas are easy tools that simplify calculating chances in various scenarios and are foundational in countless practical applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The first card selected from a standard 52 -card deck was a king. a. If it is returned to the deck, what is the probability that a king will be drawn on the second selection? b. If the king is not replaced, what is the probability that a king will be drawn on the second selection? c. What is the probability that a king will be selected on the first draw from the deck and another king on the second draw (assuming that the first king was not replaced)?

Solve the following: a. \(20 ! / 17 !\) b. \({ }_{g} P_{3}\) c. \({ }_{7} C_{2}\)

Irwin Publishing, Inc., as part of its summer sales meeting, has arranged a golf outing at the Quail Creek Golf and Fish Club. Twenty people have signed up to play in the outing. The PGA Professional at Quail Creek is responsible for arranging the foursomes (four golfers playing together). How many different foursomes are possible?

Albert Pujols of the St. Louis Cardinals had the highest batting average in the 2003 Major League Baseball season. His average was . \(359 .\) So assume the probability of getting a hit is .359 for each time he batted. In a particular game assume he batted three times. a. This is an example of what type of probability? b. What is the probability of getting three hits in a particular game? c. What is the probability of not getting any hits in a game? d. What is the probability of getting at least one hit?

The following diagram represents a system of two components, \(A\) and \(B\), which are in series. (Being in series means that for the system to operate, both components \(A\) and \(B\) must work.) Assume the two components are independent. What is the probability the system works under these conditions? The probability \(A\) works is .90 and the probability \(B\) functions is also .90 .

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.